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September 19/20, 2007 SIS 100 Magnet cooling and cryogenic distribution.

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Presentation on theme: "September 19/20, 2007 SIS 100 Magnet cooling and cryogenic distribution."— Presentation transcript:

1 September 19/20, 2007 SIS 100 Magnet cooling and cryogenic distribution

2 September 19/20, 2007 Each sextant consists: 18 Dipoles 28 Quadrupoles 24 Correctors ? Scraper 4 warm sections Length: 180 m SIS100 No collimators at cryogenic temperature

3 September 19/20, 2007 SIS100 cooling scheme Maximal  p = ? => dipole All other users have to be adopted to this pressure drop  p by: introducing an orifice at the inlet (small rage due to manufacturing accuracy and/ or Combination of different users

4 September 19/20, 2007 SIS100 cooling scheme System requires nearly no pressure drop along the supply lines to achieve the same pressure head along the sector for every component.  p supply < 50 mbar  p suction < 20 mbar d supply = 0,038 m (0,045m) d suction = 0,070 m (0,060 m)

5 September 19/20, 2007 Maximal flow given by the geometry flow impedance Minimal flow given by flow regime: slug or plug flow have to be avoided to reach equal temperature distribution within the coil pressure control Vapour fraction at yoke outlet should be kept between.9 and 1., to achieve an energy efficient operation SIS100 cooling dipole

6 September 19/20, 2007 Internal heat exchanger Recooler between supply line and magnet cooling Approx. 50m dipole /200m sextant = 0,25 => Q max,supply =0.1 W/m

7 September 19/20, 2007 SIS100 inlet conditions = 0.1W/m

8 September 19/20, 2007 Two traditional Nuclotron magnets: Tests

9 September 19/20, 2007 SIS100 cooling dipole Curved double layer dipole Cycle 2c B= 0 -> 1.9 T B=4T/s  cycle =1.8 s.

10 September 19/20, 2007 SIS100 cooling Pressure drop calculations Hermann, 2. 10 4 < Re < 2. 10 6

11 September 19/20, 2007 SIS100 cooling Pressure drop measurement

12 September 19/20, 2007 SIS100 cooling T in =4.5K; P in =1.56 bar; P suction =1.1 bar; m=2.45g/s;  coil = 63s,  Yoke = 12 s

13 September 19/20, 2007 SIS100 cooling T in =4.5K; P in =1.56 bar; P suction =1.1 bar; m=2.45g/s;  coil = 66s,  Yoke = 12 s T in =4.5K; P in =1.51 bar; P suction =1.12 bar; m=2.18g/s;  coil = 68s,  Yoke = 13 s

14 September 19/20, 2007 SIS100 cooling T in =4.5K; P in =1.56 bar; P suction =1.1 bar; m=2.45g/s;  coil = 66s,  Yoke = 12 s T in =4.4K; P in =1.56 bar; P suction =1.1 bar; m=2.56g/s;  coil = 66s,  Yoke = 12 s

15 September 19/20, 2007 T in = 4.51K SIS100 cooling

16 September 19/20, 2007 SIS100 cooling T in = 4.51K

17 September 19/20, 2007 SIS100 cooling T in = 4.51K

18 September 19/20, 2007 T in = 4.5K SIS100 cooling

19 September 19/20, 2007 SIS100 cooling

20 September 19/20, 2007 Curved double layer option There is a common range of pressures of operation, where both magnets, the first and the last will work, but The heat load onto the supply line should not exceed.08 W/m in the magnet cryostats. This should be possible be special shielding from the return line. To achieve a similar operational field, following groups for the correction elements are proposed by H. Khodzhibagiyan: Module M1: a quadrupole, pickup and steerer Module M2: a quadrupole, pickup and multipole Module M3: a quadrupole, multipole and collimator Module M4: a quadrupole, steerer and collimator The beam pipe cooling should be handled as a separate consumer and be put into the modules M1..M4 SIS100 cooling

21 September 19/20, 2007 SIS100 cooling Dipole: static load 7W, load in cycle 2c: 35.7 W Quadrupole: static load 4W, load in cycle 2c: 18.7 W Correctors:? Beam pipe cooling:? Scraper:?

22 September 19/20, 2007 180 m

23 September 19/20, 2007 Feed box on tunnel level in niche => short reaction time for the control valves Transfer lines through the tunnel as few valves as possible in the non accessible area

24 September 19/20, 2007 Distribution box on tunnel level in niche => Smaller space requirements in the transfer section Transfer lines through the tunnel valves in the non accessible area

25 September 19/20, 2007 SIS100 cooling -> To Refrigerator

26 September 19/20, 2007

27 Pressure drop versus heat load on the coil for a constant overall heat load of 30 W.

28 September 19/20, 2007 T-s-Diagram for three different load distribution onto the coil. The pressure drop variation caused by this load variation is below 2 mbar (or.5%).


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