1. 9.5
The Binomial Theorem
Let’s look at the expansion of (x + y)n
(x + y)0 = 1
(x + y)1 = x + y
(x + y)2 = x2 +2xy + y2
(x + y)3 = x3 + 3x2y + 3xy2 + y3
(x + y)4 = x4 + 4x3y + 6x2y2 + 4xy3 + y4

2. Expanding a binomial using Pascal’s Triangle1
Write the
next row.

3. Expand (x + 3)4
From Pascal’s triangle write down
the 4th row.
These numbers are the same numbers that are the
coefficients of the binomial expansion.
The expansion of (a + b)4 is:
1a4b0 + 4a3b1 + 6a2b2 + 4a1b3 + 1a0b4
Notice that the exponents always add up to 4 with
the a’s going in descending order and the b’s in
ascending order.
Now substitute x in for a and 3 in for b.

4. 1a4b0 + 4a3b1 + 6a2b2 + 4a1b3 + 1a0b4
x4 + 4x3(3)1 + 6x2(3)2 + 4x(3)3 + 34
This simplifies to
x4 + 12x3 + 54x x + 81
Expand (x – 2y)4
This time substitute x in for a
and -2y for b. Use ( ).
x4 + 4x3(-2y)1 + 6x2(-2y)2 + 4x(-2y)3 + (-2y)4
The final answer is:
x4 – 8x3y + 24x2y2 – 32xy3 + 16y4

5. The Binomial Theorem
In the expansion of (x + y)n
(x + y)n = xn + nxn-1y + … + nCmxn-mym + … +nxyn-1 + yn
the coefficient of xn-mym is given by

6. Find the following binomial coefficients.28
10C3 =
120
7C3 = 35
7C4 = 35

7. = 55,427,328 a7b5 Find the 6th term in the expansion of (3a + 2b)12
Using the Binomial Theorem, let x = 3a and y = 2b
and note that in the 6th term, the exponent of y is
m = 5 and the exponent of x is n – m = 12 – 5 = 7.
Consequently, the 6th term of the expansion is:
= 55,427,328 a7b5