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DIMENSIONAL ANALYSIS DIMENSIONAL ANALYSIS A.K.A FACTOR-LABELING USING UNITS TO SOLVE A MATH PROBLEM.

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Presentation on theme: "DIMENSIONAL ANALYSIS DIMENSIONAL ANALYSIS A.K.A FACTOR-LABELING USING UNITS TO SOLVE A MATH PROBLEM."— Presentation transcript:

1 DIMENSIONAL ANALYSIS DIMENSIONAL ANALYSIS A.K.A FACTOR-LABELING USING UNITS TO SOLVE A MATH PROBLEM

2 TYPES USE A FORMULA OR CONVERSION FACTORS – SHOW A RELATIONSHIP BETWEEN DIFFERENT UNITS OF MEASUREMENT – EX: 12 in = 1 ft 1 in = 2.54 cm 100 cm = 1 m 1 kg = 2.2 lbs

3 HOW TO USE IDENTIFY THE GIVEN AND THE UNKNOWN. WRITE DOWN THE APPROPRIATE CONVERSION FACTOR(S) TO USE. (OR PLUG NUMBERS INTO THE FORMULA)

4 TO SOLVE (WHEN USING A FORMULA) IDENTIFY THE GIVENS AND UNKNOWN. SUBSTITUTE THE GIVENS INTO THE FORMULA REARRANGE THE FORMULA TO SOLVE FOR THE UNKNOWN

5 EXAMPLE THE MASS OF AN OBJECT IS 5.87g AND THE VOLUME IS 7.98mL. WHAT IS THE DENSITY OF THE OBJECT?

6 IDENTIFY GIVEN & UNKNOWN D = ? m = 5.87 g D = m/v v = 7.98 mL SUBSTITUTE THE NUMBERS D = 5.87g = 0.736 g/mL 7.98mL

7 TO SOLVE (WHEN USING CONVERSION FACTORS) PUT YOUR GIVEN OVER 1. (THIS TURNS IT INTO A FRACTION) MULTIPLY THE GIVEN BY THE APPROPRIATE CONVERSION FACTOR(S). THE UNITS TELLYOU WHICH CONVERSION FACTOR TO USE & HOW TO SET IT UP.

8 CANCEL UNITS. IF THE UNITS CANCEL THEN YOU CAN DO THE MATH. SIG. FIGS. COME FROM THE GIVEN.

9 EXAMPLE A WOMAN NEEDS 76.0 m OF FABRIC. HOW MANY YARDS IS THIS? –GIVEN: 76.0 m –UNKNOWN: ? YARDS –CONVERSION FACTOR(S) –CONVERSION FACTOR(S): 0.3048 m = 1 ft 3 ft = 1 yd

10 76.0 m x 1 ft x 1 yd = 1 0.3048 m 3 ft CALC. ANS: 83.11461067 yds ROUNDED ANS: 83.1 yds UNKNOWN UNIT

11 PRACTICE PROBLEMS COPY AND WORK 1) The density of an object is 7.71 g/mL. Its mass is 51.12g. What volume does the object occupy?

12 2) A box has a mass of 4.5 kg and a volume of 6.4L. Calculate the density in g/cm 3. Use dimensional analysis to convert your metric units.

13 ANSWERS 1) D = 7.71g/mL m = 51.12g v = ? D = m v solve for this

14 WORK: v = m D v = 51.12g 6.63 mL 7.71g/mL =

15 PROBLEM 2 REQUIRES 3 STEPS: –1 ST CONVERT kg TO g –2 ND CONVERT L TO cm 3 –USE DENSITY EQUATION

16 2) GIVEN: 4.5kg UNK: g UNK: g C.F.: 1kg = 1000g C.F.: 1kg = 1000g 4.5kg X 1000g = 4500g 1 1kg

17 GIVEN: 6.4L GIVEN: 6.4L UNK: mL UNK: mL C.F.:1L = 1000 mL C.F.:1L = 1000 mL 1mL = 1cm 3 1mL = 1cm 3 6.4L X 1000mL X 1 cm 3 = 1 1L 1mL 6400cm 3

18 WORK: D = m/v D= 4500g = 6400cm 3 0.70g/cm 3


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