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Factoring means finding the things you multiply together to get a given answer.

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Presentation on theme: "Factoring means finding the things you multiply together to get a given answer."— Presentation transcript:

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2 Factoring means finding the things you multiply together to get a given answer.

3 You did some work with factoring in grade school. For instance, you found the prime factorization of numbers.

4 You have also found factors of numbers and their common factors.

5 When adding or subtracting fractions, you used factors to find the least common denominator.

6 In algebra we mostly care about factoring polynomials.  We want to find what you need to multiply together to get a given polynomial.  It’s like you’re playing Jeopardy with the distributive property.

7 Almost all the time we will be factoring quadratic trinomials.

8 The most common factoring problems look like this: Factor x 2 + 12x + 35 We need to find the quantities we can multiply to get this polynomial.

9 Factor x 2 + 12x + 35 The answer will have the format (x + ___)(x + ___)

10 Factor x 2 + 12x + 35 To find the numbers that go in the quantity, find what you can multiply to get 35 that adds up to 12

11 Factor x 2 + 12x + 35 multiply to get 35 that adds up to 12 The only numbers that do both are 7 and 5. So … (x + 7)(x + 5)

12 Factor x 2 + 12x + 35 multiply to get 35 that adds up to 12 The only numbers that do both are 7 and 5. So … (x + 7)(x + 5) (x + 5)(x + 7) is also OK.

13 Factor x 2 + 13x + 36

14 Factor x 2 + 13x + 36 + 

15 Factor x 2 + 13x + 36 +  There are lots of ways to get 36, like 6  6, 9  4, and 12  3.

16 Factor x 2 + 13x + 36 +  There are lots of ways to get 36, like 6  6, 9  4, and 12  3. Only 9 + 4 adds up to 13.

17 Factor x 2 + 13x + 36 +  There are lots of ways to get 36, like 6  6, 9  4, and 12  3. Only 9 + 4 adds up to 13. So the answer is (x + 9)(x + 4)

18 Factor x 2 + 13x + 40 x 2 + 10x + 24 x 2 + 10x + 9

19 Factor x 2 + 13x + 40 (x + 8)(x + 5) x 2 + 10x + 24 (x + 6)(x + 4) x 2 + 10x + 9 (x + 9)(x + 1)

20 Factor x 2 – 16x + 48

21 Factor x 2 – 16x + 48 The rule is still the same Multiply to get 48 Add to get -16

22 Factor x 2 – 16x + 48 The rule is still the same -12  -4 = 48 -12 + -4 = -16

23 Factor x 2 – 16x + 48 The rule is still the same -12  -4 = 48 -12 + -4 = -16 So it’s (x – 12)(x – 4).

24 Factor x 2 – 5x + 6 x 2 – 16x + 55 x 2 – 18x + 32

25 Factor x 2 – 5x + 6 (x – 2)(x – 3) x 2 – 16x + 55 (x – 11)(x – 5) x 2 – 18x + 32 (x – 16)(x – 2)

26 Factor x 2 – x – 72

27 Factor x 2 – x – 72 +  This time we need both positive and negative factors because we’re multiplying to get -72. We also need to add to -1.

28 Factor x 2 – x – 72 +  Consider (x + 9)(x – 8) and (x – 9)(x + 8) Both multiply to -72 Only the 2 nd adds to -1 So … It’s (x – 9)(x + 8)

29 Factor x 2 + 5x – 24 This time we need to multiply to -24 and add to positive 5

30 Factor x 2 + 5x – 24 (x + 8)(x – 3)

31 If you have one positive and one negative factor, the larger factor has the same sign as the middle term in the trinomial. x 2 + 4x – 21 = (x + 7)(x – 3) x 2 – 3x – 18 = (x – 6)(x + 3)

32 Factor x 2 + 5x – 36 x 2 – 4x – 32 x 2 + 12x – 28

33 Factor x 2 + 5x – 36 (x – 4)(x + 9) x 2 – 4x – 32 (x – 8)(x + 4) x 2 + 12x – 28 (x + 14)(x – 2)

34 Factor x 2 + 6x + 9

35 Factor x 2 + 6x + 9 + 

36 Factor x 2 + 6x + 9 +  (x + 3)(x + 3)

37 Factor x 2 + 6x + 9 +  (x + 3)(x + 3) Most books would write this as (x + 3) 2

38 Factor x 2 + 16x + 64 x 2 – 18x + 81 x 2 + 12x + 36

39 Factor x 2 + 16x + 64 (x + 8) 2 x 2 – 18x + 81 (x – 9) 2 x 2 + 12x + 36 (x + 6) 2

40 Factor x 2 – 49

41 Factor x 2 – 49 We need to multiply to get -49

42 0x Factor x 2 – 49 We need to multiply to get -49 We need to add to get 0

43 0x Factor x 2 – 49 We need to multiply to get -49 We need to add to get 0 It’s (x + 7)(x – 7)

44 Factor x 2 – 100 x 2 – 1 x 2 – 25

45 Factor x 2 – 100 (x + 10)(x – 10) x 2 – 1 (x – 1)(x + 1) x 2 – 25 (x + 5)(x – 5)

46 Let’s try a bit of everything.

47 x 2 + 8x + 12 x 2 – x – 20 x 2 – 16x + 64 x 2 – 12x + 27

48 x 2 + 8x + 12 (x + 6)(x + 2) x 2 – x – 20 (x – 5)(x + 4) x 2 – 16x + 64 (x – 8) 2 x 2 – 12x + 27 (x – 3)(x – 9)

49 x 2 – 4x - 45 x 2 – 16 x 2 + 2x + 1 x 2 – 18x + 72

50 x 2 – 4x - 45 (x – 9)(x + 5) x 2 – 16 (x – 4)(x + 4) x 2 + 2x + 1 (x + 1)(x + 1) x 2 – 18x + 72 (x – 12)(x – 6)

51 Your book also likes problems like this. Factor a 2 + 2ab – 15b 2

52 Factor a 2 + 2ab – 15b 2 The rules are still the same, but the answer will have both a and b in it.

53 Factor a 2 + 2ab – 15b 2 Multiply to get -15 Add up to 2

54 Factor a 2 + 2ab – 15b 2 Multiply to get -15 Add up to 2 It’s (a + 5b)(a – 3b)

55 Factor x 2 + 6xy + 8y 2 n 2 – 2np – 35p 2

56 Factor x 2 + 6xy + 8y 2 (x + 4y)(x + 2y) n 2 – 2np – 35p 2 (n + 5p)(n – 7p)

57 Your book also likes problems like this. Factor x 10 + 16x 5 + 63

58 Factor x 10 + 16x 5 + 63 What’s different this time is that the first part has x 10. This means the answer will have the form (x 5 + __)(x 5 + __)

59 Factor x 10 + 16x 5 + 63 +  Everything else is the same. So, the answer is … (x 5 + 9)(x 5 + 7)

60 Factor x 4 – 26x 2 + 25 completely.

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62 Factor x 4 – 26x 2 + 25 completely. (x 2 – 25)(x 2 – 1)

63 Factor x 4 – 26x 2 + 25 completely. (x 2 – 25)(x 2 – 1) … BUT, we’re not done.  Both parts can be factored again.

64 Factor x 4 – 26x 2 + 25 completely. (x 2 – 25)(x 2 – 1) (x + 5)(x – 5)(x + 1)(x – 1)

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66 There are two more things that can complicate factoring.

67 First … Quadratic coefficients

68 If there’s a coefficient that makes the problem look like ax 2 + bx + c The answer will usually have the form (ax + __)(x + __)

69 ax 2 + bx + c You still want to find numbers that will multiply to “c”. (ax + __)(x + __)

70 ax 2 + bx + c Unfortunately, they WON’T just add up to b.

71 ax 2 + bx + c Remember FOIL. Outside + Inside needs to add to b

72 Factor 3x 2 + 23x + 14

73 Factor 3x 2 + 23x + 14 The answer will have the form (3x + __)(x + __)

74 Factor 3x 2 + 23x + 14 The answer will have the form (3x + __)(x + __) Since 7  2 = 14, it might be (3x + 7)(x + 2) or (3x + 2)(x + 7)

75 Factor 3x 2 + 23x + 14 Which is right? (3x + 7)(x + 2) (3x + 2)(x + 7) Check outside + inside

76 Factor 3x 2 + 23x + 14 Which is right? (3x + 7)(x + 2) 6 + 7 = 13  (3x + 2)(x + 7) 21 + 2 = 23

77 Factor 3x 2 + 23x + 14 The answer is (3x + 2)(x + 7)

78 Factor 5x 2 + 2x – 3

79 Factor 5x 2 + 2x – 3 Could be (5x + __)(x – __) or (5x – __)(x + __)

80 Factor 5x 2 + 2x – 3 The numbers at the end will be 3 and 1 (one + and one –)

81 Factor 5x 2 + 2x – 3 Consider (5x + 3)(x – 1) (5x + 1)(x – 3) (5x – 3)(x + 1) (5x – 1)(x + 3) Check outside + inside

82 Factor 5x 2 + 2x – 3 Consider (5x + 3)(x – 1) -5+3= -2 (5x + 1)(x – 3) -15+1= -14 (5x – 3)(x + 1) 5–3 = 2 (5x – 1)(x + 3) 15–1 = 14 Check outside + inside

83 Factor 5x 2 + 2x – 3 The answer is (5x – 3)(x + 1)

84 Factor 2x 2 + 19x + 24 7x 2 – 37x + 10 3x 2 – x – 10

85 Factor 2x 2 + 19x + 24 (2x + 3)(x + 8) 7x 2 – 37x + 10 (7x – 2)(x – 5) 3x 2 – x – 10 (3x + 5)(x – 2)

86 The other possible complication is common factors.

87 Common factor problems usually involve binomials, like this one: Factor 6x 7 + 15x 6

88 The answer typically has the form ___( __ + __ )  The common factor goes outside the parentheses.  Divide the original problem by the common factor to get what stays in the parentheses.

89 Factor 6x 7 + 15x 6

90 Factor 6x 7 + 15x 6 To find the common factor…  Find the biggest number that goes into both 6 and 15 (the GCF)  Choose the smaller exponent … Here it’s 3x 6

91 Factor 6x 7 + 15x 6 So our answer has the form 3x 6 ( __ + __ )

92 Factor 6x 7 + 15x 6 So our answer has the form 3x 6 ( __ + __ ) Now divide both terms by 3x 6  Divide coefficients.  Subtract exponents.

93 Factor 6x 7 + 15x 6 The final answer is … 3x 6 (2x + 5)

94 Factor 12x 4 y 2 – 8xy 3

95 Factor 12x 4 y 2 – 8xy 3 Common factor is 4xy 2 So answer is 4xy 2 (__ + __)

96 Factor 12x 4 y 2 – 8xy 3 4xy 2 (3x 3 – 4y)

97 Factor 7x 5 + 21x 4 18x 3 – 27x 4 30a 5 b 2 + 25a 3 b 3

98 Factor 7x 5 + 21x 4 7x 4 (x + 3) 18x 3 – 27x 4 9x 3 (2 – 3x) 30a 5 b 2 + 25a 3 b 3 5a 3 b 2 (6a 2 + 5b)

99 Factor 2x 4 + 16x 3 + 30x 2 completely.

100 Factor 2x 4 + 16x 3 + 30x 2 completely. First take out a common factor. Here it’s 2x 2

101 Factor 2x 4 + 16x 3 + 30x completely. 2x 2 (x 2 + 8x + 15) Now factor what’s inside the parentheses.

102 Factor 2x 4 + 16x 3 + 30x completely. 2x 2 (x 2 + 8x + 15) = 2x 2 (x + 5)(x + 3)

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