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Geometric Distribution

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Presentation on theme: "Geometric Distribution"— Presentation transcript:

1 Geometric Distribution
A probability distribution to determine the probability that success will occur on the nth trial of a binomial experiement

2 Geometric Distribution
Repeated binomial trials Continue until first success Find probability that first success comes on nth trial Probability of success on each trial = p

3 Geometric Probability

4 A sharpshooter normally hits the target 70% of the time.
Find the probability that her first hit is on the second shot. Find the mean and the standard deviation of this geometric distribution.

5 A sharpshooter normally hits the target 70% of the time.
Find the probability that her first hit is on the second shot. P(2)=p(1-p) n-1 = .7(.3)2-1 = 0.21 Find the mean  = 1/p = 1/.7 1.43 Find the standard deviation

6 Poisson Distribution A probability distribution where the number of trials gets larger and larger while the probability of success gets smaller and smaller

7 Poisson Distribution Two outcomes : success and failure
Outcomes must be independent Compute probability of r occurrences in a given time, space, volume or other interval  (Greek letter lambda) represents mean number of successes over time, space, area

8 Poisson Distribution

9 The mean number of people arriving per hour at a shopping center is 18.
Find the probability that the number of customers arriving in an hour is 20. r = 20  = 18 Find P(20) e =

10 The mean number of people arriving per hour at a shopping center is 18.

11 Poisson Probability Distribution Table
Table 4 in Appendix II provides the probability of a specified value of r for selected values of .

12 Using the Poisson Table
 = 18, find P(20):

13 Poisson Approximation to the Binomial Distribution
The Poisson distribution can be used as a probability distribution for “rare” events.

14 “Rare” Event The number of trials (n) is large and the probability of success (p) is small.

15 If n  100 and np < 10, then The distribution of r (the number of successes) has a binomial distribution which is approximated by a Poisson distribution . The mean  = np.

16 Use the Poisson distribution to approximate the binomial distribution:
Find the probability of at most 3 successes.

17 Using the Poisson to approximate the binomial distribution for n = 240 and p = 0.02
Note that n  100 and np = 4.8 < 10, so the Poisson distribution can be used to approximate the binomial distribution. Find the probability of at most 3 successes: Since  = np = 4.8, we use Table 4 to find P( r  3) = = .2942


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