1. COMPLEX Z R O S

2. Complex zeros or roots of a polynomial could result from one of two types of factors: Type 1 Type 2 Notice that with either type, the complex zeros come in conjugate pairs. There are 2 complex solutions that have the same real term and opposite signs on imaginary term. This will always be the case. Complex zeros come in conjugate pairs.

3. So if asked to find a polynomial that has zeros, 2 and 1 – 3i, you would know another root would be 1 + 3i. Let’s find such a polynomial by putting the roots in factor form and multiplying them together. Multiply the last two factors together. All i terms should disappear when simplified. Now multiply the x – 2 through Here is a 3 rd degree polynomial with roots 2, 1 - 3i and 1 + 3i If x = the root then x - the root is the factor form.

4. Let’s take this polynomial and pretend we didn’t know the roots and work the other direction so we can see the relationship to everything we’ve learned here. 1, 2, 4, 5, 10, 20 1  Possible rational roots By Descartes Rule there are 3 or 1 positive real zeros (3 sign changes in f(x)) and no negative real roots (no sign changes in f(-x)). Let’s try 2 (synthetic division) 2 -4 20 2 1 -4 14 -20 1 -2 10 0 Now put variables back in and factor or use quadratic formula By quad formula: So there was one positive and two imaginary roots

5. Use the given root to find the remaining roots of the function Since 3i is a root we also know that its conjugate -3i is also a root. Let’s use synthetic division and reduce our polynomial by these roots then. 9i -27+15i -45-6i 18 3i 3 5 25 45 -18 3 5+9i -2+15i -6i 0 3 5 -2 0 -3i -9i -15i 6i 0 Put variables in here & set to 0 and factor or formula this to get remaining roots. So the roots of this function are 3i, -3i, 1/3, and -2

6. Acknowledgement I wish to thank Shawna Haider from Salt Lake Community College, Utah USA for her hard work in creating this PowerPoint. www.slcc.edu Shawna has kindly given permission for this resource to be downloaded from www.mathxtc.com and for it to be modified to suit the Western Australian Mathematics Curriculum.www.mathxtc.com Stephen Corcoran Head of Mathematics St Stephen’s School – Carramar www.ststephens.wa.edu.au