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The Chinese University of Hong Kong The Chinese University of Hong Kong EDD 5161F Educational Communications and Technology Group 14.

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Presentation on theme: "The Chinese University of Hong Kong The Chinese University of Hong Kong EDD 5161F Educational Communications and Technology Group 14."— Presentation transcript:

1

2 The Chinese University of Hong Kong The Chinese University of Hong Kong EDD 5161F Educational Communications and Technology Group 14

3 Mathematics Target Audience: F.4 Science Students Duration: 2lessons Topic: Basic Properties of Circles

4 Basic Properties of Circles Angles in the semi-circle Angles in the semi-circle Angles in the semi-circle Angles in the semi-circle Angles in the same segment Angles in the same segment Angles in the same segment Angles in the same segment Basic terms of a circle Basic terms of a circle Basic terms of a circle Basic terms of a circle Angles at centre and circumference

5 I.Basic Terms of a Circle A B CD E O Chord Radius Diameter Arc Segment

6 II. Angles at centre and circumference y = 2x Reference:  at centre = 2  at circumference y x

7 Proof: m n x y x = 2m y = 2n x + y = 2 (m+n)  at centre = 2 (  at circumference)

8 Illustrative example: x yO Find x and y  at centre twice  at circumference

9 Quiz: y A. B. C. D. E. O Q.1

10 O x A. B. C. D. E. Q.2

11 III.Angle in the semi-circle Reference:  in the semi-circle A B C O 

12 Proof: O AB C  at centre twice  at circumference

13 Illustrative example: z O x  in the semi-circle ( base  s, isos  )

14 IV.Angle in the segment x = y Reference:  in the same segment x y

15 Proof: O x z y z = 2x  at centre twice  at circumference z = 2y  at centre twice  at circumference x = y

16 Illustrative example: A B C D y  in the same segment  in the semi-circle  sum of  O

17 Quiz: y x Find x and y  in the same segment Q.1

18 x A. B. C. D. E. Q.2

19 Revision on the properties of circles y x A B C O x y  in the same segment  in the semi-circle  at centre = 2  at circumference

20 THE END THE END

21 Prepared by Name Student No. Chan Chi Man Benjamin98040300 Wong Kwong Leung98118940 Chan Mei Ling97043700


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