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Chemical Equations › Balancing, Types of Equations Compound Composition › Atom mass; Atomic and formula weight › % Composition › Empirical Formulas › Mole Amounts; Molar Mass › Mole Calculations Amounts in chemical reactions
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Chemical equations help us to describe chemical reactions. BEFOREAFTER
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Combustion (of a hydrocarbon with O 2 ) Combination Reactions Decomposition Reactions Single Displacement Reactions (Ch.4) Double Displacement Reactions (Ch.4)
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Hydrocarbons react with oxygen to give carbon dioxide and water: CH 3 CH 2 CH 3 (g) + O 2 (g) CO 2 (g) + H 2 O(g) Balance it!
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Hydrocarbons react with oxygen to give carbon dioxide and water: C 3 H 8 (g) + 5O 2 (g) 3CO 2 (g) + 4H 2 O(g) Balance it!
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Combination Reactions: A + B C Mg(s) + O 2 (g) ?
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Combination Reactions: A + B C Mg(s) + O 2 (g) MgO(s)
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Combination Reactions: A + B C 2Mg(s) + O 2 (g) 2MgO(s) Fig 3.5
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Decomposition Reactions: C A + B Sodium azide decomposes to its elements: NaN 3 (s) ? (N 3 - is a polyatomic ion)
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Decomposition Reactions: C A + B Sodium azide decomposes to its elements: NaN 3 (s) Na(s) + N 2 (g) (N 3 - is a polyatomic ion) Balance it!
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Decomposition Reactions: C A + B Sodium azide decomposes to its elements: 2NaN 3 (s) 2Na(s) + 3N 2 (g) (N 3 - is a polyatomic ion)
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Another example: 2HgO(s) 2Hg(l) + O 2 (g) Rxn
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Some compounds decompose to more stable compounds: 2H 2 O 2 (l) 2H 2 O(l) + O 2 (g) CaCO 3 (s) CaO(s) + CO 2 (g)
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Atomic Weight Molecular Weight / Formula Weight Percent Composition Empirical Formulas
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When we describe the mass of atoms of an element, we must consider all of the naturally occurring isotopes. Carbon is composed of › 98.8925 % C-12 (12.00000 amu) › 1.1080 % C-13 (13.00335 amu) Its weighted average is 12.011 amu. Its atomic weight is 12.011 amu.
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Atomic weight is different than mass number.
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(62.94 amu)(0.6917) = 43.5356 (64.93 amu)(0.3083) = 20.0179 63.55 amu ( 4 sig figs )
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The formula weight of a substance is the sum of the atomic weights of the atoms that make up the formula. Mg(OH) 2 2(16.00) amu 2(1.008) amu + 24.31 amu 58.33 amu = formula wt. Mg(OH) 2
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The formula weight of a molecular compound is also called its molecular weight. H 2 O 1.008 amu 1.008 amu + 16.00 amu 18.02 amu = molecular wt. of H 2 O
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Mass Percent Composition = (#Atoms of Element)(Atomic Weight) x100 Formula Weight of Compound
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l What is the mass %Cl in MgCl 2 ? l Formula weight = (2 x 35.45amu) + 24.31 amu l 95.21 amu l Mass of Cl: 2 x 35.45amu = 70.90amu l Mass %Cl =
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What is the mass %Mg in MgCl 2 ? 74.47% Cl 25.53% Mg
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How would you go about determining the mass of carbon in 5.0 g CCl 4 ?
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%C = (12.011amu/153.811 amu)x100 = 7.8089% C g Carbon = (0.078089)(5.0g) = 0.39 g
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Which of the following has the greatest %O? Explain. MgO CaO Na 2 O K 2 O
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What is the percent carbon in C 2 H 4 ? What is the percent carbon in C 3 H 6 ?
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What is the percent carbon in C 2 H 4 ? % C = 85.63% What is the percent carbon in C 3 H 6 ? % C = 85.63%
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Different compounds with the same percent composition have the same empirical formula. The empirical formula shows the ratio of atoms of each element as the smallest whole-number ratio.
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Which of the following are empirical formulas? CH 4 C 2 H 2 N 2 O 5 C 2 H 6 Al 2 O 3
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Which of the following are empirical formulas? CH 4 C 2 H 2 N 2 O 5 C 2 H 6 Al 2 O 3
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