1. Final Exam Review Current, Power, Voltage, Resistance Ohm’s Law Series & Parallel Circuits Electromagnetic Induction

2. Calculating a Power Bill Formula: $ = rPt Bill = Rate * Power (kW) * time (h) For this application ONLY, Power is in kilowatts, and time is in hours.

3. Example At 0.007 $/kWh, calculate the cost of running a 1000W microwave for 30 minutes. $ = rPt $ = (0.007 $/kWh)(1kW)(0.5h) $ = $0.00350 =

4. Practice Pg 623 Section Review # 4.

5. Current, Power, Voltage 3 main equations: Q = It Charge (C) = Current (A) * time (s) V = IR Voltage (V) = Current (A) * Resistance (Ω) P = IV Power (W) = Current (A) * Voltage (V)

6. Circuit Types Series Circuits: Circuits with only one path for electricity to flow through.

7. Circuit Types Parallel Circuit: Circuit with two or more loops.

8. Properties of Circuit Types SeriesParallel I tot = I 1 = I 2 = I 3 =…I tot = I 1 + I 2 + I 3 + … V tot = V 1 + V 2 + V 3 +…V tot = V 1 = V 2 = V 3 =… R tot = R 1 + R 2 + R 3 +…1/R tot = 1/R 1 +1/R 2 +…

9. Example- Series Circuit A 9.0V battery is connected to four light bulbs in series, with resistances of 4.0 Ω, 5.0Ω, 7.0Ω, and 2.0Ω. Find the equivalent resistance for the circuit and the current in the circuit.

10. Example A 9.0V battery is connected to four light bulbs in series, with resistances of 4.0 Ω, 5.0Ω, 7.0Ω, and 2.0Ω. Find the equivalent resistance for the circuit and the current in the circuit. R tot = R 1 + R 2 + R 3 + R 4

11. Example A 9.0V battery is connected to four light bulbs in series, with resistances of 4.0 Ω, 5.0Ω, 7.0Ω, and 2.0Ω. Find the equivalent resistance for the circuit and the current in the circuit. R tot = R 1 + R 2 + R 3 + R 4 R tot = 4.0 + 5.0 + 7.0 + 2.0 = 18.0Ω

12. Example A 9.0V battery is connected to four light bulbs in series, with resistances of 4.0 Ω, 5.0Ω, 7.0Ω, and 2.0Ω. Find the equivalent resistance for the circuit and the current in the circuit. R tot = R 1 + R 2 + R 3 + R 4 R tot = 4.0 + 5.0 + 7.0 + 2.0 = 18.0Ω V=IR tot

13. Example A 9.0V battery is connected to four light bulbs in series, with resistances of 4.0 Ω, 5.0Ω, 7.0Ω, and 2.0Ω. Find the equivalent resistance for the circuit and the current in the circuit. R tot = R 1 + R 2 + R 3 + R 4 R tot = 4.0 + 5.0 + 7.0 + 2.0 = 18.0Ω V=IR tot 9.0V = I (18.0Ω) I = 0.5A

14. Practice Pg 650 Practice A 1 & 2

15. Example- Parallel Circuit A 9.0V battery is connected to two resistors of 2.0Ω and 4.0Ω in parallel. Find the equivalent resistance for the circuit and the total current in the circuit.

16. Example A 9.0V battery is connected to two resistors of 2.0Ω and 4.0Ω in parallel. Find the equivalent resistance for the circuit and the total current in the circuit. 1/R tot = 1/R 1 + 1/R 2

17. Example A 9.0V battery is connected to two resistors of 2.0Ω and 4.0Ω in parallel. Find the equivalent resistance for the circuit and the total current in the circuit. 1/R tot = 1/R 1 + 1/R 2 1/R tot = 1/2.0 + 1/4.0 =.75 R tot = 1.33Ω

18. Example A 9.0V battery is connected to two resistors of 2.0Ω and 4.0Ω in parallel. Find the equivalent resistance for the circuit and the total current in the circuit. 1/R tot = 1/R 1 + 1/R 2 1/R tot = 1/2.0 + 1/4.0 =.75 R tot = 1.33Ω V= IR tot

19. Example A 9.0V battery is connected to two resistors of 2.0Ω and 4.0Ω in parallel. Find the equivalent resistance for the circuit and the total current in the circuit. 1/R tot = 1/R 1 + 1/R 2 1/R tot = 1/2.0 + 1/4.0 =.75 R tot = 1.33Ω V= IR tot 9.0 = I (1.33Ω) I = 6.92A

20. Practice Pg 655- Practice B #3