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Published byScot Bond Modified over 8 years ago
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Chapter 7
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SIMPLIFY: 20 12 3
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20 = 4 5 = 2 5 12 3 12 3 3 3 3 4 3==
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MULTIPLY: ( 2 5 ) 2
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(2 5 ) 2 = 4 25 = 4 5 = 20.
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COMPLETE: ( ___ ) 2 + ( ___ ) 2 = ( ___ ) 2 leg 1 leg 2 hyp
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(leg 1 ) 2 + (leg 2 ) 2 = (hyp) 2 Pythagorean Theorem
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Complete to form RIGHT triangles: 3, 4, ____5, 12, ____ 6, 8, ____8, 15, ____
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3, 4, 55, 12, 13 6, 8, 108, 15, 17
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Given segment lengths a, b, c longest Rightc 2 a 2 + b 2 Obtusec 2 a 2 + b 2 Acutec 2 a 2 + b 2
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Rightc 2 = a 2 + b 2 Obtusec 2 > a 2 + b 2 Acutec 2 < a 2 + b 2
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COMPLETE: L = ____ H = ____ 45
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L = L H = L 2
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SOLVE: x = _____ y = _____ 8 x y 45
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x = 8 y = 8 2
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COMPLETE: L L = _____ H = _____ 30 60 LsLs
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L L = L s 3 H = 2 L s
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SOLVE: x = _____ y = _____ 30 60 4 x y
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x = 4 3 y = 8
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AREA OF EQUILATERAL TRIANGLES : A = ½ ( ____ )( ____ ) A = ½ ( ____)( ____ ) A = ( ____ ) 2 ( ____ )
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A = ½ bh A = ½ ap A = s 2 4
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Find the area: (Equilateral Triangle) 6
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30 6 3 9 18 A = ½ bh A = ½ (18)(9 ) A = 81 A = ½ ap A = ½ (3 )(54) A = 81 A = s 2 4 A = (18) 2 4 A = 81
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AREA OF SQUARES: A = ( ____ ) 2 A = ½ ( ____ )( ____ )
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A = s 2 A = ½ ap A = ½ d 1 d 2 side (s) a
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Find the area: (Square) 10
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20 A = s 2 A = 20 2 A = 400 A = ½ ap A = ½ (10)(80) A = 400 A = ½ d 1 d 2 A = ½ (20 )(20 ) A = 400 45
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AREA OF REGULAR HEXAGONS: A = ½ ( ____ )( ____ )
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A = ½ ap 120 a 60
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Find the area: 8 (Regular Hexagon)
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8 44 4 3 60 A = ½ ap A = ½ (4 3)(48) A = 96 3
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AREA OF PARALLELOGRAMS: A = ( ____ )( ____ )
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A = bh Base (b) Height (h)
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AREA OF ANY TRIANGLE: A = ½ ( ____ )( ____ )
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A = ½bh base (b) height (h)
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Find the height: 66 4
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h 2 + 2 2 = 6 2 h 2 = 32 h = 32 = 4 2 6 6 4 22 h
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AREA OF RIGHT TRIANGLES: A = ½ ( ____ )( ____ )
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A = ½ (l 1 )( l 2 ) leg (l 1 )leg (l 2 )
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AREA OF RHOMBUSES: A = ½ ( ____ ) ( ____ )
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A = ½ (d 1 )(d 2 )
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AREA OF TRAPEZOIDS: A = ½ ( ____ ) ( ____ + ____ )
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A = ½ (h)(b 1 + b 2 ) base (b 1 ) base (b 2 ) height (h)
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FOR CIRCLES: Circumference = ( __ )( __ )( __ )
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C = 2rπ
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What fraction of the circumference is arc AB? r 120 o A B
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120 = 1 360 3
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AREA OF CIRCLES: A = ( ____ )( ____ ) 2
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A = πr 2
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What fraction of the circle is shaded? 45 0 r
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45 = 1 360 8
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