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Worksheet: Acids, Bases & pH Key
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1. Label the substance below as an acid, base or neutral substance. (a)pH = 7 (b) pOH = 9 (c) pH = 3 (d) pOH = 4 (e) pH = 13 (f) pOH = 7
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1. Label the substance below as an acid, base or neutral substance. (a)pH = 7 N(b) pOH = 9 A (c) pH = 3 A(d) pOH = 4 B (e) pH = 13 B(f) pOH = 7 N
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2. How does the Arrhenius theory define an acid?
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An acid produces H 3 O + ions when dissolved in water.
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3. How does the Arrhenius theory define an base?
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A base produces OH - ions when dissolved in water.
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4. Differentiate between an electrolyte and a nonelectrolyte.
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An electrolyte dissolves into ions when placed in water whereas a nonelectrolyte dissolves into molecules.
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5. What type of substances are electrolytes?
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Acids, Bases, Salts
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6. When H+ ions are dissolved in water they become hydronium ions. What is the formula for a hydronium ion?
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H3O+H3O+
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7. What is the pH of a solution with a [H + ] = 4.32 x 10 -12 ?
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pOH = 11.365
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8. What is the pOH of a solution with a [OH - ] = 6.83 x 10 -3 ?
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pOH = 2.166
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9. What is the pOH of a solution with a pH = 3.8?
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pOH = 10.2
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10. What is the [H + ] in a solution with a pH = 7.3?
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[H + ] = 5.0 x 10 -8
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11. What is the [OH - ] in a solution with a pOH = 10.7?
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[OH - ] = 2.0 x 10 -11
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12. What is the pH of a solution with a [OH - ] = 8.62 x 10 -5 ?
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pH = 9.936
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13a) Write the balanced equation for the acid-base neutralization of H 2 SO 4 and Ba(OH) 2.
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H 2 SO 4 + Ba(OH) 2 → BaSO 4 + 2H 2 O
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13b) Write the balanced equation for the acid-base neutralization of HF and NaOH.
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HF + NaOH → NaF + H 2 O
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13c) Write the balanced equation for the acid-base neutralization of HI and Sr(OH) 2.
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2HI + Sr(OH) 2 → SrI 2 + 2H 2 O
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13d) We often use the equation M acid x V acid = M base x V base. Which of the acid-base neutralization reactions above could we not use this formula for? Explain.
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The reaction between HI and Sr(OH) 2 could not be used because the acid and the base do not react in a 1:1 ratio.
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13e) In an acid-base neutralization reaction 26 ml of Ba(OH) 2 reacts with 16 ml of 0.48M H 2 SO 4. What is the molarity of the Ba(OH)2?
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0.30M
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13f) How many milliliters of 0.57M HF will react with 39 ml of 0.86M NaOH in an acid-base neutralization reaction?
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59 ml
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