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Worksheet: Acids, Bases & pH Key. 1. Label the substance below as an acid, base or neutral substance. (a)pH = 7 (b) pOH = 9 (c) pH = 3 (d) pOH = 4 (e)

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Presentation on theme: "Worksheet: Acids, Bases & pH Key. 1. Label the substance below as an acid, base or neutral substance. (a)pH = 7 (b) pOH = 9 (c) pH = 3 (d) pOH = 4 (e)"— Presentation transcript:

1 Worksheet: Acids, Bases & pH Key

2 1. Label the substance below as an acid, base or neutral substance. (a)pH = 7 (b) pOH = 9 (c) pH = 3 (d) pOH = 4 (e) pH = 13 (f) pOH = 7

3 1. Label the substance below as an acid, base or neutral substance. (a)pH = 7 N(b) pOH = 9 A (c) pH = 3 A(d) pOH = 4 B (e) pH = 13 B(f) pOH = 7 N

4 2. How does the Arrhenius theory define an acid?

5 An acid produces H 3 O + ions when dissolved in water.

6 3. How does the Arrhenius theory define an base?

7 A base produces OH - ions when dissolved in water.

8 4. Differentiate between an electrolyte and a nonelectrolyte.

9 An electrolyte dissolves into ions when placed in water whereas a nonelectrolyte dissolves into molecules.

10 5. What type of substances are electrolytes?

11 Acids, Bases, Salts

12 6. When H+ ions are dissolved in water they become hydronium ions. What is the formula for a hydronium ion?

13 H3O+H3O+

14 7. What is the pH of a solution with a [H + ] = 4.32 x 10 -12 ?

15 pOH = 11.365

16 8. What is the pOH of a solution with a [OH - ] = 6.83 x 10 -3 ?

17 pOH = 2.166

18 9. What is the pOH of a solution with a pH = 3.8?

19 pOH = 10.2

20 10. What is the [H + ] in a solution with a pH = 7.3?

21 [H + ] = 5.0 x 10 -8

22 11. What is the [OH - ] in a solution with a pOH = 10.7?

23 [OH - ] = 2.0 x 10 -11

24 12. What is the pH of a solution with a [OH - ] = 8.62 x 10 -5 ?

25 pH = 9.936

26 13a) Write the balanced equation for the acid-base neutralization of H 2 SO 4 and Ba(OH) 2.

27 H 2 SO 4 + Ba(OH) 2 → BaSO 4 + 2H 2 O

28 13b) Write the balanced equation for the acid-base neutralization of HF and NaOH.

29 HF + NaOH → NaF + H 2 O

30 13c) Write the balanced equation for the acid-base neutralization of HI and Sr(OH) 2.

31 2HI + Sr(OH) 2 → SrI 2 + 2H 2 O

32 13d) We often use the equation M acid x V acid = M base x V base. Which of the acid-base neutralization reactions above could we not use this formula for? Explain.

33 The reaction between HI and Sr(OH) 2 could not be used because the acid and the base do not react in a 1:1 ratio.

34 13e) In an acid-base neutralization reaction 26 ml of Ba(OH) 2 reacts with 16 ml of 0.48M H 2 SO 4. What is the molarity of the Ba(OH)2?

35 0.30M

36 13f) How many milliliters of 0.57M HF will react with 39 ml of 0.86M NaOH in an acid-base neutralization reaction?

37 59 ml


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