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Solar Interior (continued)

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1 Solar Interior (continued)
Role of convection energy transport in the solar interior

2 The onset of convection
Convection occurs in liquids and gases when the temperature gradient > some critical value, i.e. it begins because the state of the fluid is unstable. In a gas, convection occurs if a rising element is less dense than its surroundings. This depends on the rate at which the element expands due to decreasing pressure, and the rate at which the surrounding density decreases with height. In the Sun and other stars the temperature falls going from the core outwards. Thus both dT/dr and dP/dr are negative. For r < 0.71 R, dT/dr is determined by the Rosseland absorption coefficient (approximating free-free and free-bound absorption). When r > 0.71 R, as T falls still further, the free electrons start to recombine with nuclei to form ions which are effective absorbers of radiation. As a result the opacity increases and so dT/dr becomes steeper (i.e. T falls off with r more quickly). In a star, unlike the laboratory, there are no rigid walls at well defined temperatures for us to consider. In fact, the size of the star and the values of the physical quantities within it depend on the way in which energy is transported. In addition, stars are composed of highly compressible gas which means that a rising element depends not only on its temperature but also on its pressure, which is also the pressure of its surroundings.

3 ONSET OF CONVECTION Illustrating an element of gas rising in the solar interior and principle of convection. Element of gas after rising Values of pressure (P), density (ρ) outside gas element Element of gas before rising Temperature = T1, T1’ initially, then T2, T2’ after element has risen.

4 Onset of convection (contd.)
Let’s assume that the element rises adiabatically and does not exchange heat with its surroundings. So, in the figure, for 2′ < 2 and T2′ > T2, the element keeps rising towards the photosphere. Here it radiates, cools, becomes denser, and falls. Hence a convective cycle is established. Evidence for convection can be seen in the patterns of granulation and supergranulation in the surface layers of the Sun.

5 Figure shows the gas element starting out at P1′ = P1 and 1′ = 1
Figure shows the gas element starting out at P1′ = P1 and 1′ = 1. It moves to a new position with P2′ = P2 but 2 ≠ 2′ and T2 ′ ≠ T2. The transfer is adiabatic if the element rises quickly compared with the time to absorb or emit radiation. Hence, or where γ is the ratio of specific heats at constant pressure & volume: (as we had before) for a fully ionized gas.

6 In terms of density (ρ1/ρ2 = V2/V1):
Hence the condition for instability is (13a) i.e. density inside the element < density of surroundings. Before the element starts rising, it is indistinguishable from its surroundings, so: Also, after the element rises, the pressures inside & outside the element must be equal: Now let 1 = , 2 = ρ + d and P1 = P, P2 = P + dP, then inequality (13a) is: (13b) using the binomial expansion, (1 + α)n ~ 1 + nα if α is small.

7 First recall differential calculus rule for quotients:
Now if we consider radial gradients (subscript r) as in the Sun’s interior, the condition for instability becomes: Eliminate ρr using ideal gas equation (μ = molecular weight, mH = H atom mass): or First recall differential calculus rule for quotients: (13)

8 So inequality (13) becomes:
and expanding: or But note that both dT/dr and dP/dr are negative and hence the criterion for instability is: (14)

9 The RHS of inequality (14) is called the adiabatic temperature gradient. So there is convection when the magnitude of dTr /dr is greater than the adiabatic value. Proceeding outwards in the solar interior, the absorption (opacity) increases because of the increased recombination of free electrons with ions (particularly Fe ions). This causes the radial temperature gradient dTr /dr to steepen. Onset of convection occurs at a level in the solar interior where the temperature ~ 106 K. The condition for convective instability is called the Schwarzschild Criterion. It implies that when the actual T gradient, | dTr /dr | is greater than the | dTr /dr |adiabatic convection will begin. (See Schwarzschild’s book pp. 44 et seq. for further description of convective energy transport.)

10 We have now derived the basic stellar structure equations: Equation of hydrostatic equilibrium (3) Equation of state (8) Mass as a function of radius (4) Radiation flux Lr as a function of radius (9) Radiative temperature gradient (12) Condition for convective transport (14) The boundary conditions for the solution of these equations are: M(r=0) = 0; L(r=0) = 0; M(r=R) = M; radius of Sun at age 4.6 Gyr is R. These can be integrated numerically to give T, P, M, and L as a function of radius r – a model of the solar interior. A standard solar model has been developed by J. N. Bahcall (see his book Neutrino Astrophysics, chap. 4).

11 Solar evolution Progressive gravitational contraction of an interstellar gas cloud – some gravitational energy is converted to thermal energy Temperature (T ) and particle density (n) increase at the centre of the collapsing cloud: when T and n become large enough, nuclear fusion of H begins (“nucleosynthesis”) and contraction stops. Sun is on main sequence, where it spends nearly all its lifetime (next slide). After 1010 years = 10 Gyr, the H is exhausted, contraction will resume. Fusion continues in a thin H shell whose radius increases with time. The layers outside the H shell are heated so that the Sun expands to become a red giant (see next but 1 slide). As core contraction continues the core temperature will increase until He fusion begins (T ~ 108 K) and contraction halts again. When He is exhausted, contraction continues until electron degeneracy provides sufficient pressure to halt the collapse – the white dwarf phase. A tenuous envelope of gas is shed to form a planetary nebula.

12 Hertzsprung-Russell Diagram
Stellar masses indicated in units of 1 solar mass = 1 Mʘ 0.25 Mʘ

13 Evolution of the Sun: Contraction Main Sequence Red giant He-burning stage White dwarf

14 NGC 3132 nebula Examples of Planetary nebulae Cat’s Eye nebula

15 Solar evolution: core temperature and density
MAIN SEQUENCE Core density Shaded area = convectively unstable Core temperature Sun is fully convective up to 1.4 x106 years temperature throughout < 1-2 x106 K, opacity is high and (dT/dr)rad is steep  Schwarzschild criterion is always exceeded. As a result of complete convection, all 2D is consumed, not just that in core. As contraction continues Tc increases and because the gas begins to be fully ionized (dT/dr)rad decreases relative to the adiabatic gradient  radiative transfer begins after 106 years and up to 2 x107 years extends to the whole star. During this phase luminosity reaches a minimum but then begins to increase By 2x107 years, core temperature and density are high enough to begin H fusion - Tc= 7x106 K and c = 2x104 kg m-3. As Tc rises to 1.2x107 K, 12C can fuse to form 14N - this is a brief phase that halts contraction and causes expansion. The core becomes convective again but is mainly radiative. At this stage (~5x107 years) a long and stable H fusion phase begins on the main sequence. From this time on R, L and Tc increase slowly while Xc (the central mass fraction of H) drops steadily. Continues to ~8x109 years when H is exhausted. PRESENT

16 Nuclear fusion reactions
For nuclear reactions to occur, the K.E. of the interacting particles must be large enough to overcome the Coulomb (charge) barrier and bring them within the range of the (residual) strong nuclear force: 1.7 × m ( = 1.7 femtometers = 1.7 fm). Four factors determine the most likely nuclear reactions: Abundance of nuclear species Reaction probability at the core temperature Nuclear charge, Z Production of stable nuclei as reaction products Since the Coulomb force scales with Z 2, reactions occur preferentially between low-Z nuclei. The most abundant are: H, He, C, N, O, Ne, Mg & Si. At the temperature of the Sun’s core, some reaction rates are very slow – only one reaction per particle occurs in 1.4×1010 years.

17 Nuclear reaction sequences in Sun
Particle energies in the core (temperature = 15.6 MK) are at the few keV level, but typical Coulomb barriers for light elements are ~ MeV. Fusion in main sequence stars only begins as the result of quantum mechanical tunnelling (i.e. wave functions of interacting particles penetrate each other). Two nuclear reaction sequences occur in the Sun: Proton-proton (p-p) chain – gives 99% of the energy Carbon-Nitrogen (CN) cycle – gives 1% of the energy.

18 Proton—proton chain There is a series of reactions. First, deuterium (2H) is formed from the collision of two protons. 1a) p + p  2H + e+ + e with Q = MeV, E < MeV Alternatively, the p—e—p reaction can start the chain: 1b) p + e- + p  2H + e with Q = 0.4 MeV, E =1.442 MeV where Q is the amount of energy produced (e.g. in -ray photons, positron annihilation, and particle kinetic energy) which is available for heating the Sun (i.e. to produce its luminosity); Eν is the neutrino energy (neutrinos escape from the Sun and so carry away this energy). Both reactions proceed very slowly – first, 2 protons must penetrate each other to within 1.7 x m (only ~10-8 of them do), secondly, one must undergo an inverse β decay during the collision process: p → n + e+ + νe

19 Proton—proton chain (contd.)
The next step happens within ~10s: 2H + p  3He +  Q = MeV followed by: 3He + 3He  4He + 2p Q = MeV Note that (1a) and (2) or (1b) and (2) must occur twice for each time (3) occurs. The net result is: p  4He + 2e+ + 2e plus energy available for heating the Sun. .

20 Proton—proton chain (contd.)
Important side reactions (producing neutrinos – observable if in blue): 4) 3He + 4He  7Be +  with Q = MeV followed by either of these two reactions: 5) 7Be + e-  7Li + e with Q = MeV and E = MeV (89.7%) or 6) 7Li + p  2 4He with Q = MeV and E = MeV (10.3%) Or these reactions: 7Be + p  8B +  Q = MeV 8B  8Be* + e+ + e Q = MeV E < MeV 8Be*  2 4He Q = MeV In addition there is a very rare reaction (“hep” reaction): 10) 3He + p  4He + e+ + e E < MeV

21 Carbon-Nitrogen cycle
This set of reactions contributes ~1% of the solar luminosity and is only important in the interiors of higher temperature stars. The summary reaction is: 4p  4He + 2 e+ + 4 + 2 e Q = MeV with C and N nuclei involved, acting as catalysts.

22 Reaction Rates To get energy generation rates per unit mass per second, we evaluate the reaction rates (units: m-3 s-1): where N1 and N2 are the number densities of nuclei with atomic number Z1 and Z2 and atomic mass A1 and A2. The factor <v>12 is a rate coefficient or “temperature-averaged cross section”, and is an integral of the product of the cross section (v), the particle velocity v, and the Maxwell-Boltzmann velocity distribution (velocities v are in the centre-of-mass system of the reacting nuclei) –

23 is the reduced mass, E is the centre-of-mass energy,
where is the reduced mass, E is the centre-of-mass energy, T is the temperature, S(E) is a function which defines the cross sections and f0 is a factor that describes the “screening effect” of electrons. The additional exp (-2) term expresses the probability of penetrating the Coulomb barrier and is called the Gamow penetration term: So reactions between light nuclei with small charges are favoured where A is related to the atomic masses A1, A2 by S(E) can be measured, but only at E  200 keV. S(E) for lower energies are obtained by extrapolation to lower energies.

24 The energy generation rate, , is set by the reaction rate per unit volume, the energy per reaction, and the density. Hence, ε = f0 X1 X2 ρ T α where X1 and X2 are reactant fractions (X1 = X2 for p-p chain) and α = 4.5 for the p-p chain (it is α = 20 for the C-N cycle). So ε is extremely dependent on the core temperature. Fusion suddenly “turns on” during the solar contraction phase when T reaches a particular value.

25 Standard solar model The points discussed so far allow us to specify the standard solar model describing the physical conditions in the solar interior as follows. Abundances The model begins with a homogeneous chemical composition (H or X = 0.71, He or Y = 0.27, “metals” or Z = 0.02) – changes that occur during the 4.6 × 109 years to the present day are assumed only to occur due to fusion reactions. Hydrostatic equilibrium The Sun is assumed to be in hydrostatic equilibrium. Energy transport In the deep interior (out to 0.71 R), energy transport is by radiation. Outside this region, energy transport is by convection. Energy generation Nuclear fusion reactions (mostly p-p chain) are the primary source of energy.

26 Conditions inside Sun: Bahcall’s models
Luminosity Hydrogen fraction Temperature Density r/R0

27 Solar neutrinos There are uncertainties in the solar standard model because of the Sun’s internal composition and age, and from errors in opacities, nuclear reaction rates and the equation of state (relating pressure and density) in the dense central regions. In the p-p chain, neutrinos of the following energies are produced: < MeV 1.442 MeV 0.862 MeV 0.384 MeV < MeV < MeV … and for the C-N cycle: < MeV < MeV < MeV

28 Calculated Neutrino Fluxes
Spectra of solar neutrinos: p-e-p and 7Be reactions produce neutrinos with single energies. p-p chain reactions produce neutrinos with continuous energies. Energy range of Neutrino experiments: “hep” neutrinos are those produced by 3He + p reactions.

29 Predicted neutrino fluxes at Earth (standard solar model)
Source Reaction no. Neutrino energy (MeV) Flux (1014 m-2 s-1) Proton-proton p-p 1a < 0.420 6.0 p-e-p 1b < 1.442 0.014 “hep” 10 < 8x10-7 7Be 5 0.862,0.384 0.47 8B 8 < 14.02 5.8x10-4 CN cycle 13N < 1.199 0.06 15O < 1.732 0.05 17F < 1.740 5.2x10-4

30 Neutrino production as a function of solar radius
The fraction of neutrinos that originate in each fraction of the solar radius is dflux/d(R/R_o). Figure shows the production fraction for the reactions indicated. Fraction of solar luminosity produced at each solar radius denoted by L.

31 The Homestake Neutrino Detector
The first solar neutrino experiment was set up in 1968 by Raymond Davis and collaborators. It operated continuously from 1970 to 1994. The experiment was 1.5 km deep in the Homestake gold mine in South Dakota (to shield it from cosmic rays). Its operation was based on the reaction: 37Cl + e  37Ar + e- The neutrino energy threshold is MeV. From the standard model most (77%) detectable neutrinos for this reaction are from reaction (8) in the p—p chain, i.e.  decay of 8B to 8Be. ~13% are from reaction (5). The detector consisted of a large (400 m3 ) tank of the cleaning fluid perchloroethylene (C2Cl4) containing 2.2 × 1030 Cl atoms. Just under 2 solar neutrino-induced reactions were expected per day. About 100 billion neutrinos pass through your thumbnail every second. for every 100 billion solar neutrinos passing through th earth there is only 1 reaction. Ray Davis and John Bahcall proposed an experiment to look for neutrinos in First results were announced in 1968 and only 1/3 of radiaoactive argon atoms were detected.

32 The Homestake Mine Neutrino Detector in South Dakota.
The tank contained 400 m3 of perchloroethylene. Raymond Davis Jr ( ), Nobel Prize winner in 2002.

33 37Ar decays by electron capture and emits 2.82 keV electrons that
A typical “run” lasted 80 days, after which He gas was bubbled through the tank to pick up 37Ar atoms. A measured volume of 37Ar gas was then placed in a proportional counter (similar to a Geiger counter but with pulse height proportional to photon energy). 37Ar decays by electron capture and emits 2.82 keV electrons that are detected by the proportional counter. Counting was carried out over 8 months to estimate the background - 37Ar decays in ~ 3 months. New unit introduced by Bahcall - the solar neutrino unit or SNU: 1 SNU  1 neutrino capture per sec in 1036 target atoms 5.35 SNU  1 37Ar atom per day Observed 37Ar production rate = 2.55 ± 0.25 SNU Prediction rate from Bahcall’s standard solar model = 9.3 ± 1.3 SNU Observed rate = 3.6 times less than predicted by theory. This is (or was) the solar neutrino problem. Auger electrons - when an electron is removed from a core level an electron from a higher level can make a transition down, releasing energy. The energy can either be in the form of a photon or it can be transferred to another electron which is then ejected - this is an Auger electron.

34 Other experiments include:
Chemical detection in large Ga targets, either aqueous (GALLEX) or solid (SAGE). Ge decays by electron capture with a half-life of 11 days – the resulting electrons are detected as for the 37Cl experiment. Neutrino scattering by electrons orbiting atoms in water molecules in highly purified water (KAMIOKANDE and SUPER KAMIOKANDE) or “heavy water” (Sudbury Neutrino Observatory, SNO). The electron generates Čerenkov radiation which is detected by arrays of photomultipliers. SUPER KAMIOKANDE and SNO also detect muon neutrinos. Čerenkov radiation is generated by electrons with v > c / n where n is the refractive index. Radiation is emitted in a cone with half-angle cos  = 1 / n , where  = v / c. KAMIOKANDE thus determines the direction of neutrinos. The gallium experiments were sensitive to lower energy neutrinos whose fluxes could be calculated more accurately by John Bahcall. Energy threshold = MeV Energy threshold for the neutrino scattering experiment MeV. these experiments are able to detect some neutrinos other than electron neutrinos and detected about half the predicted number.

35 SUPER KAMIOKANDE neutrino detector (Japan)
The detector, which measures 40m (tall) × 40m (wide), is filled with purified water, and has 13,000 photomultiplier tubes that detect Cerenkov radiation from recoiling electrons struck by incoming neutrinos, in the form of a cone of light. The detector is 1km underground. Unlike other neutrino detectors, it can determine the neutrino direction.

36 Super Kamiokande under construction: filling up with water

37 Sun’s image in neutrinos: 500 days of Super Kamiokande data

38 Measured and predicted neutrino fluxes
Target Experiment Threshold energy (MeV) Measured neutrino flux (SNU) Predicted neutrino flux (SNU) Ratio: measured /predicted Chlorine 37 Homestake 0.814 2.56 9.5 0.270.02 Water Kamiokande 7.5 2.80 6.62 0.420.06 Gallium 71 Gallex 0.2 69.7 136.8 0.510.06 SAGE 72 0.530.10

39 Possible explanations for the discrepancy:
Observed neutrino rate is 1.9—3.6 times less than predicted by theory. Possible explanations for the discrepancy: The standard solar model is wrong The experiments are wrong Standard model of particle physics is wrong The neutrinos detected in the 37Cl +   37Ar + e- reaction (in the Homestake expt.) are mostly those due to 8B decays. The 8B neutrino production rate  T 15, so only a slightly wrong T in the standard solar model could account for the discrepancy.

40 Low Z model: (dT/dr)rad 
hence a lower central temperature can be achieved by decreasing . This can be done with a lower abundance of heavy elements in the core. Need to assume Z/X ~ 0.1 (Z/X)surface to obtain 1/3 of standard model neutrino flux. But! This is ruled out by helioseismology (p-mode oscillations). Rapid core rotation: If the core were to rotate 1000 times faster than the surface, the thermal pressure required to support the Sun against gravity would be reduced and the neutrino flux would decrease. But! analysis of p-mode oscillations shows no increase of rotation rate between r = 0.2 R and r = R. This is outside the region of the core where 8B neutrinos are produced. 3. Mixing in the Sun: the core progressively depletes H by fusion (note diffusion of nuclear species is negligible). Now the energy generation rate   X 2  T 4.5, so somehow returning H to the core would allow a reduced value of T. To obtain a factor 3 reduction in neutrino flux requires 60% of the Sun’s mass to have been mixed for the Sun’s lifetime. But! There is no evidence of mixing at this level.

41 Neutrino mixing – the Neutrino Problem solved
There are 3 different neutrino states or flavours: e,  ,  associated with the electron, muon, and tau particle in weak interaction decays. Most solar neutrino experiments so far have only detected electron neutrinos. Mikheyev and Smirnov (1985) and Wolfenstein (1978) showed that neutrinos can change state in the presence of other matter if they have a tiny rest mass. This change of state is called the MSW effect. Masses are very small: the e has a mass that is < 2.2 eV/c2. Hence the emitted electron neutrinos could be “mixed” into muon or tau particle neutrinos modified as they leave the Sun. So electron neutrinos would only be 1/3 of the total number of neutrinos. The solar neutrino problem has now been resolved by mixing of the neutrino flavours as they emerge from the solar core many detectors only see electron neutrinos which are ~1/3 of the total neutrinos arriving at Earth. Two different reactions can occur when an electron neutrino strikes a deuterium nucleus: in a "neutral-current reaction" the neutrino splits the deuterium nucleus into a proton and a neutron; in a "charge-current reaction" two protons and an electron are produced. All three neutrino flavours experience neutral-current reactions, but only electron neutrinos undergo charged-current reactions. All three flavours also experience "elastic scattering" off electrons in the detector. At SNO the electrons produced in charged-current reactions emit Cerenkov radiation as they travel through water. The intensity of this radiation is proportional to the energy of the neutrino, and this allows the energy distribution of the incoming neutrinos to be calculated. The Sudbury team compared its value of electron-neutrino flux with a very precise measurement of the total neutrino flux based on elastic scattering measurements at SuperKamiokande.


43 Solar rotation All stars must rotate - random eddy motion in protostellar clouds transfers angular momentum. The Sun rotates rather slowly compared with many similar stars. Pressure differences drive flows between the poles and the equator. The Sun does not rotate rigidly (rotates faster at equator). In the convection zone convective motions are much faster than circulation currents - this leads to a distribution of angular velocity that varies both with depth and latitude → differential rotation.

44 Measured rates of solar rotation
Solar rotation rates observed by Doppler shifts at the solar limb and by sunspots. Latitude N or S (o) Period from Doppler shift (days) Spot period (days) 25.6 24.7 10 25.7 24.9 20 26.0 25.3 30 26.6 40 27.7 26.9 50 29.3 60 31.4 70 33.6 80 33.5

45 Flows in the solar interior

46 Flows in the solar interior (contd.)
Faster equatorial rotation ascribed to large-scale motions– meridional flows– from equator to pole near surface, return flows from pole to equator well beneath surface. Flow velocities measured by the Michelson Doppler Imager instrument on SOHO are ~10 m s-1 Observations from sunspots are slightly ambiguous – small sunspots rotate slightly faster than large spots.

47 Solar spectral irradiance ( fν or fλ)
Theory (HRSA = Harvard Reference Standard Atmosphere) and observed distributions + Black body

48 Photospheric radiation
fν as a function of wavelength (or frequency) is measured with bolometers, either Earth-based or on spacecraft. The values of f are corrected to the mean Earth-Sun distance (149,600,000 km). Its integral over frequency: is the total solar irradiance (formerly known as the “solar constant”) = total amount of radiation per unit energy per unit time per unit area reaching the top of the Earth’s atmosphere.

49 Variability of Total Solar Irradiance
The total solar irradiance is slightly variable and depends on the 11-year sunspot cycle. Total range of variations is 0.3%, and is at a maximum at sunspot maximum. But when there are large sunspots the total solar irradiance may dip by 0.25%. Its mean value is about × 103 W m-2 (1.368 kW m-2).

50 Irradiance (W m-2)

51 More recent information...
D. Pesnell (AGU 2008)

52 The Sun’s Effective Temperature
The Sun’s mean total irradiance is × 103 W m-2 This is incident on a sphere, radius = 1 A.U. = × 1011 m. So total energy/second received by sphere is × 103 × 4 π (1.496 × 1011)2 W. Radiation is uniformly emitted from the entire surface of the Sun. Radius of Sun is R = 6.96 × 108 m. If the Sun were a perfect black body, the radiation emitted would be 4 π R2 × σ Teff4 W where Teff is the Sun’s effective temperature and σ = Stefan-Boltzmann constant = 5.67 × 10-8 W m-2 K-4. This is the Sun’s luminosity. Therefore i.e. Teff = 5778 K.

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