1. 15 Aug 20111 Visual Basic for Applications Programming language Very similar to Visual Basic Embedded in Microsoft Office applications “Object oriented” Automate Office operations Build macros and functions We will only learn enough VBA to write simple functions

2. 15 Aug 20112 Program Program = code call = run = execute = launch = start List of instructions Input Got at program’s start Asked to the user Got from Excel table Does some predetermined operations Output Written in Debug window or Message Box Written in Excel table “returned” like Excel functions

3. 15 Aug 20113 Variables Memory places to store values Types Integer numbers: Integer and Long Real number: Single and Double Dates: Date True/False: Boolean Sentences: String

4. 15 Aug 20114 Ask user values of x and y and print x+y Variables: x Single, y Single, z Single Example Start sub example1 Get value from user and store in x (Single) Get value from user and store in y (Single) Calculate x+y and store in z (Single) Print value of z End

5. 15 Aug 20115 Ask user values of x and y, calculate x+y, ask user for integer value a and print (x+y)*a Variables: x Single, y Single, z Single, a Integer, result Single Example Get value from user and store in a (Integer) Print value of result End Calculate z*a and store in result (Single) Start sub example2 Get value from user and store in x (Single) Get value from user and store in y (Single) Calculate x+y and store in z (Single)

6. 15 Aug 20116 Why should we rewrite a program that we have already written? We can give the subroutine a name, MySum, to be able to later reuse it. This reusable subroutine may have parameters, used to “communicate” with the other programs Reusing programs End Start subroutine MySum parameters: z (Single) Get value from user and store in x (Single) Get value from user and store in y (Single) Calculate x+y and store in z

7. 15 Aug 20117 We “call” the subroutine MySum inside the main program and use its parameter Reusing programs Get value from user and store in a (Integer) Print value of result End Calculate z*a and store in result (Single) Start sub example2bis Call MySum(z) z(Single) End Start subroutine MySum parameters: z (Single) Get value from user and store in x (Single) Get value from user and store in y (Single) Calculate x+y and store in z

8. 15 Aug 20118 We could use the subroutine also to get the values only and leave the calculation to the main program Reusing programs Get value from user and store in a (Integer) Print value of result End Calculate z*a and store in result (Single) Start sub example2ter Call GetXY(x,y) x(Single), y(Single) End Start subroutine GetXY parameters: x (Single), y (Single) Get value from user and store in x Get value from user and store in y Calculate x+y and store in z (Single)

9. 15 Aug 20119 Homeworks Write a program which asks for a an amount of money, an interest rate and a number of years and prints the compound interest Rewrite the previous program using a separate subroutine GetData to get the data. Rewrite the previous program using also a separate subroutine PrintInterest to print the compound interest. Rewrite the previous program using a sub called main which does nothing else but calling subroutines GetData, CalculateInterest, PrintInterest, which do all the job. Write a program which asks for a an amount of money, an interest rate and two dates StartDate and EndDate. Using the expression NumberOfYears = DateDiff( “yyyy”, StartDate, EndDate ) to get the difference in years, re-use the previous subroutines CalculateInterest and PrintInterest to print the compound interest.

10. 15 Aug 201110 IF-THEN-ELSE condition We want to branch the flow according to the value of a variable If (condition) Then (operations if true) Else (operations if false) End If

11. 15 Aug 201111 Start with already values for x (Single) and y (Single). If x<y, print y-x, else print sentence “sorry” Variables: x Single, y Single, diff Single, sentence String Example Start with x (Single), y (Single) Print value of diff Calculate y-x and store in diff (Single) Put “sorry” in sentence (String) Print value of sentence End true false x < y

12. 15 Aug 201112 Ask integer value. If it is positive, print “positive”, if it is not positive, ask for a real value and print it Variables: x Integer, y Single, sentence String Example Start Print value of y Put “positive” in sentence (String) Print value of sentence End true x > 0 false Get value from user and store in x (Integer) Get value from user and store in y (Single)

13. 15 Aug 201113 Build sub example5 which asks for an integer value. If it is positive, it prints “positive”. If it is negative, it asks for a real value and prints it. If it is zero it does nothing. Variables: x Integer, y Single, sentence String Example Start Put “positive” in sentence (String) Print value of sentence End Print value of y true x > 0 false Get value from user and store in x (Integer) Get value from user and store in y (Single) true false x < 0

14. 15 Aug 201114 Suppose there are two taxation systems, A and B. Build sub CalculateTax with flowchart which asks for the chosen taxation system and for the income and then prints the tax according to the rule: Class exercise SystemIncome levelTax A< 200003000 >=2000015% of income B<500009000 >=5000020% of income

15. 15 Aug 201115 Solution of class exercise Start sub CalculateTax tax (Double) End Print value of tax false system = “A” true Get value from user and store in system (String) true false income < 20000 Get value from user and store in income (Long) tax=3000tax=income*0.15 true false income < 50000 tax=9000tax=income*0.2 Use operator & to concatenate strings: ”result is ” & tax

16. 15 Aug 201116 In order to help subroutine CalculateTax, use a subroutine DoCalc which needs income, income level, fixed tax, tax percentage and calculates the tax. Improvement

17. 15 Aug 2011 17 Solution of improvement Start sub CalculateTax tax (Double) End Print value of tax false system = “A” true Get value from user and store in system (String) Get value from user and store in income (Long) End Start subroutine DoCalc parameters: income (Long), incomeLevel (Long), fixedTax (Long), taxPercentage (Single), tax (Double) tax=fixedTax tax=income*taxPercentage true false income < incomeLevel Call DoCalc(income, 20000,3000,0.15,tax) Call DoCalc(income, 50000,9000,0.2,tax)

18. 15 Aug 201118 Whenever a subroutine 1.does not interact with the user 2.gets its input from the parameters 3.returns only one variable as output it is much more efficient to use a function instead of a subroutine Function calcTax2( … parameters … ) as Single … do the calculations here and put the result in a variable with the same name as the function … End Function Function

19. 15 Aug 2011 19 Function Start sub CalculateTax tax (Double) End Print value of tax false system = “A” true Get value from user and store in system (String) Get value from user and store in income (Long) End returning calcTax Start function calcTax (Double) parameters: income (Long), incomeLevel (Long), fixedTax (Long), taxPercentage (Single) calcTax=fixedTax calcTax=income*taxPercentage true false income < incomeLevel tax=calcTax(income, 20000,3000,0.15) tax=calcTax(income, 50000,9000,0.2)

20. Print value of calcTax(income, 20000,3000,0.15) 15 Aug 201120 Functions are much more versatile and can be used directly in calculations and other functions or commands Usage of functions Start sub CalculateTax tax (Double) Print value of calcTax(income, 50000,9000,0.2) false system = “A” true Get value from user and store in system (String) Get value from user and store in income (Long) End

21. 15 Aug 201121 Homeworks Write a program with flowchart which asks for a an amount of money, an interest rate and two dates StartDate and EndDate. Using a function to calculate the compound interest and a subroutine to get the data, print the compound interest. Write function TaxDeduction (flowchart is too long) which gets as input children, income and age and returns the Italian tax deduction according to: Children Age of youngest child Deduction 1 below 3 years900 · (95,000 – income) / 95,000 3 years and more800 · (95,000 – income) / 95,000 2 below 3 years900 · (110,000 – income) / 110,000 3 years and more800 · (110,000 – income) / 110,000 3 below 3 years900 · (125,000 – income) / 125,000 3 years and more800 · (125,000 – income) / 125,000 4 below 3 years1,100 · (140,000 – income) / 140,000 3 years and more1,000 · (140,000 – income) / 140,000 more than 4Same formulas as above but 140,000 is increased by 15,000 for every child after the fourth. Important: when the deduction is negative, it becomes 0.

22. 15 Aug 201122 Write the squares of the numbers from 1 to 20 Example Start Set n (Integer) to 1 Print value of y Calculate n*n and store value in y (Long) Increment n by 1 Print value of y Calculate n*n and store value in y Increment n by 1 End

23. 15 Aug 201123 FOR-NEXT loop We want to repeat the same procedure in a similar way several times FOR : SET UP A COUNTER (operations) NEXT : INCREMENT AND GO BACK To go out of the loop before its end: EXIT FOR

24. 15 Aug 201124 Write the squares of the numbers from 1 to 20 Variables: n Integer, y Long Example6 Start Set n (Integer) to 1 and loop Print value of y End Calculate n*n and store value in y (Long) Increment n by 1 and loop until n does not exceed 20

25. 15 Aug 201125 Write the square root of the numbers from 3126 to 1087 going backwards with steps of 31 Variables: n Integer, y Long Example7 Start Set n (Integer) to 3126 and loop Print value of y End Calculate sqr(n) and store value in y (Single) Increment n by -31 and loop until n does not go below 1087

26. 15 Aug 201126 Write the square root of the numbers from 3126 to 1087 going backwards with steps of 31, asking the user at each step whether he wants the program to end. Example7bis Start Set n (Integer) to 3126 and loop Print value of y End Calculate sqr(n) and store value in y (Single) Increment n by -31 and loop until n does not go below 1087 truefalse goon =“yes” Get value from user and store in goon goon (String) Exit For

27. 15 Aug 201127 Homework Write function isEven with flowchart, which wants an integer as input and returns a Boolean (a variable with value True or False, without quotations!). To detect whether a number is even, use as condition Int(number/2)=number/2. Write a program with flowchart which asks the user for a positive integer and computes the following sequence for 20 times: if the number is even, halve it; if it's odd, multiply by 3 and add 1. Repeat this process until 20 times have been reached or until the value is 1, printing out each value. Finally print out how many of these operations have been performed. Typical output might be: initial value is 9; next values are: 28, 14, 7, 22, 11, 34, 17, 52, 26, 13, 40, 20, 10, 5, 16, 8, 4, 2, 1; number of steps 19

28. 15 Aug 201128 Using functions A function may be used: by a subroutine (or by another function), via direct usage such as variable=functionName(parameters), where the subroutine is responsible for providing the parameters inside an Excel sheet, exactly like any other Excel function, where parameters are written directly or indicated as cell reference, such as =functionName(D7;E5;27;0;A1) Not run directly via Run button, since there is no way to pass parameters and no way to gather the function’s returned output

29. 15 Aug 201129 Reading data from Excel sheet To access Excel sheet we use Range(“E2:H9”).Cells(3,2) which corresponds to cell F4, since (3,2) are the row and column of the range! Therefore E2 is (1,1), F2 is (1,2), F3 is (2,2) and F4 is (3,2). Range(“E2:H9”).Count which tells us the number of cells in the range (in this case 32)

30. 15 Aug 201130 Example Write program Multiplic which reads number in cell D5, multiplies it by the number in cell D6 and prints the result. Compact it using a single instruction. Start End a (Single) a= Range(“D5”).Cells(1,1) Print value of a*b a = Range(“D1:D20”).Cells(5,1) b = Range(“D5:D6”).Cells(2,1) b (Single) b= Range(“D6”).Cells(1,1)

31. 15 Aug 201131 Example Write program FixCell which asks the user for a cell reference and a real number and puts that number in that cell. Start End get a string from user and store it in cellReference (String) Range(cellReference).Cells(1,1)=value get a single from user and store it in value (Single)

32. 15 Aug 201132 Array We want to store many values of the same type ARRAY It always needs to be prepared It is accessed directly indicating the index 12345678910111213141516

33. 15 Aug 201133 Ask the user 20 real numbers and store them into an array. Ask the user which value he wants to be printed and print it. Variables: x Array of Single, j Integer, n Integer Example11 Start Print value in n-th position of x Get value from user and store in n (Integer) End Set j (Integer) to 1 and loop Prepare an array x containing 20 single Get value from user and store in j-th position of x Increment j by 1 and loop until j exceeds 20

34. 15 Aug 201134 Ask the user 20 real values. When you have all of them, calculate their sum. Then print it. Variables: x Array of Single, j Integer, sum Single Example11bis Start Print value of sum End Set j (Integer) to 1 and loop Prepare an array x containing 20 single Get value from user and store in j-th position of x Increment j by 1 and loop until j exceeds 20 sum (Single) sum = 0 j=1 and loop Increment j by 1 and loop until j exceeds 20 sum = sum + x (at j-th position)

35. 15 Aug 201135 Improve the previous program using only one loop and telling each time which number the user is entering (4 th, 5 th, …) Improve it further more using 1 st, 2 nd, 3 rd instead of 1 th, 2 th, 3 th and do not use an array! Example11ter

36. 15 Aug 201136 Example15 Read numbers in range D3:D13 and put them in array x with indexes 1 to 11. Then print the fifth element of the array Start End Set j (Integer) to 1 and loop Increment j by 1 and loop until j exceeds 11 x array of Single 1 To 11 x(j)= Range(“D3:D13).Cells(j,1) Print value of x(5) For j=3 To 13 x(j–2)=Range(“D1:D13”).Cells(j,1) For j=1 To 11 x(j)=Range(“D1:D13”).Cells(j+2,1)

37. 15 Aug 2011 37 Get 20 values from D1:D20 and put them into an array. When you have all of them, ask the user for a bound. Then print how many of the 20 values exceed that bound. Example12 Start Print value of count End Set j (Integer) to 1 and loop Prepare an array x containing 20 single x(j)=Range(“D1:D20”).Cells(j,1) Increment j by 1 and loop until j exceeds 20 count (Integer) count= 0 j=1 and loop Increment j by 1 and loop until j exceeds 20 count = count+1 Get value from user and store in bound (Single) truefalse x(j) > bound

38. 15 Aug 201138 Whenever we are not sure of from where to where the array index goes, we can use functions LBound(x) and UBound(x) which automatically take the value of the first and the last index of the array x Rewrite the previous program using LBound(x) and UBound(x) instead of 1 and 20 LBound and UBound

39. 15 Aug 201139 Build a function countLargerThanLimit which accepts as input an array of singles and a limit and returns how many elements of the array are larger than the limit In this function you must use LBound and UBound because the function cannot know a priori the array bounds Example12ter

40. 15 Aug 201140 Ask the user 20 real numbers. When you have all of them, calculate the average of the positive ones. Then print it. Hints First build a program which simply calculates the average Use count (Integer) variable to count how many are positive Start setting count=0 (exactly as sum is set equal to 0) Use IF-THEN-ELSE condition to check whether each number is positive (and therefore should be summed and counted) Example13

41. 15 Aug 201141 Solution Start Print value of average End Set j (Integer) to 1 and loop Prepare an array x containing 20 single Get value from user and store in j-th position of x Increment j by 1 and loop until j exceeds 20 sum (Single) sum = 0 j=1 and loop Increment j by 1 and loop until j exceeds 20 sum = sum + x(j) average (Single) average = sum / count count (Integer) count = 0 count = count + 1 true x(j)>0 false

42. 15 Aug 201142 What happens when all 20 values are negative? The computer crashes since a division by zero was found! We need to check that count be positive before dividing! Problem of the solution

43. 15 Aug 201143 Better solution Start Print value of average End Set j (Integer) to 1 and loop Prepare an array x containing 20 single Get value from user and store in j-th position of x Increment j by 1 and loop until j exceeds 20 sum (Single) sum = 0 j=1 and loop Increment j by 1 and loop until j exceeds 20 sum = sum + x(j) average (Single) average = sum / count count (Integer) count = 0 count = count + 1 true x(j)>0 false true count>0 false Print value of sentence sentence (String) sentence = “sorry no positive”

44. 15 Aug 201144 Build a function which receives d (array of 20 Date), m (Single) and r (array of 20 Single). For each d and r, if d is in the past and r is positive, calculate the interest from d to now, using m as money amount and the corresponding r as interest rate. Otherwise, do not consider this data. Return the average of the calculated interests. Hints You can use And operator (like in Access) To get current date, there is Now() function Write also a program which reads the data from columns G, H, I of Excel sheet and tests the function. Homework (example 14)

45. 15 Aug 201145 Solution sum (Single) sum = 0 Start with d (array of 20 Date), m (Single), r (array of 20 Single) count (Int) count = 0 End returning average Set j (Integer) to 1 and loop Increment j by 1 and loop until j exceeds 20 false true d(j)<Now() And r(j)>0 count = count +1interest (Single) interest = m * ( 1+r(j) ) (Now – d(j)) / 365 – m sum = sum + interest Starting variables: d (array of 20 Date) m (Single) r (array of 20 Single) Used variables: interest (Single) count (Integer) sum (Single) average (Single) average = sum / count

46. 15 Aug 201146 Homework Build function MaxOfArray which receives an array of singles and returns the maximum Hint: try to think at how would you do this task manually step by step and then replicate it on a program Build a subroutine to test the function, using the data in column D

47. 15 Aug 201147 Solution Start function MaxOfArray Parameters: x array of Single End returning maxCandidate Set j (Integer) to second index of array and loop maxCandidate (Single) maxCandidate=first element of array Increment j by 1 and loop until j exceeds the last index of the array maxCandidate = x(j) true x(j)> maxCandidate false

48. 15 Aug 201148 WHILE-WEND loop We want to repeat the same procedure in the same way until something happens WHILE : (condition) (operations) WEND : GO BACK

49. 15 Aug 201149 Ask the user a real value. If it is negative, print “bye” and stop. If it is positive or zero, tell the user its square root and ask another. Go on over and over. Variables: y Single, squareroot Single, sentence String Example16 StartEnd While y >=0 Print value of squareroot go back Get value from user and store in y (Single) Calculate sqr(y) and store in squareroot (Single) Get value from user and store in y Print value of sentence sentence (String) sentence = “bye”

50. 15 Aug 201150 Do not use WHILE- WEND loop but use IF instead. You need to “jump” to another place in the program and it is not possible (for the moment) Variables: y Single, squareroot Single, sentence String Equivalent example StartEnd Print value of squareroot Get value from user and store in y (Single) Calculate sqr(y) and store in squareroot (Single) Get value from user and store in y true y >= 0 false Print value of sentence sentence (String) sentence = “bye”

51. 15 Aug 201151 Build a function which receives x (array of Single). It goes through each value of x calculating the sum of the values, stopping when a zero value is found. Then it returns the sum. Hints The loop can end for two reasons: a zero value is found or all 30 values have been examined You can use the FOR-NEXT loop, but in this case you must add a condition which “jumps” to the end of the program when a zero is found You can instead use the WHILE-WEND loop, but in this case you must add a manual counter to go through x which takes care of ending when it reaches 30 Build a sub which takes data from column D to test the function Homework (example17)

52. 15 Aug 201152 Solutions End returning sum sum (Single) sum = 0 Start with x (Array of 30 Single) Set j (Integer) to first index and loop Increment j by 1 and loop until j exceeds last index true x(j) <> 0 false sum = sum + x(j) End returning sum sum (Single) sum = 0 Start with x (Array of 30 Single) sum = sum + x(j) Do only if x(j)<>0 and j<=last index go back j (Integer) j = first index j = j + 1

53. 15 Aug 201153 Build a program which reads an array of singles (for example D1:D22) and reprints them sorted from smallest to largest Hints First think at how you would do this task step by step manually Then rethink carefully at each step of the manual procedure Then, according to the algorithm you have invented, it might be useful either to build a separate array to put the data or to build a subroutine which accepts an array and two indexes and switches the position of the elements in the array Extremely difficult homework