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1.6 Absolute Value Inequalities and Equations Honors Algebra II.

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Presentation on theme: "1.6 Absolute Value Inequalities and Equations Honors Algebra II."— Presentation transcript:

1 1.6 Absolute Value Inequalities and Equations Honors Algebra II

2 Absolute Value Distance from zero on the number line. Distance from zero on the number line.

3 Absolute Value Distance from zero on the number line. Distance from zero on the number line. Always positive result for absolute value. Always positive result for absolute value.

4 Absolute Value  Distance from zero on the number line.  Always positive result for absolute value.  Works as a grouping in order of operations, but it is NOT parentheses => don’t distribute!

5 Absolute Value |x| = x if x ≥ 0 |x| = -x if x < 0

6 Steps to Solve Absolute Value Equations  Isolate absolute value expression  Split into two equations  Solve both  Check both

7 Absolute Value Equations Solve: |2x – 1| = 5

8 Absolute Value Equations CHECK: |2x – 1| = 5 x = 3x = -2

9 Absolute Value Equations Solve:3 |4w – 1| - 5 = 10

10 Absolute Value Equations Check:3 |4w – 1| - 5 = 10

11 Absolute Value Equations Solve:|2x + 5| = 3x + 4

12 Absolute Value Equations Check: |2x + 5| = 3x + 4

13 Extraneous Solutions  Solutions that, though solved for correctly, do not work in the original equation.  YOU MUST CHECK YOUR ANSWERS! Absolute Value Equations

14 Absolute Value Inequalities

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16 Steps to Solve Absolute Value Inequalities  Isolate absolute value expression  Split into two inequalities  Solve both  Check

17 Solve:|3x + 6| ≥ 12 Absolute Value Inequalities

18 Solve:3 |2x + 6| - 9 < 15 Absolute Value Inequalities

19 Summary Isolate Absolute Value Isolate Absolute Value If =, OR problem |x| = 5 If =, OR problem |x| = 5 x = 5 or x = -5 If >, ≥, OR problem |x| > 5 If >, ≥, OR problem |x| > 5 x 5 If <, ≤, AND problem|x| < 5 If <, ≤, AND problem|x| < 5 -5 < x < 5 -5 < x < 5 x > -5 and x -5 and x < 5

20 Tolerance: one half the difference of the maximum and minimum acceptable values. Manufacturing Application

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23 More Examples: 1.) 2 |3x – 1| + 5 = 33 2.) |5z + 3| - 7 < 34 3.) -3 |2x – 3| + 1 ≤ -20


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