# 5-3 Solving Proportions Warm Up Problem of the Day Lesson Presentation

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5-3 Solving Proportions Warm Up Problem of the Day Lesson Presentation
Course 2 Warm Up Problem of the Day Lesson Presentation

5-3 Solving Proportions Warm Up
Course 2 5-3 Solving Proportions Warm Up Determine whether the ratios are proportional. 5 8 15 24 1. , yes 12 15 16 25 2. , no 15 10 , 20 16 3. no 14 18 , 42 54 4. yes

5-3 Solving Proportions Problem of the Day
Course 2 5-3 Solving Proportions Problem of the Day If A = 1, B = 2, C = 3, D = 4, and so on, all the way to Z = 26, then what is A + B + C + D Z = ? (Hint: A + Z = B + Y.) 351

Course 2 5-3 Solving Proportions Learn to solve proportions by using cross products.

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Course 2 5-3 Solving Proportions Insert Lesson Title Here Vocabulary cross product

5 · 6 = 30 6 2 = 15 5 2 · 15 = 30 5-3 Solving Proportions
Course 2 5-3 Solving Proportions For two ratios, the product of the numerator in one ratio and the denominator in the other is a cross product. If the cross products of the ratios are equal, then the ratios form a proportion. 5 · 6 = 30 = 2 5 6 15 2 · 15 = 30

5-3 Solving Proportions a c In the proportion = , the cross products,
Course 2 5-3 Solving Proportions CROSS PRODUCT RULE In the proportion = , the cross products, a · d and b · c are equal. a b c d You can use the cross product rule to solve proportions with variables.

Additional Example 1: Solving Proportions Using Cross Products
Course 2 5-3 Solving Proportions Additional Example 1: Solving Proportions Using Cross Products Use cross products to solve the proportion. = m 5 9 15 15 · m = 9 · 5 The cross products are equal. 15m = 45 Multiply. 15m 15 = 45 15 Divide each side by 15 to isolate the variable. m = 3

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Course 2 5-3 Solving Proportions Insert Lesson Title Here Check It Out: Example 1 Use cross products to solve the proportion. 6 7 = m 14 7 · m = 6 · 14 The cross products are equal. 7m = 84 Multiply. 7m 7 84 7 = Divide each side by 7 to isolate the variable. m = 12

Course 2 5-3 Solving Proportions When setting up a proportion to solve a problem, use a variable to represent the number you want to find. In proportions that include different units of measurement, either the units in the numerators must be the same and the units in the denominators must be the same or the units within each ratio must be the same. 16 mi 4 hr 8 mi x hr 16 mi 8 mi 4 hr x hr = =

Understand the Problem
Course 2 5-3 Solving Proportions Additional Example 2: Problem Solving Application If 3 volumes of Jennifer’s encyclopedia takes up 4 inches of space on her shelf, how much space will she need for all 26 volumes? 1 Understand the Problem Rewrite the question as a statement. Find the space needed for 26 volumes of the encyclopedia. List the important information: 3 volumes of the encyclopedia take up 4 inches of space.

Course 2 5-3 Solving Proportions Additional Example 2 Continued 2 Make a Plan Set up a proportion using the given information. Let x represent the inches of space needed. 3 volumes 4 inches 26 volumes x volumes inches =

Course 2 5-3 Solving Proportions Additional Example 2 Continued Solve 3 3 4 26 x Write the proportion. = 3 · x = 4 · 26 The cross products are equal. 3x = 104 Multiply. 3x 3 104 3 Divide each side by 3 to isolate the variable. = 2 3 x = 34 2 3 She needs 34 inches for all 26 volumes.

Course 2 5-3 Solving Proportions Additional Example 2 Continued 4 Look Back 4 · 26 = 104 26 3 4 = 2 3 34 3 · 34 2 3 = 104 The cross products are equal, so 34 2 3 is the answer

Understand the Problem
Course 2 5-3 Solving Proportions Check It Out: Example 2 John filled his new radiator with 6 pints of coolant, which is the 10 inch mark. How many pints of coolant would be needed to fill the radiator to the 25 inch level? 1 Understand the Problem Rewrite the question as a statement. Find the number of pints of coolant required to raise the level to the 25 inch level. List the important information: 6 pints is the 10 inch mark.

Check It Out: Example 2 Continued
Course 2 5-3 Solving Proportions Check It Out: Example 2 Continued 2 Make a Plan Set up a proportion using the given information. Let p represent the pints of coolant. 6 pints 10 inches p 25 inches pints inches =

Check It Out: Example 2 Continued
Course 2 5-3 Solving Proportions Check It Out: Example 2 Continued Solve 3 6 10 p 25 Write the proportion. = 10 · p = 6 · 25 The cross products are equal. 10p = 150 Multiply. 10p 10 150 10 Divide each side by 10 to isolate the variable. = p = 15 15 pints of coolant will fill the radiator to the 25 inch level.

Check It Out: Example 2 Continued
Course 2 5-3 Solving Proportions Check It Out: Example 2 Continued 4 Look Back 10 · 15 = 150 6 10 15 = 25 6 · 25 = 150 The cross products are equal, so 15 is the answer.

Insert Lesson Title Here
Course 2 5-3 Solving Proportions Insert Lesson Title Here Lesson Quiz: Part I Use cross products to solve the proportion. 25 20 45 t 1. = t = 36 2. x 9 = 19 57 x = 3 2 3 r 36 3. = r = 24 n 10 28 8 4. = n = 35

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Course 2 5-3 Solving Proportions Insert Lesson Title Here Lesson Quiz: Part II 5. Carmen bought 3 pounds of bananas for \$1.08. June paid \$ 1.80 for her purchase of bananas. If they paid the same price per pound, how many pounds did June buy? 5 pounds

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