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Applications and Models: Growth and Decay

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1 Applications and Models: Growth and Decay
Section 4.6 Applications and Models: Growth and Decay

2 Population Growth The function P (t ) = P0e kt, k > 0 can model many kinds of population growths. In this function: P0 = population at time 0, P = population after time, t = amount of time, k = exponential growth rate. The growth rate unit must be the same as the time unit.

3 Example Population Growth of the United States.
In 1990 the population in the United States was about 249 million and the exponential growth rate was 8% per decade. (Source: U.S. Census Bureau) Find the exponential growth function. What will the population be in 2020? After how long will the population be double what it was in 1990?

4 Solution At t = 0 (1990), the population was about 249 million.
We substitute 249 for P0 and 0.08 for k to obtain the exponential growth function. In 2020, 3 decades later, t = 3. To find the population in 2020 we substitute 3 for t: The population will be approximately million in 2020.

5 Solution continued We are looking for the doubling time T.

6 Interest Compound Continuously
The function P (t ) = P0e kt can be used to calculate interest that is compounded continuously. In this function: P0 = amount of money invested, P = balance of the account, t = years, k = interest rate compounded continuously.

7 Example Suppose that $2000 is deposited into an IRA at an interest rate k, and grows to $ after 12 years. What is the interest rate? Find the exponential growth function. What will the balance be after the first 5 years? How long did it take the $2000 to double?

8 Solution At t = 0, P (0) = P0 = $2000. Thus the exponential growth function is

9 Solution continued

10 Solution continued The exponential growth function is
The balance after 5 years is

11 Solution continued

12 Growth Rate and Doubling Time
The growth rate k and the doubling time T are related by kT = ln 2 or * The relationship between k and T does not depend on P0.

13 Example A certain town’s population is doubling every 37.4 years.
What is the exponential growth rate? Solution:

14 Models of Limited Growth
In previous examples, we have modeled population growth. However, in some populations, there can be factors that prevent a population from exceeding some limiting value. One model of such growth is which is called a logistic function. This function increases toward a limiting value a as t approaches infinity. Thus, y = a is the horizontal asymptote of the graph.

15 Exponential Decay Decay, or decline, of a population is represented by the function P (t ) = P0e kt, k > 0. In this function: P0 = initial amount of the substance, P = amount of the substance left after time, t = time, k = decay rate. The half-life is the amount of time it takes for half of an amount of substance to decay.

16 Graphs

17 Example Carbon Dating. The radioactive element carbon-14 has a half-life of 5750 years. If a piece of charcoal that had lost 7.3% of its original amount of carbon, was discovered from an ancient campsite, how could the age of the charcoal be determined? Solution: The function for carbon dating is P (t ) = P0e t. If the charcoal has lost 7.3% of its carbon-14 from its initial amount P0, then 92.7%P0 is the amount present.

18 Example continued To find the age of the charcoal, we solve the equation for t :


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