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MA 242.003 Day 61 – April 12, 2013 Pages 777-778: Tangent planes to parametric surfaces – an example Section 12.6: Surface area of parametric surfaces.

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Presentation on theme: "MA 242.003 Day 61 – April 12, 2013 Pages 777-778: Tangent planes to parametric surfaces – an example Section 12.6: Surface area of parametric surfaces."— Presentation transcript:

1 MA 242.003 Day 61 – April 12, 2013 Pages 777-778: Tangent planes to parametric surfaces – an example Section 12.6: Surface area of parametric surfaces – Review and examples Section 13.6: Surface integrals

2 Let S be the parametric surface traced out by the vector- valued function as u and v vary over the domain D. Pages 777-778: Tangent planes to parametric surfaces

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9 (continuation of example)

10 Section 12.6: Surface area of parametric surfaces

11 Goal: To compute the surface area of a parametric surface given by with u and v in domain D in the uv-plane. 1. Partition the region D, which also partitions the surface S

12 So we approximate by the Parallelogram determined by and

13 So we approximate by the Parallelogram determined by and

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15 Now find the surface area.

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17 Another method:

18 (continuation of example)

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23 Section 13.6: Surface Integrals

24 Section 12.6: Surface area of parametric surfaces Goal: To define the surface integral of a function f(x,y,z) over a parametric surface given by with u and v in domain D in the uv-plane.

25 Section 12.6: Surface area of parametric surfaces Goal: To define the surface integral of a function f(x,y,z) over a parametric surface given by with u and v in domain D in the uv-plane. 1. Partition the region D, which also partitions the surface S

26 Section 12.6: Surface area of parametric surfaces

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30 How do we evaluate such an integral?

31 Recall our approximation of surface area:

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33 The surface integral over S is the “double integral of the function over the domain D of the parameters u and v”.

34 This formula should be compared to the line integral formula

35 Notice the special case: The surface integral of f(x,y,z) = 1 over S yields the “surface area of S”

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37 (continuation of example)

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