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Elliptic PDEs and the Finite Difference Method

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1 Elliptic PDEs and the Finite Difference Method
LECTURE 2 Elliptic PDEs and the Finite Difference Method

2 Aim of Lecture During this lecture we will discuss:
Elliptic Partial Differential Equations Finite Difference Method Taylor’s Series Expansions High Order Terms & Truncation Finite Difference Discretisation Solution Methods Linear/Matrix System Solvers Iterative Solvers: Jacobi, Gauss-Seidel Use of Excel

3 Elliptic PDEs Elliptic PDEs represent phenomena that have already reached a steady state and are, hence, time independent. Two classic Elliptic Equations are: Laplace Equation or Poisson’s Equation u(x,y) is dependent variable and g is a constant

4 Elliptic PDE – Example Temperature, u(x,y) profile around two computer chips on a printed circuit board. Where g is the heat source. Heat Source g

5 FINITE DIFFERENCE METHOD

6 Taylor’s Series Expansions
x+h x-h Recall the Taylor’s Series expansion of a function about a point, x We will use this to find approximate solutions to PDEs

7 High Order Terms Note the in the previous expansion
This refers to all powers of h greater than or equal to 4, e.g. When h is small, these high order terms are tiny, e.g. We can simplify expressions by making h small and ignoring high order terms This is known as truncation

8 Taylor Series expansions in 2D
x+Dx x-Dx y-Dy y y+Dy (x,y) Consider the function u expanded about the point (x,y)

9 Taylor Series expansions in 2D
Now consider a regular grid of points and use the notation This gives i i+1 i -1 j -1 j j+1

10 Finite Differences We can rearrange the Taylor’s series gives
(known as forward difference) (known as backward difference)

11 Finite Differences We can also add and subtract Taylor’s series
(1) – (2) gives (1) + (2) gives (known as central difference) (also known as central difference [2nd order])

12 Finite Differences: Summary
We can rearrange the Taylor’s series to get Then truncate the higher order terms and substitute for differentials in the PDE - Forward difference - Backward difference - Central difference Central difference (2nd order)

13 Exercise Write down the central difference approximations for:

14 Truncation Error Approximating derivatives, in this case using finite differences, is known as discretisation. These approximations will result in errors known as truncation error. Truncation Error

15 Finite Difference Method – Example
j -1 j j+1 Consider Poisson’s equation. Discretise Difference formula for each node:

16 Finite Difference Method – Example
Consider the case: Then The difference equation can be written as: or

17 Example u = 0 y x (1,0) (0,0) (0,1) (1,1) Consider the PDE shown, on a square domain with zero boundary conditions (u = 0)

18 Approximate Solution Represent using a Finite Difference grid with
Need to find approximations to u for all nodal values However we know that u = 0 on all boundaries So need only to find approximations for u at four internal nodes Required values are i = j =

19 Example In general we have: Or, in terms of the 4 unknowns: So that
and then (e.g. using Matlab) i = j =

20 Solvers Notice that the Finite Difference method will generally result in a matrix system of the form Au = b where u = [u1 u2 ……….. un ]T b = [b1 b2 ……….. bn ]T and

21 Solvers Generally in 2D we will get matrices of the form
Note the banded structure of the matrix.

22 Banded matrices Banded matrices arise in finite difference methods because (in 2D) the value at each node is directly dependent only on its four nearest neighbours. Banded matrices are sparse (i.e. mostly full of zeroes) with a regular structure and hence can be stored in minimal space. For example, if the finite difference grid is 100 by 100, the number of unknowns is 10,000 and the number of entries in the matrix is 100,000,000 which might require 1,600Mb (megabytes) to store in a computer. However, by just storing five non-zero diagonals we can reduce the storage requirement to around 50,000 values or around 800Kb (kilobytes) = 0.8Mb. This means the system can be solved much more rapidly.

23 Direct and Iterative Solvers
Exact solution requires inversion of A Very slow. Huge memory requirements. Direct Solvers: (Gaussian Elimination, etc) Need to store whole matrix. (Disadvantage) Slow, especially for large matrices. (Disadvantage) Robust even with ill-conditioned matrices. (Advantage) Iterative Solvers: (Jacobi, Gauss Seidel, etc) Good for large matrix systems. No need to store whole matrix (Advantage) Fast, even for large matrices. (Advantage) Poor for ill-conditioned matrices. May converge only slowly. (Disadvantage)

24 Iterative Solvers Two classical Examples are Jacobi and Gauss-Seidel
Consider following system of equations Start with initial vector x1 = [0, 0, 0] T. The final solution is x = [1, 1,1] T. It takes 8 iterations for Jacobi and 6 iterations for Gauss Seidel. Jacobi Gauss Seidel

25 Iterative Solvers – Matrix Version
Need to solve Ax = b Let A = D+L+U (Diagonal + Lower triangle + Upper triangle) The Jacobi method can be written as: Dx(k+1) = -(L+U)x(k) + b The Gauss Seidel method can be written: (D+L)x(k+1) = -Ux(k) + b (generally converges faster as it uses most recent information)

26 Iterative Solvers – Convergence
To ensure convergence of an iterative solver such as Jacobi or Gauss Seidel, we require Diagonal Dominance in the matrix, i.e. for each row i In other words, the diagonal element in each row (or column) is greater in magnitude than the sum of the off diagonal elements We can sometimes rearrange the order of the equations to ensure diagonal dominance

27 Exercise Write down the Jacobi method for the following system
Would you expect it to converge? If not, how would you rewrite it so that it would converge?

28 Example – Gauss Seidel Example: use Excel to solve the following
Rewrite as Gauss-Seidel iterations

29 Gauss Seidel in Excel FLAG (to reset, see Tutorial 1) Formula for X1
(uses old value of X2)

30 Gauss Seidel in Excel Formula for X2 (uses current value of X1)


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