1. AES Advanced Encryption Standard

2. Requirements for AES AES had to be a private key algorithm. It had to use a shared secret key. It had to support the following key sizes: – 128 bits – 192 bits – 256 bits DES uses only 56-bit keys. If you were able to search half the DES key space in 1 second, then on average, it would take 149 trillion years to crack a 128-bit AES key.

3. Operation 1) Expand 128 bits key or 16-byte ( 4 X 4 Arrays) key into 11 (4 X 4 Arrays) and each arrays containing 16 bytes. (16 bytes – 176 bytes) (4 words – 44 words)(w0 to w43). 2)16 – bytes plain text block is copied into 4x4 array is called state 3)XOR state with key block.

4. Key expansion

5. After filling first array the remaining 10 arrays (w4 to w43) are filled one by one. Every added key array block depends on the immediately preceding block and the block 4 position earlier to it If the word in W array is a multiple of four, some complex logic is used (for w4,w8,w12….) for increase security But for others simple XOR is used. Like for w5, we would XOR w4 and w1 and store output as w5.

6. Key expansion But if word is multiple of four w4,w8,w12… then three functions are used. Rotate, Substitute and constant Rotate : Suppose original 4 word key is: Byt e 012345678910101 1212 1313 1414 1515 hex0 0101 0202 0303 0404 0505 0606 0707 0808 0909 0A0A 0B0B 0C0C 0D0D 0E0E 0F0F

7. Key expansion For find w4: 1) First Rotation will produce Rotate W3 ( 0C 0D 0E 0F) which is equals to ( 0D 0E 0F 0C ).

8. Key expansion 2) second substitute,we need to take one byte at a time and look up in S- box. For example first byte 0D is replace with 00,similarly, 0E is replace with 00..so on…

9. Key expansion 3) Finally at last stage substituted word XOR with constant ( with the help of constant table) as per round number. This constant is a word (4 bytes),and last 3 bytes always contain 0. Thus XORing any input word with such a constant is as good as XORing only with first byte of input word. Like D7 AB 76 FE XOR 01 00 00 00 = D6 AB 76 FE Finally this XOR with w [i-4] means w0. where I = word number. Round12345678910 constant01020408102040801B36

10. Plain text Operation A) First Plain text of 16 bytes arrange into 4 x 4 array. B) Apply Previous s-box to each array of plain text bytes. Note: only one S-BOX used.

11. Plain text Operation C) Third step rotate Row of plain text k bytes.

12. Plain text 0peration D) Last perform Mix columns: Matrix multiplication….for matrix, State is arranged into 4x4 matrix. This HEXA matrix multiplication is implemented over GALOIS FIELD.

13. One round Finally plaintext (substituted, rotate and mix columns ) XOR with KEY ( Expand, rotate, substitute, and xor with constant).