1. THE HYPERBOLA

2. A hyperbola is the collection of all points in the plane the difference of whose distances from two fixed points, called the foci, is a constant. The hyperbola has two symmetric parts called branches. Each branch has a vertex and a focus. The axis that contains the vertices is called the transverse axis. This is the same definition as an ellipse except we have the difference is always constant instead of the sum.

3. PARTS OF A HYPERBOLA center foci conjugate axis vertices The black dashes lines are asymptotes for the graphs. transverse axis

4. The equation for a hyperbola can be derived by using the definition and the distance formula. It is derived in your book on pages 792-93. The resulting equation is: a a c b b This looks similar to the ellipse equation but notice the sign difference. To graph a hyperbola, make a rectangle that measures 2a by 2b as a sketching aid and draw the diagonals. These are the asymptotes.

5. Find the vertices and foci and graph the hyperbola: From the center the ends of the transverse axis are "a" each direction. "a" is the square root of this value The ends of the transverse axis are the vertices and the axis is 2a long. (-3, 0)(3, 0) a a From the center the ends of the conjugate axis are "b" each direction. "b" is the square root of this value b b Make a rectangle & draw diagonals for the asymptotes. To find the foci, they are "c" away from the center in each direction. Find "c" by the equation:

6. Let's find the equations of the asymptotes. What is the slope of this line? They are lines with y intercept of 0. (-3, 0)(3, 0) a a Can you see this would be b over a or in this case, up two, over three or 2/3? b b The second line has the same slope only negative. hint: rise over run

7. The center of the hyperbola may be transformed from the origin. The equation would then be: horizontal transverse axis vertical transverse axis The axis is determined by the first term NOT by which denominator is the largest. If the x term is positive it will be horizontal, if the y term is the positive term it will be vertical.

8. Find the center, foci, vertices and graph the ellipse complete the square on the x terms and then on the y terms We grouped the y terms and factored out a 4 and grouped the x terms and factored out a -3. The y squared term is first because it is positive. 1111 The right hand side must be a 1 so divide all terms by 12 12 3 4 1 This is now in standard form and we are ready to find what we need and graph (next screen)

9. The center is at (h, k). In this case (1, -1). a = square root 3 so the vertices (on the transverse axis) are square root of 3 each way from the center. Since it is the y term that is positive, we move square root of 3 each way in the y direction. this is b 2 so b = 2 (1, -1) this is a 2 so a = square root of 3 To find foci: So foci are: so vertices are: Make the rectangle and asymptotes to help you graph