# Stoichiometry.

## Presentation on theme: "Stoichiometry."— Presentation transcript:

Stoichiometry

Stoichiometry Stoy – key – ohm – e - tree

9.1 Introduction to Stoichiometry
1. Define Stoichiometry. 2. Describe the importance of the mole ratio in stoichiometric calculations. 3. Write a mole ratio relating two substances in a chemical equation. 4. Calculate the amount in moles of a reactant or product from the amount in moles of a different reactant or product.

Obj 1: What is Stoichiometry?
Stoichiometry means Stoicheio = element Metron = measure Stoichiometry is the quantitative study of chemical reactions using balanced equations.

Obj 2: Mole Ratio Mole Ratios come from the coefficients in a balanced equation. Mole Ratios are used to convert moles of one substance (X) into moles of another substance (Y).

Obj 3: Mole Ratios from Balanced Equations
1 N H2  2 NH3 The Possible Mole Ratios are:

Obj 3: Mole Ratios from Balanced Equations
1 N H2  2 NH3 The Possible Mole Ratios are: 1 mol N mol N mol H2 3 mol H mol NH3 2 mol NH3

Obj 3: Mole Ratios from Balanced Equations
1 N H2  2 NH3 Other Possible Mole Ratios: 1 mol N mol N mol H2 3 mol H mol NH3 2 mol NH3 3 mol H mol NH3 2 mol NH3 1 mol N mol N mol H2

Obj 4: Using a Mole Ratio 1 N2 + 3 H2  2 NH3
7.5 mol N ? mol H ? mol NH3

Obj 4: Using a Mole Ratio 1 N2 + 3 H2  2 NH3
7.5 mol N ? mol H ? mol NH3 7.5 mol N2 (3 mol H2 ) = ? (1 mol N2 )

Obj 4: Using a Mole Ratio 1 N2 + 3 H2  2 NH3
7.5 mol N ? mol H ? mol NH3 7.5 mol N2 (3 mol H2 ) = 22.5 mol H2 (1 mol N2 )

Using a Mole Ratio 1 N2 + 3 H2  2 NH3
7.5 mol N mol H ? mol NH3 7.5 mol N2 (2 mol NH3) = ? (1 mol N2 )

Obj 4: Using a Mole Ratio 1 N2 + 3 H2  2 NH3
7.5 mol N mol H ? mol NH3 7.5 mol N2 (2 mol NH3) = mol NH3 (1 mol N2 )

Obj 4: Cookie Stiochiometry
One Batch: N H2  2 NH3 Double Batch: _ N _ H2  _ NH3

Obj 4: Cookie Stiochiometry
One Batch: N H2  2 NH3 Double Batch: 2 N H2  4 NH3

Obj 4: Cookie Stiochiometry
One Batch: N H2  2 NH3 Double Batch: 2 N H2  4 NH3 Triple Batch: _ N _ H2  _ NH3

Obj 4: Cookie Stiochiometry
One Batch: N H2  2 NH3 Double Batch: 2 N H2  4 NH3 Triple Batch: N H2  6 NH3

Obj 4: Cookie Stiochiometry
One Batch: N H2  2 NH3 Double Batch: 2 N H2  4 NH3 Triple Batch: N H2  6 NH3 Half Batch: _ N _ H2  _ NH3

Obj 4: Cookie Stiochiometry
One Batch: N H2  2 NH3 Double Batch: 2 N H2  4 NH3 Triple Batch: N H2  6 NH3 Half Batch: N H2  1 NH3

Lets Look at Our Problem Again We want 7.5 batch !
1 N H2  2 NH3 __ mol N ___ mol H2 __ mol NH3

Lets Look at Our Problem Again We want 7.5 batch !
1 N H2  2 NH3 7.5 mol N mol H mol NH3

The End The Final Curtain