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Oscillators fall CM lecture, week 4, 24.Oct.2002, Zita, TESC Review simple harmonic oscillators Examples and energy Damped harmonic motion Phase space.

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Presentation on theme: "Oscillators fall CM lecture, week 4, 24.Oct.2002, Zita, TESC Review simple harmonic oscillators Examples and energy Damped harmonic motion Phase space."— Presentation transcript:

1 Oscillators fall CM lecture, week 4, 24.Oct.2002, Zita, TESC Review simple harmonic oscillators Examples and energy Damped harmonic motion Phase space Resonance Nonlinear oscillations Nonsinusoidal drivers

2 Review Simple harmonic motion Mass on spring:  F = ma - k x = m x” - k x = - m  2 x Simple pendulum:  F = ma - mg sin  = m s” - g  = L  ” = -L  2  Solutions: x = A cost  t + B sin  t or x = C + e i  t + C - e -i  t v max =  A, a max =  2 A Potential energy: V = (1/2) k x 2. Ch.11: for any conservative force, F = -kx where k = V”(x 0 )

3 Energies in SHO (Simple Harmonic Oscillator)

4 LC circuit as a SHO Instead of  F = ma, use Kirchhoff’s loop law  V = 0. Find the voltage across a capacitor from C = Q/V c. The voltage across an inductor is V L = L dI/dt. Use I= - dQ/dt to write a diffeq for Q(t) (current flows as capacitor discharges): Show that Q(t) = Q 0 e -i  t is a solution. Find frequency  and I(t) Energy in capacitor = U E = (1/2) q V= (1/2) q 2 /C Energy in inductor = U B =(1/2) L I 2

5 Oscillations in LC circuit

6 Damped harmonic motion (3.4 p.84) First, watch simulation and predict behavior for various drag coefficients c. Model damping force proportional to velocity, F d = -cv:  F = ma - k x - cx’ = m x” Simplify equation: divide by m, insert  =  k/m and  = c/(2m): Guess a solution: x = A e t Sub in guessed x and solve resultant “characteristic equation” for. Use Euler’s identity: e i  = cos  + i sin  Superpose two linearly independent solutions: x = x 1 + x 2. Apply BC to find unknown coefficients.

7 Solutions to Damped HO: x = e  t (A 1 e qt +A 2 e -qt ) Two simply decay: critically damped (q=0) and overdamped (real q) One oscillates: UNDERDAMPED (q = imaginary). Predict and view: does frequency of oscillation change? Amplitude? Use (3.4.7) where   =  k/m Write q = i  d. Then  d =______ Show that x = e  t (A cos  d  t +A 2 sin  d  t) is a solution. Do Examples 3.4.2, 3.4.4 p.91. Setup Problem 9. p.129

8 Examples of Damped HO G.14.55 ( 385): A block of mass m oscillates on the end of spring of force constant k. The black moves in a fluid which offers a resistive force F= - bv. (a) Find the period of the motion. (b) What is the fractional decrease in amplitude per cycle? © Write x(t) if x=0 at t=0, and if x=0.1 m at t=1 s. Do this first in general, then for m = 0.75 kg, k = 0.5 N/m, b = 0.2 N.s/m.

9 RLC circuit as a DHO Capacitor: V c.=Q/C Inductor: V L = L dI/dt. Resistor: V R = IR Use I= - dQ/dt to write a diffeq for Q(t): Note the analogy to the diffeq for a mass on a spring! Inertia: Inductance || mass; Restoring: Cap || spring; Dissipation: Resistance || friction Don’t solve the diffeq all over again - just use the form of solution you found for mass on spring with damping! Solve for Q(t):

10 RLC circuit Ex: (G.30.8.p.766) At t=0, an inductor (L = 40 mH = milliHenry) is placed in series with a resistance R = 3  (ohms) and charged capacitor C = 5  F (microFarad). (a) Show that this series will oscillate. (b) Determine its frequency with and without the resistor. © What is the time for the charge amplitude to drop to half its starting value? (d) What is the amplitude of the current? (e) What value of R will make the circuit non-oscillating?

11 Driven HO and Resonance As in your DiffEq Appendix A, the solution to a nonhomogeneous differential equation m x” + c x’ + kx = F 0 e i  t has two parts: y(t) = y h (t) + y p (t) The solution y h (t) to the homogeneous equation (driver = F = 0) gives transient behavior (see phase diagrams). For the steady-state solution to the nonhomogeneous equation, guess y p (t) = A F 0 e i(  t-  ). Plug it into the diffeq and apply initial conditions to find A and . Show that the amplitude A (3.6.9) peaks at resonance (w r 2 = w 0 2 - 2  2 = w d 2 -  2 ) and levels out to the steady-state value in (3.16.13a) p.103. Set up Problem 3.10 p.129 if time.

12 Resonance


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