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Nuclear Chemistry Chapter 23 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.

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Presentation on theme: "Nuclear Chemistry Chapter 23 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display."— Presentation transcript:

1 Nuclear Chemistry Chapter 23 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.

2 The symbols for various chemical elements and numbers of electrons, protons and neutrons in every species. Atomic number (Z) = number of protons in nucleus Mass number (A) = number of protons + number of neutrons = atomic number (Z) + number of neutrons X A Z Mass Number Atomic Number Element Symbol A Z 1p1p 1 1H1H 1 or proton 1n1n 0 neutron 0e0e 00 or electron 0e0e +1 00 or positron 4 He 2 44 2 or  particle 1 1 1 0 0 0 +1 4 2

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4 Balancing Nuclear Equations 1.Conserve mass number (A). The sum of protons plus neutrons in the products must equal the sum of protons plus neutrons in the reactants. 1n1n 0 U 235 92 + Cs 138 55 Rb 96 37 1n1n 0 ++ 2 235 + 1 = 138 + 96 + 2x1 2.Conserve atomic number (Z) or nuclear charge. The sum of nuclear charges in the products must equal the sum of nuclear charges in the reactants. 1n1n 0 U 235 92 + Cs 138 55 Rb 96 37 1n1n 0 ++ 2 92 + 0 = 55 + 37 + 2x0 23.1

5 212 Po decays by alpha emission. Write the balanced nuclear equation for the decay of 212 Po. 4 He 2 44 2 or alpha particle - 212 Po 4 He + A X 84 2Z 212 = 4 + AA = 208 84 = 2 + ZZ = 82 212 Po 4 He + 208 Pb 84 282 23.1

6 Worked Example 23.1

7 Worked Example 23.3

8 Nuclear Stability and Radioactive Decay Beta decay 14 C 14 N + 0  + 6 7 40 K 40 Ca + 0  + 19 20 1 n 1 p + 0  + 0 1 Decrease # of neutrons by 1 Increase # of protons by 1 Positron decay 11 C 11 B + 0  + 6 5 +1 38 K 38 Ar + 0  + 19 18 +1 1 p 1 n + 0  + 1 0 +1 Increase # of neutrons by 1 Decrease # of protons by 1 and have A = 0 and Z = 0 23.2

9 Electron capture decay Increase # of neutrons by 1 Decrease # of protons by 1 37 Ar + 0 e 37 Cl + 18 17 55 Fe + 0 e 55 Mn + 26 25 1 p + 0 e 1 n + 1 0 Alpha decay Decrease # of neutrons by 2 Decrease # of protons by 2 212 Po 4 He + 208 Pb 84 282 Spontaneous fission 252 Cf 2 125 In + 2 1 n 98 490 23.2

10 The radioactive decay series Is a sequence of nuclear reaction that ultimately result in the formation of a stable isotope. The decay series of naturally occurring uranium-238 to thorium- 234 involves 14 steps. The decay scheme, also shows the half – lives of all the products. The beginning radioactive isotope in the series is called the parent and the product, the daughter. 238 U Parent 206 Pb daughter 23.3 92 82 23.3 natural radioactivity

11 Kinetics of Radioactive Decay [N] = [N] 0 exp(- t)ln[N] = ln[N] 0 - t [N] ln [N] 23.3 rate = - NN tt rate = N NN tt = N - N = the number of atoms at time t N 0 = the number of atoms at time t = 0 is the decay constant ln2 = t½t½ [N] t [N] 0 = - t ln All radioactive decays obey first –order kinetics.

12 Problems

13 1 – 2 – 3 – 4 – 5 – 6 – 7 – 23 – 25 – 28 – 29 – 31 – 33 – 34 – 35 – 36 – 55 – 57 – 59


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