Presentation is loading. Please wait.

Presentation is loading. Please wait.

MATH 31 LESSONS Chapter 2: Derivatives 4. The Chain Rule.

Similar presentations


Presentation on theme: "MATH 31 LESSONS Chapter 2: Derivatives 4. The Chain Rule."— Presentation transcript:

1 MATH 31 LESSONS Chapter 2: Derivatives 4. The Chain Rule

2 Section 2.6: The Chain Rule Read Textbook pp. 96 - 102

3 A. Composite Functions (Review) A composite function is defined as where g (x) is the “inside function” f is the “outside function”

4 Ex. 1If f (x) = x 2 - 3x + 7 and g(x) = 4 - x 2, then find: Try this example on your own first. Then, check out the solution.

5 f (x) = x 2 - 3x + 7 g(x) = 4 - x 2 g (x) is the inside function. Replace it with g (x) = 4 - x 2

6 f (x) = x 2 - 3x + 7 g(x) = 4 - x 2 Wherever you see x in the f function, replace it with 4 - x 2

7 f (x) = x 2 - 3x + 7 g(x) = 4 - x 2

8 B. The Chain Rule For the composite function

9 First, take the derivative of the outside function (and leave the inside function the same)...

10 ... then, take the derivative of the inside function

11 The chain rule can also be expressed in Leibnitz notation:

12 This is easy to remember, because if we treat these as true fractions, the du’s would cancel and you would be left with dy / dx. But of course, you would never do this.

13 The Chain Rule Applied to Power Functions The most common application of the chain rule in this unit is when the outside function is a power. e.g. y = [ f (x) ] n

14 First, take the derivative of the outside power function (and leave the inside function the same)...... then, take the derivative of the inside function

15 or

16 Ex. 2Differentiate using the chain rule. No need to simplify. Try this example on your own first. Then, check out the solution.

17 Method 1: Leibnitz Let u = x 2 - 3x Assign u as the “inside function”

18 Let u = x 2 - 3x Then, y = u 4 When you replace the inside function with u, you are left with just the outside function

19 u = x 2 - 3x y = u 4 This is the Leibnitz formula for the chain rule. Remember, to ensure it is in the proper form, you can “cancel” the du’s and you are left with dy / dx

20 u = x 2 - 3x y = u 4 Substitute y = u 4 and u = x 2 - 3x

21 u = x 2 - 3x y = u 4

22 u = x 2 - 3x y = u 4 Back substitute so that the answer is in terms of x

23 Method 2: “Outside, Inside” The “inside function” is x 2 - 3x

24 The “outside function” is the 4 th power

25 First, do the derivative of the outside function. Be certain to keep the inside function the same

26 Next, don’t forget to do the derivative of the inside function

27 Since this method is much faster, we will use this method exclusively from now on.

28 Ex. 3Differentiate using the chain rule. No need to simplify. Try this example on your own first. Then, check out the solution.

29 Bring all the x’s to the top.

30 First, do the derivative of the outside function. Be certain to keep the inside function the same

31 Next, don’t forget to do the derivative of the inside function

32

33 Ex. 4Differentiate using the chain rule. No need to simplify. Try this example on your own first. Then, check out the solution.

34 Express in power notation.

35 First, do the derivative of the outside function. Be certain to keep the inside function the same

36 Next, don’t forget to do the derivative of the inside function

37

38 Ex. 5Differentiate using the chain rule. No need to simplify. Try this example on your own first. Then, check out the solution.

39 First, do the derivative of the outside function. Be certain to keep the inside function the same

40 Next, don’t forget to do the derivative of the inside function

41 Apply the derivative to each part of the inside function. You will be required to do the chain rule again.

42 Derivative of “outside function” (leave inside same) Don’t forget the derivative of the “inside function”

43

44 Ex. 6Find Try this example on your own first. Then, check out the solution.

45 You read this as: “Find the derivative of y, and then evaluate it at x = 3”

46  First, find the derivative using the chain rule:

47 chain rule

48

49  Next, evaluate the derivative at x = 3:

50

51 Ex. 7If g (3) = 6, g (3) = 5, f (5) = 2, and f (6) = 8, then evaluate: Try this example on your own first. Then, check out the solution.

52  Expand the function first in terms of x : First, do the derivative of the outside function. Be certain to keep the inside function the same

53 Next, don’t forget to do the derivative of the inside function

54  Now, evaluate the function: g (3) = 6 g (3) = 5 f (5) = 2 f (6) = 8

55 g (3) = 6 g (3) = 5 f (5) = 2 f (6) = 8

56 g (3) = 6 g (3) = 5 f (5) = 2 f (6) = 8

57 Ex. 8Differentiate, using more than one rule. Fully factor your answer. Try this example on your own first. Then, check out the solution.

58 Which rule do you use first?

59 Take the derivative of the first and leave the second + Leave the first and take the derivative of the second (u  v) = u v + u v Use the product rule first

60 Next, use the chain rule

61

62 Put in the same order.

63 Let A = x 2 + 6 Use substitution to make the factoring easier.

64 But A = x 2 + 6 After factoring, back substitute so that it is in terms of only x. Be certain to use brackets.

65 But A = x 2 + 6 Simplify inside the bracket.

66 But A = x 2 + 6

67 Ex. 9Differentiate, using more than one rule. Fully simplify your answer. Try this example on your own first. Then, check out the solution.

68 Which rule do you use first?

69 Chain rule first First, do the derivative of the outside function. Be certain to keep the inside function the same

70 Don’t forget to do the derivative of the “inside function”.

71 Use the quotient rule Quotient Rule:

72

73

74

75 This is another possible answer.


Download ppt "MATH 31 LESSONS Chapter 2: Derivatives 4. The Chain Rule."

Similar presentations


Ads by Google