1. Advanced Higher Physics Unit 2 Electromagnetism

2. Magnetic Field A current carrying conductor exerts a magnetic field. The strength of this field is measured by magnetic induction (B). The unit of magnetic induction is the Tesla (T). The magnetic field around a wire is circular and the direction of the field is found using the left hand rule. I B

3. Relationship between force exerted on a conductor in a magnetic field and the current in the magnetic field.

4. Magnetic field and force If a current carrying conductor is inside a magnetic field then it experiences a force. l I B F=BIlsinθ θ Where: B is the magnetic induction in Tesla (T) l is the length of wire inside the field Θ is the angle between the field and the conductor. Note: The force is a maximum when the conductor is perpendicular to the field (θ=90˚) The force is 0 when the conductor is parallel to the field (θ=0˚). In data booklet

5. Definition of the tesla From, the tesla can be defined as: the magnetic induction (B=1T), of a magnetic field in which a conductor of length one metre (l=1m), carrying a current of one Ampere (I=1A) perpendicular to the field (θ=90˚,sin 90=0)is acted by a force of one Newton (F=1N).

6. Right hand rule I B F

7. Example A wire is suspended from a balance between the poles of a strong magnet of magnetic induction 84mT. The balance is set to 0. A current of 2.1 A is passed through the wire and the reading on the balance is 11mN. a)Calculate the angle between the Conductor and the magnetic field. b) State the direction of the force on the Wire. c) How can the wire be arranged to increase the force on it to a maximum? d) Calculate the maximum force on the conductor using the same current. e) What happens to the force on the wire when the direction of the 2.1 A current is reversed?

10. The Hall effect I B F V Hall Voltage

11. Magnetic induction along a straight wire

12. Magnetic Field due to an ‘infinite’ conductor When current passes: So with [permeability of free space] In data booklet

13. Example Determine the magnetic induction at a distance of 0.25 m from a wire carrying a current of 3.0 A. State any assumption made.

14. Force between two wires I1I1 I2I2 r wire 1 wire 2 B1B1 Wire 1 sets up a magnetic field: Wire 2 is in this magnetic field and experiences a force: F=B 1 I 2 l Using right hand rule gives direction of force. Now substituting gives: Using left hand rule, gives direction of magnetic Field B 1. Therefore: F In data booklet You need to be able to derive this !

15. By a similar argument it is easy to show that wire 1 experiences the same force per unit length. Note: If the currents are in the same direction then the force is attractive. If the currents are in opposite direction then the force is repelling.

16. Example A long straight conductor has a current of 3.0 A. This conductor is placed parallel to a short straight conductor of length 0.2 m which has a current of 2.5 A. The separation of the conductors is 0.15 m. 1.Calculate the magnetic induction, due to the long conductor, at midpoint M of the short conductor. 2.Calculate the approximate value for the force on the short conductor. 3.Why is this an approximate value for the force?