Presentation is loading. Please wait.

Presentation is loading. Please wait.

(MTH 250) Lecture 21 Calculus. Previous Lecture’s Summary Trigonometric integrals Trigonometric substitutions Partial fractions.

Similar presentations


Presentation on theme: "(MTH 250) Lecture 21 Calculus. Previous Lecture’s Summary Trigonometric integrals Trigonometric substitutions Partial fractions."— Presentation transcript:

1 (MTH 250) Lecture 21 Calculus

2 Previous Lecture’s Summary Trigonometric integrals Trigonometric substitutions Partial fractions

3 Today’s Lecture Recalls Improper integrals Introduction to vectors Dot product of vectors Cross product of vectors

4 Recalls

5 Recalls

6 We use the following identities to evaluate special of trigonometric integrals. IntegralIdentity Recalls

7 Recalls

8 How to find partial fractions: Linear factors Power of a linear factor Quadratic factor, we break it down to partial fractions as follows: Recalls

9 Recalls

10 Improper integrals

11

12

13

14

15

16

17 Conti.. Therefore,

18 Improper integrals

19

20

21

22

23

24

25

26

27 Introduction to vectors Coordinate axes and planes.:

28 Introduction to vectors Distance formula in three dimensions: The distance │P 1 P 2 │between the points P 1 (x 1,y 1,z 1 ) and P 2 (x 2,y 2,z 2 ) is

29 Introduction to vectors

30

31

32

33

34

35 Dot product of vectors

36

37 Cross product of vectors

38

39

40 Lecture Summary Recalls Improper integrals Introduction to vectors Dot product of vectors Cross product of vectors


Download ppt "(MTH 250) Lecture 21 Calculus. Previous Lecture’s Summary Trigonometric integrals Trigonometric substitutions Partial fractions."

Similar presentations


Ads by Google