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7-2 Graphing Exponential Functions

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Presentation on theme: "7-2 Graphing Exponential Functions"β€” Presentation transcript:

1 7-2 Graphing Exponential Functions
Today’s Objective: I can graph any exponential function.

2 f and g are exponential functions with the same base.
The graph of g is a ______ of the graph of f . compression reflection translation none of the above Justify your reasoning g f

3 Parent Function: 𝑦= 𝑏 π‘₯ 𝑦=π‘Žβ‹… 𝑏 π‘₯ 𝑦=π‘Žβ‹… 𝑏 π‘₯βˆ’β„Ž +π‘˜ Stretch or compress
Right/Left (h) Up/Down (k) (1+h, ab+k) (1, ) ab (h, a+k) (0, ) a (1, ) (0, ) 1 b 𝑦=π‘˜ To Graph: Plot: y-intercept: (0, a) Plot: 2nd Point: (1, ab) Translate points and asymptote Asymptote y = k

4 𝑦= 2 π‘₯ 𝑦= 3β‹…2 π‘₯ y-intercept: 2nd Point: Translate: Asymptote: (0, 1)
𝑦=π‘Ž ⋅𝑏 π‘₯βˆ’β„Ž +π‘˜ To Graph: Plot: y-intercept: (0, a) Plot: 2nd Point: (1, ab) Translate points and asymptote Asymptote y = k 𝑦= β‹…2 π‘₯ y-intercept: 2nd Point: Translate: Asymptote: (0, 1) y-intercept: 2nd Point: Translate: Asymptote: (0, 3) (1, 2) (1, 6) none none 𝑦=0 𝑦=0 Domain: Range: All Real #s 𝑦>0 Domain: Range: All Real #s 𝑦>0

5 𝑦= βˆ’2(4) π‘₯ 𝑦= 1 2 β‹…4 π‘₯ y-intercept: 2nd Point: Translate: Asymptote:
𝑦= β‹…4 π‘₯ 𝑦= βˆ’2(4) π‘₯ 𝑦=π‘Ž ⋅𝑏 π‘₯βˆ’β„Ž +π‘˜ To Graph: Plot: y-intercept: (0, a) Plot: 2nd Point: (1, ab) Translate points and asymptote Asymptote y = k y-intercept: 2nd Point: Translate: Asymptote: (0, βˆ’2) (0, 1 2 ) y-intercept: 2nd Point: Translate: Asymptote: (1, βˆ’8) (1, 2) none none 𝑦=0 𝑦=0 Domain: Range: All Real #s 𝑦<0 Domain: Range: All Real #s 𝑦>0

6 𝑦= 2 π‘₯βˆ’3 𝑦= 2 π‘₯ +2 y-intercept: 2nd Point: Translate: Asymptote:
𝑦=π‘Ž ⋅𝑏 π‘₯βˆ’β„Ž +π‘˜ To Graph: Plot: y-intercept: (0, a) Plot: 2nd Point: (1, ab) Translate points and asymptote Asymptote y = k 𝑦= 2 π‘₯ +2 y-intercept: 2nd Point: Translate: Asymptote: (0, 1) (0,1) y-intercept: 2nd Point: Translate: Asymptote: (1, 2) (1, 2) β†’ 3 ↑ 2 𝑦=0 𝑦=2 p.447: 7, 8, 11, 15, 16, 18, 20,21,38,39 Domain: Range: All Real #s Domain: Range: All Real #s 𝑦>0 𝑦>2

7 7-2 Graphing Exponential Functions Day 2
Today’s Objective: I can graph any exponential function.

8 πΆπ‘’π‘Ÿπ‘Ÿπ‘’π‘›π‘‘ π‘‡π‘’π‘šπ‘ π‘ƒπ‘Ÿπ‘’π‘£π‘–π‘œπ‘’π‘  π‘‡π‘’π‘šπ‘
The best temperature to brew coffee is between 195Β°F and 205Β°F. Coffee is cool enough to drink at 185Β°F. The table shows temperature readings from a sample cup of coffee. Model this relationship. Temp change per minute 4.2% Time (min) Temp (Β°F) 203 5 177 10 153 15 137 20 121 Temp less room temp (70Β°) πΆπ‘’π‘Ÿπ‘Ÿπ‘’π‘›π‘‘ π‘‡π‘’π‘šπ‘ π‘ƒπ‘Ÿπ‘’π‘£π‘–π‘œπ‘’π‘  π‘‡π‘’π‘šπ‘ 133 107 83 67 51 0.80 𝑦=π‘Žβ‹… 𝑏 π‘₯βˆ’β„Ž +π‘˜ 0.78 𝑦= 133β‹… (0.96) π‘₯ +70 0.81 0.76 Average Temp change per 5 min. = 21% decrease

9 The best temperature to brew coffee is between 195Β°F and 205Β°F
The best temperature to brew coffee is between 195Β°F and 205Β°F. Coffee is cool enough to drink at 185Β°F. The table shows temperature readings from a sample cup of coffee. Model this relationship. Graph on calculator: enter data: [STAT] Set window STAT PLOT: [2nd], [y =] [GRAPH] L1 Time (min) Temp (Β°F) 203 5 177 10 153 15 137 20 121 L2 π‘Œ 1 =133 (0.96) π‘₯ +70

10 Continuous growth or decay
You have $3000 to invest for 10 years at 5% annual rate with your choice of compounding. (yearly, quarterly, continuously) Yearly: 𝐴 𝑑 =π‘Ž 1+π‘Ÿ 𝑑 𝐴 10 = 𝐴 10 =4,886.68 Continuously: 𝑦=𝑒 𝑦= π‘₯ π‘₯ Quarterly: 𝐴 𝑑 =π‘Ž 1+ π‘Ÿ 𝑛 𝑛𝑑 𝐴 10 = (10) 𝐴 10 =4,930.86 𝑒= 𝐴 𝑑 =𝑃 𝑒 π‘Ÿπ‘‘ 𝐴 10 =3000 𝑒 0.05βˆ™10 𝐴 10 =4,946.16


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