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Geometry 10.5 Areas of Circles and Polygons Objectives Find the area of a circle and polygons To be able to solve problems with circles and polygons.

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Presentation on theme: "Geometry 10.5 Areas of Circles and Polygons Objectives Find the area of a circle and polygons To be able to solve problems with circles and polygons."— Presentation transcript:

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2 Geometry 10.5 Areas of Circles and Polygons

3 Objectives Find the area of a circle and polygons To be able to solve problems with circles and polygons

4 Area of a Circle The area of a circle is  times the square of the radius or A =  r 2.

5 Using the Area of a Circle Find the area of P. Solution: a. Use r = 8 in the area formula. A =  r 2 =  8 2 = 64   201.06  So, the area if 64 , or about 201.06 square inches.

6 Using the Area of a Circle Find the diameter of Z. Solution: Area of circle Z is 96 cm 2. A =  r 2 96=  r 2 96/  = r 2 30.56  r 2 5.53  r  The diameter of the circle is about 11.06 cm.

7 The Apothem The apothem (a) is the segment drawn from the center of the polygon to the midpoint of the side (and perpendicular to the side)

8 More... a G F E DC B A H Hexagon ABCDEF with center G radius GA apothem GH

9 Area of a regular polygon The area of a regular polygon is: A = ½ Pa Area Perimeter Perimeterapothem

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11 45-45-90

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15 1.Perimeter = 14+14+14 = 42 m 2.Apothem: “30-60-90” triangle = (7√3)/3 = 4.0 3.Area = ½ Pa = ½ * 14 * 3 * 4 = 84 m²

16 1.Perimeter = 15*4= 60 in 2.Apothem: “45-45-90” triangle = 7.5 in 3.Area = ½ Pa = ½ * 4*15*7.5 = 225 in²

17 Perimeter = 10*5= 50 m Apothem: “36-54-90” triangle = 5/tan 36 = 6.9 Area = ½ Pa = ½ * 50* 6.9 = 172.5 m² 1.Find central angle measure : 360/n = 360/ 5 = 72° 2.Apothem splits angle into halves 72/2 = 36 °

18 A = ½ Pa If a = 5√3, than we have 30-60-90 triangle so the side = 10 A = ½*6*10*5 √3 = 259.8cm²

19 A = ½ Pa If a = 7.5, and P = 54.49 A = ½*7.5 * 54.49 = 204.3 m²

20 A region = A square – A circle A square = 40*40 = 1600 A circle = 3.14*20² = 1256 A region = 1600-1256 = 344 m²

21 A region = A circle – A (2 smaller circles) A circle= 64*3.14 = 200.96 A one smaller circle = 16*3.14 = 50.24 A region = 200.96-2*50.24=100.5m²


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