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Saturated solution – no more solute will dissolve solubility product constant – equilibrium constant for ionic compounds that are only slightly soluble.

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Presentation on theme: "Saturated solution – no more solute will dissolve solubility product constant – equilibrium constant for ionic compounds that are only slightly soluble."— Presentation transcript:

1 saturated solution – no more solute will dissolve solubility product constant – equilibrium constant for ionic compounds that are only slightly soluble K sp CaCO 3 (s) Ca 2+ (aq) + CO 3 2 − (aq) H2OH2O K = [ Ca 2+ ] [CO 3 2− ] sp

2 molar solubility – # moles of ionic solid that dissolves per 1 L DI water to form a saturated solution at 25  C molar solubility always equals “X” 6.7 x 10 - 5 moles of CaCO 3 (s) will dissolve per 1 L DI water producing 6.7 x 10 - 5 M Ca 2+ (aq) and 6.7 x 10 - 5 M CO 3 2 - (aq) Determine the final equilibrium concentration of Ca 2+ (aq) and CO 3 2 - (aq) in the saturated solution

3 Determine the equilibrium concentration of all ions and the molar solubility of Ca 3 (PO 4 ) 2 (s)


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