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1 Equilibrium 13911201....54 slideshttp:\\asadipour.kmu.ac.ir1

2 Equilibrium The Concept of Equilibrium As a system approaches equilibrium, both the forward and reverse reactions are occurring. At equilibrium, the forward and reverse reactions are proceeding at the same rate. 213911201....54 slideshttp:\\asadipour.kmu.ac.ir N 2 O 4 (g) 2 NO 2 (g)

3 Equilibrium A System at Equilibrium Once equilibrium is achieved, the amount of each reactant and product remains constant. 313911201....54 slideshttp:\\asadipour.kmu.ac.ir N 2 O 4 (g) 2 NO 2 (g)

4 Equilibrium 413911201....54 slideshttp:\\asadipour.kmu.ac.ir

5 Equilibrium The Equilibrium Constant Forward reaction: N 2 O 4 (g)  2 NO 2 (g) Rate law: Rate = k f [N 2 O 4 ] Reverse reaction: 2 NO 2 (g)  N 2 O 4 (g) Rate law: Rate = k r [NO 2 ] 2 513911201....54 slideshttp:\\asadipour.kmu.ac.ir N 2 O 4 (g) 2 NO 2 (g)

6 Equilibrium The Equilibrium Constant Therefore, at equilibrium Rate f = Rate r k f [N 2 O 4 ] = k r [NO 2 ] 2 Rewriting this, it becomes kfkrkfkr [NO 2 ] 2 [N 2 O 4 ] = 613911201....54 slideshttp:\\asadipour.kmu.ac.ir

7 Equilibrium Manipulating Equilibrium Constants 2NO 2 Cl(g)  2NO 2 (g)+Cl 2 (g) K eq =[NO 2 ] 2 [Cl 2 ]/[NO 2 Cl] 2 R=K[NO2Cl] 1=NO2Cl  NO2+Cl K1=[NO2][Cl]/[NO2Cl] 2=NO2Cl+Cl  NO2+Cl2 K2=[NO2][Cl2]/[NO2Cl][Cl] K=K1*K2=K eq =[NO 2 ] 2 [Cl 2 ]/[NO 2 Cl] 2 713911201....54 slideshttp:\\asadipour.kmu.ac.ir The equilibrium constant for a net reaction made up of two or more steps is the product of the equilibrium constants for the individual steps.

8 Equilibrium The Equilibrium Constant The ratio of the rate constants is a constant at that temperature, and the expression becomes K eq = kfkrkfkr [NO 2 ] 2 [N 2 O 4 ] = 813911201....54 slideshttp:\\asadipour.kmu.ac.ir N 2 O 4 (g) 2 NO 2 (g)

9 Equilibrium The Equilibrium Constant(K c ) To generalize this expression, consider the reaction The equilibrium expression for this reaction would be K c = [C] c [D] d [A] a [B] b aA + bBcC + dD 9 13911201....54 slideshttp:\\asadipour.kmu.ac.ir

10 Equilibrium The Concept of Equilibrium Chemical equilibrium occurs when a reaction and its reverse reaction proceed at the same rate. 1013911201....54 slideshttp:\\asadipour.kmu.ac.ir

11 Equilibrium What Are the Equilibrium Expressions for These Equilibria? 1113911201....54 slideshttp:\\asadipour.kmu.ac.ir

12 Equilibrium The Equilibrium Constant(K p ) Because pressure is proportional to concentration for gases in a closed system, the equilibrium expression can also be written K p = (P C ) c (P D ) d (P A ) a (P B ) b 1213911201....54 slideshttp:\\asadipour.kmu.ac.ir

13 Equilibrium Relationship between K c and K p From the ideal gas law we know that Rearranging it, we get PV = nRT P = RT nVnV 1313911201....54 slideshttp:\\asadipour.kmu.ac.ir

14 Equilibrium Relationship between K c and K p Plugging this into the expression for K p for each substance, the relationship between K c and K p becomes Where K p = K c (RT)  n  n = (moles of gaseous product) − (moles of gaseous reactant) 1413911201....54 slideshttp:\\asadipour.kmu.ac.ir

15 Equilibrium Equilibrium Can Be Reached from Either Direction As you can see, the ratio of [NO 2 ] 2 to [N 2 O 4 ] remains constant at this temperature no matter what the initial concentrations of NO 2 and N 2 O 4 are. 1513911201....54 slideshttp:\\asadipour.kmu.ac.ir N 2 O 4 (g) 2 NO 2 (g)

16 Equilibrium Equilibrium Can Be Reached from Either Direction This is the data from the last two trials from the table on the previous slide. 1613911201....54 slideshttp:\\asadipour.kmu.ac.ir

17 Equilibrium Equilibrium Can Be Reached from Either Direction It does not matter whether we start with N 2 and H 2 or whether we start with NH 3. We will have the same proportions of all three substances at equilibrium. 1713911201....54 slideshttp:\\asadipour.kmu.ac.ir

18 Equilibrium What Does the Value of K Mean? If K >> 1, the reaction is product-favored; product predominates at equilibrium. 1813911201....54 slideshttp:\\asadipour.kmu.ac.ir

19 Equilibrium What Does the Value of K Mean? If K >> 1, the reaction is product-favored; product predominates at equilibrium. If K << 1, the reaction is reactant-favored; reactant predominates at equilibrium. 1913911201....54 slideshttp:\\asadipour.kmu.ac.ir

20 Equilibrium K & Time of Equilibrium The size of K and the time required to reach equilibrium are not directly related! 13911201....54 slideshttp:\\asadipour.kmu.ac.ir20

21 Equilibrium 13911201....54 slideshttp:\\asadipour.kmu.ac.ir21

22 Equilibrium Manipulating Equilibrium Constants The equilibrium constant of a reaction in the reverse reaction is the reciprocal of the equilibrium constant of the forward reaction. 1 0.212 = K c = = 0.212 at 100  C [NO 2 ] 2 [N 2 O 4 ] N2O4 (g)N2O4 (g) 2 NO 2 (g) K c = = 4.72 at 100  C [N 2 O 4 ] [NO 2 ] 2 N2O4 (g)N2O4 (g) 2 NO 2 (g) 2213911201....54 slideshttp:\\asadipour.kmu.ac.ir

23 Equilibrium Manipulating Equilibrium Constants The equilibrium constant of a reaction that has been multiplied by a number is the equilibrium constant raised to a power that is equal to that number. K c = = 0.212 at 100  C [NO 2 ] 2 [N 2 O 4 ] N2O4 (g)N2O4 (g) 2 NO 2 (g) K c = = (0.212) 2 at 100  C [NO 2 ] 4 [N 2 O 4 ] 2 2 N 2 O 4 (g) 4 NO 2 (g) 2313911201....54 slideshttp:\\asadipour.kmu.ac.ir

24 Equilibrium The Concentrations of Solids and Liquids Are Essentially Constant Therefore, the concentrations of solids and liquids do not appear in the equilibrium expression K c = [Pb 2+ ] [Cl − ] 2 PbCl 2 (s) Pb 2+ (aq) + 2 Cl − (aq) 2413911201....54 slideshttp:\\asadipour.kmu.ac.ir

25 Equilibrium As long as some CaCO 3 or CaO remain in the system, the amount of CO 2 above the solid will remain the same. CaCO 3 (s) CO 2 (g) + CaO (s) 2513911201....54 slideshttp:\\asadipour.kmu.ac.ir K = [CO 2 ]

26 Equilibrium Homogeneous Equilibria Homogeneous equilibria are equilibria in which all substances are in the same state. N 2(g) + 3H 2(g)  2NH 3(g) H 2(g) + F 2(g)  2HF (g) 2613911201....54 slideshttp:\\asadipour.kmu.ac.ir

27 Equilibrium Heterogeneous Equilibria Write equilibrium expressions for the following: 2HOH (l)  2H 2(g) + O 2(g) 2HOH (g)  2H 2(g) + O 2(g) K = [H 2 ] 2 [O 2 ] 2713911201....54 slideshttp:\\asadipour.kmu.ac.ir CuSO 4. 5 HOH (s)  CuSO 4(s) + 5HOH (g) K = [HOH] 5

28 Equilibrium 2813911201....54 slideshttp:\\asadipour.kmu.ac.ir

29 Equilibrium Equilibrium Calculations A closed system initially containing 1.000 x 10 −3 M H 2 and 2.000 x 10 −3 M I 2 At 448  C is allowed to reach equilibrium. Analysis of the equilibrium mixture shows that the concentration of HI is 1.87 x 10 −3 M. Calculate K c at 448  C for the reaction taking place, which is H 2 (g) + I 2 (g) 2 HI (g) 2913911201....54 slideshttp:\\asadipour.kmu.ac.ir

30 Equilibrium What Do We Know? [H 2 ], M[I 2 ], M[HI], M Initially1.000 x 10 -3 2.000 x 10 -3 0 Change At equilibrium 1.87 x 10 -3 3013911201....54 slideshttp:\\asadipour.kmu.ac.ir

31 Equilibrium [HI] Increases by 1.87 x 10 -3 M [H 2 ], M[I 2 ], M[HI], M Initially1.000 x 10 -3 2.000 x 10 -3 0 Change+1.87 x 10 -3 At equilibrium 1.87 x 10 -3 3113911201....54 slideshttp:\\asadipour.kmu.ac.ir

32 Equilibrium Stoichiometry tells us [H 2 ] and [I 2 ] decrease by half as much [H 2 ], M[I 2 ], M[HI], M Initially1.000 x 10 -3 2.000 x 10 -3 0 Change-9.35 x 10 -4 +1.87 x 10 -3 At equilibrium 1.87 x 10 -3 3213911201....54 slideshttp:\\asadipour.kmu.ac.ir

33 Equilibrium We can now calculate the equilibrium concentrations of all three compounds… [H 2 ], M[I 2 ], M[HI], M Initially1.000 x 10 -3 2.000 x 10 -3 0 Change-9.35 x 10 -4 +1.87 x 10 -3 At equilibrium 6.5 x 10 -5 1.065 x 10 -3 1.87 x 10 -3 3313911201....54 slideshttp:\\asadipour.kmu.ac.ir

34 Equilibrium …and, therefore, the equilibrium constant Kc =Kc = [HI] 2 [H 2 ] [I 2 ] = 51 = (1.87 x 10 -3 ) 2 (6.5 x 10 -5 )(1.065 x 10 -3 ) 3413911201....54 slideshttp:\\asadipour.kmu.ac.ir

35 Equilibrium 13911201....54 slideshttp:\\asadipour.kmu.ac.ir35

36 Equilibrium The Reaction Quotient (Q) To calculate Q, one substitutes the initial concentrations on reactants and products into the equilibrium expression. Q gives the same ratio the equilibrium expression gives, but for a system that is not at equilibrium. 3613911201....54 slideshttp:\\asadipour.kmu.ac.ir

37 Equilibrium If Q = K, Q>K & Q<K 3713911201....54 slideshttp:\\asadipour.kmu.ac.ir

38 Equilibrium 3813911201....54 slideshttp:\\asadipour.kmu.ac.ir

39 Equilibrium Le Châtelier’s Principle “If a system at equilibrium is disturbed by a change in temperature, pressure, or the concentration of one of the components, the system will shift its equilibrium position so as to counteract the effect of the disturbance.” 3913911201....54 slideshttp:\\asadipour.kmu.ac.ir

40 Equilibrium Effects of Changes on the System 1.Concentration : The system will shift away from the added component. 2.Temperature : K will change depending on the endothermic or exothermic reactions. 3.Pressure : a. Addition of inert gas b. Decreasing the volume 4013911201....54 slideshttp:\\asadipour.kmu.ac.ir does not affect the equilibrium position. shifts the equilibrium toward the side with fewer gaseous molecules.

41 Equilibrium Production of NH 3 If H 2 is added to the system, N 2 will be consumed and the two reagents will form more NH 3. 4113911201....54 slideshttp:\\asadipour.kmu.ac.ir N 2(g) + 3H 2(g)  2NH 3(g)

42 Equilibrium Effect of Changes in Concentration on Equilibrium The addition of 1.000 M N 2 in position I → the position II 4213911201....54 slideshttp:\\asadipour.kmu.ac.ir N 2(g) + 3H 2(g)  2NH 3(g) position I 0.399M 1.197 M 0.203 M 1.348 M 1.044 M 0.304 M position II = 0.0602

43 Equilibrium Changes in Concentration Predict the effect of the changes listed to this equilbrium: As 4 O 6(s) + 6C (s)  As 4(g) + 6CO (g) a) addition of carbon monoxide b) addition or removal of C (s) or As 4 O 6(s) c) removal of As 4(g) a) left b) none c) right 4313911201....54 slideshttp:\\asadipour.kmu.ac.ir

44 Equilibrium 13911201....54 slideshttp:\\asadipour.kmu.ac.ir44

45 Equilibrium The Effect of Container Volume on Equilibrium If the size of a container is changed, the concentration of the gases change. N 2(g) + 3H 2(g)  2NH 3(g). A smaller container shifts to the right Four gaseous molecules produce two gaseous molecules. A larger container shifts to the left two gaseous molecules produce four gaseous molecules. 4513911201....54 slideshttp:\\asadipour.kmu.ac.ir

46 Equilibrium The Effect of Container Volume on Equilibrium Predict the direction of shift for the following equilibrium systems when the volume is reduced: a) P 4(s) + 6Cl 2(g)  4PCl 3(l) b) PCl 3(g) + Cl 2(g)  PCl 5(g) c) PCl 3(g) + 3NH 3(g)  P(NH 2 ) 3(g) + 3HCl (g) a) right b) right c) none 4613911201....54 slideshttp:\\asadipour.kmu.ac.ir

47 Equilibrium The Effect of Changes in Pressure CaCO 3 (s)  CaO(s) + CO 2 (g) 4713911201....54 slideshttp:\\asadipour.kmu.ac.ir

48 Equilibrium The system of N 2, H 2, and NH 3 are initially at equilibrium. When the volume is decreased, the system shifts to the right -- toward fewer molecules. 4813911201....54 slideshttp:\\asadipour.kmu.ac.ir N 2(g) + 3H 2(g)  2NH 3(g)

49 Equilibrium Effect of Temperature on Equilbirum For an exothermic reaction, if the temperature increases, K decreases. N 2(g) + 3H 2(g)  2NH 3(g) + 92 kJ For an endothermic reaction, if the temperature increases, K increases. CaCO 3(s) + 556 kJ  CaO (s) + CO 2(g) 4913911201....54 slideshttp:\\asadipour.kmu.ac.ir

50 Equilibrium The Effect of Changes in Temperature Q+Co(H 2 O) 6 2+ (aq) + 4 Cl (aq) CoCl 4 (aq) + 6 H 2 O (l) 5013911201....54 slideshttp:\\asadipour.kmu.ac.ir +Q-Q

51 Equilibrium 5113911201....54 slideshttp:\\asadipour.kmu.ac.ir

52 Equilibrium Catalysts increase the rate of both the forward and reverse reactions. 5213911201....54 slideshttp:\\asadipour.kmu.ac.ir Equilibrium is achieved faster, but the equilibrium composition remains unaltered.

53 Equilibrium The Haber Process This apparatus helps push the equilibrium to the right by 5313911201....54 slideshttp:\\asadipour.kmu.ac.ir N 2(g) + 3H 2(g)  2NH 3(g) + 92 kJ 1 6 5 4 3 2 7 9 8 Heating Catalyzing Cooling Pressure Refrigerating Removing

54 Equilibrium Offer to U 13911201....54 slideshttp:\\asadipour.kmu.ac.ir54


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