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Ch. 6 Work and Kinetic Energy AP Physics C
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What is work? Write your thoughts on the whiteboard, Share with your table partner, Share with the whole class
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Weightlifter If the weightlifter squats through a vertical distance of 80 cm and has 163.6 kg on the bar, how work does he do on the bar to push the weight back up at a constant speed?
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Why is this considered work?
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Is there work done? The woman carries the groceries –at a level position over a level floor? –Up a flight of stairs?
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Definition for work done on an object when the forces are constant: By definition, the dot product is: Where is the angle between the net force vector and the displacement vector.
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Dot Product The dot product or scalar product is defined as Using a geometric interpretation allows us to find the angle between two vectors.
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What does this mean? Recall that: – A = A x i + A y j + A k k and – B = B x i + B y j + B k k A· B = (A x i + A y j + A k k )· (B x i + B y j + B k k ) or
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Sample Problem #1 Given: F = 2 i + 3 j – 5 k s = -3 i – 4 j + 6 k Find: The total work done The angle between the force and displacement vectors
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How is work and energy related to each other? W = Fd (The force and the displacement are parallel to each other.) W = mad W = m(½v f 2 - ½v i 2 ) W = ½m v f 2 - ½m v i 2 W = K f – K i W = ∆K This is known as the Work- Kinetic Energy Theorem
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Sample Problem #2 If the initial speed is 10 m/s and the mass of the object is 50 kg, what is the final speed? Note: The work done was determined by finding the area under the F-d graph.
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Work done by varying forces: To calculate the work done, you determine the area under the force- displacement graph. This graph is for the work done when stretching a linear spring.
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Work done by varying forces: Which means in some cases, you will need to divide the area into an infinite number of infinitesimal pieces.
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Work done by varying forces: That means that you will be determining the integral (i.e. anti- derivative):
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Sample Problem 3 A block of mass 1.5 kg is pushed against a spring with a force constant of 50 N/m. If the spring is compressed 0.10 m, at what speed does the block leave the spring? Neglect any frictional effects.
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Sample Problem 2 If the net force is given by the force- position function, How much work is done to move the object from x = 1.0 m to x = 3.0 m?
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Power Rate of doing work 1 horsepower (hp) = 746 watts The power rating for an object is 2.2 hp. If the object can move with an average speed of 15 m/s, what is the net force that acts on it?
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Any Questions?
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