II III I II. Concentration Solutions. A. Concentration  The amount of solute in a solution.  Describing Concentration % by mass - medicated creams %

Presentation on theme: "II III I II. Concentration Solutions. A. Concentration  The amount of solute in a solution.  Describing Concentration % by mass - medicated creams %"— Presentation transcript:

II III I II. Concentration Solutions

A. Concentration  The amount of solute in a solution.  Describing Concentration % by mass - medicated creams % by volume - rubbing alcohol ppm, ppb - water contaminants molarity - used by chemists molality - used by chemists

A. Concentration SAWS Water Quality Report - June 2000

A. Molarity  Concentration of a solution. total combined volume substance being dissolved

A. Molarity 2M HCl What does this mean?

A. Molarity Calculations  Find the molarity of a 250 mL solution containing 10.0 g of NaF. 10.0 g 1 mol 41.99 g = 0.238 mol NaF 0.238 mol 0.25 L M == 0.95M NaF

A. Molarity Calculations  How many grams of NaCl are required to make 0.500L of 0.25M NaCl? 0.500 L0.25 mol 1 L = 7.3 g NaCl 58.44 g 1 mol

B. Molality mass of solvent only 1 kg water = 1 L water

B. Molality  Find the molality of a solution containing 75 g of MgCl 2 in 250 mL of water. 75 g MgCl 2 1 mol MgCl 2 95.21 g MgCl 2 = 3.2 m MgCl 2 0.25 kg water

B. Molality  How many grams of NaCl are req’d to make a 1.54m solution using 0.500 kg of water? 0.500 kg water1.54 mol NaCl 1 kg water = 45.0 g NaCl 58.44 g NaCl 1 mol NaCl

C. Dilution  Preparation of a desired solution by adding water to a concentrate.  Moles of solute remain the same.

C. Dilution  What volume of 15.8M HNO 3 is required to make 250 mL of a 6.0M solution? GIVEN: M 1 = 15.8M V 1 = ? M 2 = 6.0M V 2 = 250 mL WORK: M 1 V 1 = M 2 V 2 (15.8M) V 1 = (6.0M)(250mL) V 1 = 95 mL of 15.8M HNO 3

D. Preparing Solutions  500 mL of 1.54M NaCl 500 mL water 45.0 g NaCl mass 45.0 g of NaCl add water until total volume is 500 mL mass 45.0 g of NaCl add 0.500 kg of water 500 mL mark 500 mL volumetric flask  1.54m NaCl in 0.500 kg of water