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Published byJewel Clark Modified over 8 years ago
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4.1 & 4.2 A Notes
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Type of ∆DefinitionPicture Equilateral Triangle CLASSIFICATION BY SIDES All sides are
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Type of ∆DefinitionPicture Isosceles Triangle CLASSIFICATION BY SIDES At least 2 sides base leg
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Type of ∆DefinitionPicture Scalene Triangle CLASSIFICATION BY SIDES No sides are
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Type of ∆DefinitionPicture Equiangular Triangle CLASSIFICATION BY ANGLES All angles are
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Type of ∆DefinitionPicture Acute Triangle CLASSIFICATION BY ANGLES All angles are acute
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Type of ∆DefinitionPicture Right Triangle CLASSIFICATION BY ANGLES One right angle leg hypotenuse
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Type of ∆DefinitionPicture Obtuse Triangle CLASSIFICATION BY ANGLES One obtuse angle and 2 acute angles
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Interior Angles –Angles inside a shape Exterior Angles –Angles outside a shape Corollary – Statement easily proved from another statement
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a c b a c b The sum of the measures of a triangle = _______ 180°
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If two triangles have two angles that are _______, then the third angle is also ___________. A B CD E F 40° 60° 80°
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The measure of an exterior angle of a triangle is equal to the sum of the measures of the two remote interior angles. a + b = 180° b + c + d = 180° b + c + d = a + b c + d = a
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The acute angles of a right triangle are ______________. complementary a c a + c + 90 = 180° a + c = 90°
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Classify the triangle by its sides and angles. scalene right
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Classify the triangle by its sides and angles. equilateral equiangular
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Classify the triangle by its sides and angles. isosceles obtuse
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4. Find the value of x. Then classify the triangle by its angles. x + 2x + 90 = 180 3x + 90 = 180 -90 -90 3x = 90 x = 30° 3 30° 60° right
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4. Find the value of x. Then classify the triangle by its angles. 2x + 3x + 55 = 180 5x + 55 = 180 -55 -55 5x = 125 x = 25° 5 50° 75° acute
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4. Find the value of x. Then classify the triangle by its angles. 180 – 50 – 70 =60° acute 60° 120°
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5. Find the measure of each exterior angle shown. x + 80 = 3x – 22 -x -x. 102 = 2x 51° = x 2 80 = 2x – 22 +22 +22 3(51) – 22 =131°
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5. Find the measure of each exterior angle shown. 2x + 103 – x = 6x – 7 -x -x. 110 = 5x 22° = x 5 103 = 5x – 7 +7 +7 x + 103 = 6x – 7 6(22) – 7 =125°
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6. Solve for the variables. 65° 180 - 90 – 65 = 25°
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6. Solve for the variables. 55° 5y + 55 + 70 = 180 5y + 125 = 180 -125 -125 5y = 55 y = 11° 5
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6. Solve for the variables. 4x + 2y = 56 5x + y = 34 34° –2 4x + 2y = 56 –10x – 2y = –68 –6x = –12 x = 2 4(2) + 2y = 56 8 + 2y = 56 2y = 48 y = 24
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7. Find the measure of each missing angle. 120° 60° 30° 60° 30°
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