AP Calculus Definite Integrals Review (sections 5.6-5.10)
Quiz Topics Fundamental Theorem of Calculus (section 5.6) Nderiv and FnInt on calculator Definite integral properties (section 5.7) Area using integrals (section 5.8) Example: Region bounded by y = -x^2 + 5 and y = -2x + 2 Volumes of solids (section 5.9)
Integral Properties If function values of f(x) are positive and the interval boundaries are increasing, the integral will be positive. If functional values of f(x) are negative (below x axis) and the interval boundaries are increasing, the integral will be negative. As a result, it is possible to have areas of positive and negative area “cancel,” resulting in an integral of 0.