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Mathematics Relations and Functions: Factoring Polynomials Science and Mathematics Education Research Group Supported by UBC Teaching and Learning Enhancement.

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Presentation on theme: "Mathematics Relations and Functions: Factoring Polynomials Science and Mathematics Education Research Group Supported by UBC Teaching and Learning Enhancement."— Presentation transcript:

1 Mathematics Relations and Functions: Factoring Polynomials Science and Mathematics Education Research Group Supported by UBC Teaching and Learning Enhancement Fund 2012-2015 Department of Curriculum and Pedagogy FACULTY OF EDUCATION a place of mind

2 Factoring Polynomials I Retrieved from http://catalog.flatworldknowledge.com/bookhub/reader/6329?e=fwk-redden-ch06_s01

3 Multiplying Polynomials I

4 Solution

5 Solution Cont’d

6 Factoring Polynomials II

7 Solution

8 Factoring Polynomials III

9 Solution

10 Solution Cont’d Retrieved from http://www.math10.ca/lessons/polynomials/greatestCommonFactor/greatestCommonFactor.php

11 Factoring Polynomials IV

12 Solution (x + ) ____ + ____ = b ____ × ____ = c

13 Solution Cont’d ____ + ____ = 5 ____ × ____ = -6 6 6

14 Factoring Polynomials V

15 Solution

16 Solution Cont’d In order to get two numbers that multiply into a negative number, these two numbers must have different sign (+,- or -, +) ! Then, for our two numbers, we have (+1, -6), (-1, +6), (+2, -3), or (-2, +3), However, when they are added, we get -6, 6, -1, or 1, respectively. Since our b is -7, we do not have any choice!. Notice that option E does add up to -7, but it multiples into +6. Thus, we have no solution, and this example cannot be factored further! ____ + ____ = -7 ____ × ____ = -6 ?? ? ?

17 Factoring Polynomials VI

18 Solution

19 Solution Cont’d In order to get two numbers that multiply into a positive number, these two numbers must have same sign (+,+ or -, -) ! Then, for our two numbers, we can have ± 6 and ±6, which must have identical signs (+6 with +6, -6 with -6). However, when they are added, we get +12 or – 12. Since our b is +12, our two numbers are +6 and +6. Then, our factored form will look like (x + 6) (x + 6). Notice that this answer can be written as a complete square form Our answer is E. ____ + ____ = +12 ____ × ____ = +36 66 6 6

20 Factoring Polynomials VII

21 Solution

22 Solution Cont’d In order to get two numbers that multiply into a positive number, these two numbers must have the same sign (+,+ or -, -) ! So, looking at the factors of 24, we can have ± 4 and ±6, which must have identical signs (+4 with +6, -4 with -6). However, when they are added together, we get +10 or – 10. Since our b is -10, our two numbers are -4 and -6. Then, our factored form will look like (x - 4)(x - 6). Multiplying with the GCF, we get 3(x - 4)(x - 6). Our answer is C. -4-6 -4 -6

23 Factoring Polynomials VIII

24 Solution 6 6 1 1

25 Solution Cont’d

26 Factoring Polynomials IX

27 Solution -30 4 4 Careful! It cannot be -6 and -20 (if we multiply them we get +120)

28 Solution Cont’d

29 Factoring Polynomials X

30 Solution ____ × ____ = 225 15

31 Solution Cont’d “Difference of squares ”

32 Factoring Polynomials XI

33 Solution

34 Factoring Polynomials XII

35 Solution

36 Solution Cont’d Retrieved from http://maths.nayland.school.nz/Year_11/AS1.2_Algebra_Methods/12_More_Factorising.htm


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