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DOUBLE- ANGLE AND HALF-ANGLE IDENTITIES. If we want to know a formula for we could use the sum formula. we can trade these places This is called the double.

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Presentation on theme: "DOUBLE- ANGLE AND HALF-ANGLE IDENTITIES. If we want to know a formula for we could use the sum formula. we can trade these places This is called the double."— Presentation transcript:

1 DOUBLE- ANGLE AND HALF-ANGLE IDENTITIES

2 If we want to know a formula for we could use the sum formula. we can trade these places This is called the double angle formula for sine since it tells you the sine of double x

3 Let's try the same thing for This is the double angle formula for cosine but by substituting some identities we can express it in a couple other ways.

4 Double-angle Formula for Tangent

5 Summary of Double-Angle Formulas

6 x x’x’ 4 5 -3 Use triangle to find values. Let's draw a picture.

7 We can also derive formulas for an angle divided by 2 (called the half angle formula). We’ll do this by using the double angle formula for cosine that we found. Let’s solve this for sin  Now let  = x/2 In this formula it is NOT both + and - but you must figure out where the terminal side of the angle is and put on the appropriate sign for that quadrant.

8 We can also derive a half angle formula for cosine in a similar manner. We’ll do this by using a different version of the double angle formula for cosine. Let’s solve this for cos  Now let  = x/2 In this formula it is NOT both + and - but you must figure out where the terminal side of the angle is and put on the appropriate sign for that quadrant.

9 Now to derive a half angle formula for tangent, let’s use the fact that we know that tangent is sine over cosine and use their half angle formulas.

10 Half-Angle Formulas Summary As stated it is NOT both + and - but you must figure out where the terminal side of the angle is and put on the appropriate sign for that quadrant.

11

12 We could find sin 15° using the half angle formula. Since 15° is half of 30° we could use this formula if x = 30° 30° 15° is in first quadrant and sine is positive there so we want the +

13 x x’x’ 4 5 -3 Use triangle to find cosine value. If  is in quadrant II then half  would be in quadrant I where sine is positive


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