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Estimation: Confidence Intervals Based in part on Chapter 6 General Business 704
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Objectives: Estimation n Distinguish point & interval estimates n Explain interval estimates n Compute confidence interval estimates l Population mean & proportion l Population total & difference n Determine necessary sample size
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Thinking Challenge Suppose you’re interested in the average amount of money that students in this class (the population) have in their possession. How would you find out?
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Statistical Methods
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Estimation Process Mean, , is unknown Population Random Sample I am 95% confident that is between 40 & 60. Mean X = 50 Sample
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Population Parameter Estimates
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Estimation Methods
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Point Estimation n Provides single value l Based on observations from 1 sample n Gives no information about how close value is to the unknown population parameter Example: Sample mean X = 3 is point estimate of unknown population mean Example: Sample mean X = 3 is point estimate of unknown population mean
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Estimation Methods
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Interval Estimation n Provides range of values l Based on observations from 1 sample n Gives information about closeness to unknown population parameter l Stated in terms of probability n Example: Unknown population mean lies between 40 & 60 with 95% confidence
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Key Elements of Interval Estimation Confidence interval Sample statistic (point estimate) Confidence limit (lower) Confidence limit (upper) A probability that the population parameter falls somewhere within the interval.
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Confidence Limits for Population Mean Parameter = Statistic ± Error © 1984-1994 T/Maker Co.
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Many Samples Have Same Interval 90% Samples 95% Samples 99% Samples +1.65 x +2.58 x x_ XXXX +1.96 x -2.58 x -1.65 x -1.96 x X = ± Z x
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n Probability that the unknown population parameter falls within interval Denoted (1 - Denoted (1 - is probability that parameter is not within interval is probability that parameter is not within interval n Typical values are 99%, 95%, 90% Level of Confidence
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Intervals & Level of Confidence Sampling Distribution of Mean Large number of intervals Intervals extend from X - Z X to X + Z X (1 - ) % of intervals contain . % do not.
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Factors Affecting Interval Width n Data dispersion Measured by Measured by n Sample size X = / n X = / n Level of confidence (1 - ) Level of confidence (1 - ) l Affects Z Intervals extend from X - Z X to X + Z X © 1984-1994 T/Maker Co.
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Confidence Interval Estimates
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Confidence Interval Mean ( Known) n Assumptions l Population standard deviation is known l Population is normally distributed If not normal, can be approximated by normal distribution (n 30) If not normal, can be approximated by normal distribution (n 30) n Confidence interval estimate Note: 99% Z=2.58, 95% Z=1.96, 90% Z=1.65
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Estimation Example Mean ( Known) The mean of a random sample of n = 25 is X = 50. Set up a 95% confidence interval estimate for if = 10.
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Thinking Challenge You’re a Q/C inspector for Gallo. The for 2-liter bottles is.05 liters. A random sample of 100 bottles showed X = 1.99 liters. What is the 90% confidence interval estimate of the true mean amount in 2-liter bottles? 2 liter © 1984-1994 T/Maker Co.
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Confidence Interval Solution for Gallo
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Confidence Interval Estimates
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Confidence Interval Mean ( Unknown) n Assumptions l Population standard deviation is unknown l Population must be normally distributed n Use Student’s t distribution n Confidence interval estimate
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Student’s t Distribution 0 t (df = 5) Standard normal t (df = 13) Bell- shaped Symmetric ‘Fatter’ tails Note: As d.f. approach 120, Z and t become very similar
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Student’s t Table Assume: n = 3 df= n - 1 = 2 =.10 /2 =.05 2.920 t values / 2.05
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Degrees of Freedom n Number of observations that are free to vary after sample statistic has been calculated n Example l Sum of 3 numbers is 6 X 1 = 1 (or any number) X 2 = 2 (or any number) X 3 = 3 (cannot vary) Sum = 6 degrees of freedom = n -1 = 3 -1 = 2
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Estimation Example Mean ( Unknown) A random sample of n = 25 has X = 50 & S = 8. Set up a 95% confidence interval estimate for .
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Thinking Challenge You’re a time study analyst in manufacturing. You’ve recorded the following task times (min.): 3.6, 4.2, 4.0, 3.5, 3.8, 3.1. What is the 90% confidence interval estimate of the population mean task time?
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Confidence Interval Solution for Time Study X = 3.7 S = 3.8987 S = 3.8987 n = 6, df = n - 1 = 6 - 1 = 5 n = 6, df = n - 1 = 6 - 1 = 5 S / n = 3.8987 / 6 = 1.592 S / n = 3.8987 / 6 = 1.592 t.05,5 = 2.0150 t.05,5 = 2.0150 3.7 - (2.015)(1.592) 3.7 + (2.015)(1.592) 3.7 - (2.015)(1.592) 3.7 + (2.015)(1.592) 0.492 6.908 0.492 6.908
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Confidence Interval Estimates
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Estimation for Finite Populations n Assumptions l Sample is large relative to population s n / N >.05 n Use finite population correction factor Confidence interval (mean, unknown) Confidence interval (mean, unknown)
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Confidence Interval Estimates
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Confidence Interval Proportion n Assumptions l Two categorical outcomes l Population follows binomial distribution l Normal approximation can be used n·p 5 & n·(1 - p) 5 n Confidence interval estimate
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Estimation Example Proportion A random sample of 400 graduates showed 32 went to grad school. Set up a 95% confidence interval estimate for p.
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Thinking Challenge You’re a production manager for a newspaper. You want to find the % defective. Of 200 newspapers, 35 had defects. What is the 90% confidence interval estimate of the population proportion defective?
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Confidence Interval Solution for Defects n·p 5 n·(1 - p) 5
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Estimation Methods
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Bootstrapping Method n Used if population is not normal n Requires significant computer power n Steps l Take initial sample l Sample repeatedly from initial sample l Compute sample statistic l Form resampling distribution Limits are values that cut off smallest & largest /2 % Limits are values that cut off smallest & largest /2 %
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Finding Sample Sizes For Estimating I don’t want to sample too much or too little!
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Sample Size Example What sample size is needed to be 90% confident of being correct within 5? A pilot study suggested that the standard deviation is 45.
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Thinking Challenge You work in Human Resources at Merrill Lynch. You plan to survey employees to find their average medical expenses. You want to be 95% confident that the sample mean is within ± $50. A pilot study showed that was about $400. What sample size do you use?
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Sample Size Solution Medical Expenses
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Finding Sample Sizes For Estimating Proportions I don’t want to sample too much or too little! Remember Error is acceptable error Z is based on confidence level chosen p is the true proportion of “success” Never under-estimate p When in doubt, use p=.5 Remember Error is acceptable error Z is based on confidence level chosen p is the true proportion of “success” Never under-estimate p When in doubt, use p=.5
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Sample Size Example for Estimating p What sample size is needed to be 90% confident (Z=1.645) of being correct within proportion of.04 when using p=.5 (since no useful estimate of p is available)?
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Estimation of Population Total n In auditing, population total is more important than mean Total = N X Total = N X n Confidence interval (population total) l Degrees of freedom = n - 1
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Estimation of Differences n Used to estimate the magnitude of errors n Steps l Determine sample size Compute average difference, D Compute average difference, D l Compute standard deviation of differences l Set up confidence interval estimate
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Estimation of Differences Equations Mean Difference: Standard Deviation: Interval Estimate:
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Objectives: Estimation n Distinguish point & interval estimates n Explain interval estimates n Compute confidence interval estimates l Population mean & proportion l Population total & difference n Determine necessary sample size
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