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Published byEsther Taylor Modified over 4 years ago

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Projectile Motion Projectiles launched at an angle

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Velocity in the x direction is constant Velocity in the y direction changes due to gravity

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vxvx vyvy v

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v x is constant, v y is equal and opposite at equal times from the highest point

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Velocity in the x direction v x = v i (cos ) vivi x = v i (cos ) t v x = x/ t

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vivi Velocity in the y direction v y = v i (sin ) v y = y/ t y = v i (sin ) t+1/2g t 2

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yy xx t y = v i (sin ) t +1/2g t 2

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1. I throw a basketball at an angle of 58° above the horizontal with a velocity of 24.36 m/s. What is the a) time it is in the air? b) distance it goes? and c) maximum height? a) y = v i (sin ) t + 1/2g( t) 2 = 0 t = -2v i (sin )/g = -2(24.36m/s)(sin58°)/-9.81m/s 2 = 4.21s b) x = v i (cos ) t = (24.36m/s)(cos58°)(4.21s) = 54.3m c) y max = v i (sin )(1/2) t + 1/2g(1/2 t) 2 = (24.36m/s)(sin58°)(2.105s) + 1/2g(2.105) 2 = 21.7m -9.81m/s 2

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