 # Special Ratios Similar Figures: Scale Factor Ratio of Perimeters

## Presentation on theme: "Special Ratios Similar Figures: Scale Factor Ratio of Perimeters"— Presentation transcript:

Special Ratios Similar Figures: Scale Factor Ratio of Perimeters
Ratio of Areas

What is the scale factor for the similar parallelograms?
Solve for x in the pair of similar triangles. 16 8 15 30 25 x 12 30

Special Ratios in Similar Figures
3 5 6 10 Scale Factor: Ratio of the perimeters = Scale Factor OR OR OR

12 : 22 15 : 60 1 : 4 b a Area Ratio Scale Factor 6 3 5 10
15 : 60 Ratio of Areas Simplify 1 : 4

Area Ratio is 32 : 52 9 : 25 Area Ratio Example
Given the Scale Factor is 3 : 5 Area Ratio is 32 : 52 9 : 25

Example 1 The two rectangles are similar. a. Find their scale factor.
Use one pair of corresponding sides and simplify the ratio. The scale factor is 2 : 3. b. Find the ratio of their perimeters. This is the same as the scale factor or 2 : 3 c. Find the ratio of their areas. Square the scale factor or 4 : 9

Example 2 The similar figures above have a scale factor 3 : 4. The smaller figure has a perimeter of 15 inches. Find the perimeter of the larger figure. Ratio of perimeters is the same as the scale factor : 4 Write a proportion. Use cross products to solve x = 60 x = 20 The larger figure has a perimeter of 20 inches.

Example 3 The similar octagons above have a scale factor 2 : 5.
a. Find the ratio of their areas. Square the scale factor : 52 → 4 : 25 b. The larger figure has an area of 100 ft2. Find the area of the smaller figure. Write a proportion. Use cross products to solve x = 400 x = 16 The smaller octagon has an area of 16 ft2.

Example 4ab Two similar paintings have perimeters of 20 in and 40 in.
a. Find the scale factor. The scale factor is the same or 1 : 2 as the ratio of perimeters. b. Find the ratio of the areas. Square the scale factor : 22 → 1 : 4

Example 4c Two similar paintings have perimeters of 20 in and 40 in.
The ratio of their areas is 1: 4. c. The smaller area is 24 in2. Find the larger area. Write a proportion using the ratio of the areas. Use cross products to solve x = 96 The larger area is 96 in2.

Exit Problems Use the similar hexagons below.
Find their scale factor. Find the ratio of their perimeters. Find the ratio of their areas. Two similar triangles have perimeters of 12 m and 60 m 18 12

Communication Prompt Dylan has two similar trees in his backyard. One tree is twice as tall as the other. Suppose the trees were cut down in corresponding places. Each stump had a shape of a circle at its top. Is the area of the larger circle twice as big as the area of the smaller stump’s circle? Why or why not?

Special Ratios for Similar Figures
Lesson 10 Proportionality Special Ratios for Similar Figures

Special Ratios for Similar Figures
If two figures are similar and the ratio of their sides simplifies to a :b, then: The scale factor is a :b The ratio of the perimeters is a :b The ratio of the areas is a2:b2