2 Equations of lines to Remember Gradient-Intercept FormUseful for graphing since m is the gradient and b is the y-interceptPoint-Gradient FormUse this form when you know a point on the line and the gradientAlso can use this version if you have two points on the line because you can first find the gradient using the gradient formula and then use one of the points and the gradient in this equation.General FormCommonly used to write linear equation problems or express answers
3 Parallel and Perpendicular The gradient is a number that tells "how steep" the line is and in which direction. So as you can see, parallel lines have the same gradients so if you need the gradient of a line parallel to a given line, simply find the gradient of the given line and the gradient you want for a parallel line will be the same.Perpendicular lines have negative reciprocal gradients so if you need the gradient of a line perpendicular to a given line, simply find the gradient of the given line, take its reciprocal (flip it over) and make it negative.
4 4 -1 2 y = - x 1 Let's look at a line and a point not on the line Let's find the equation of a line parallel to y = - x that passes through the point (2, 4)y = - xWhat is the gradient of the first line, y = - x ?(2, 4)1This is in gradient intercept form so y = mx + b which means the gradient is –1.So we know the gradient is –1 and it passes through (2, 4). Having the point and the gradient, we can use the point-gradient formula to find the equation of the line4-12Distribute and then solve for y to leave in gradient-intercept form.
5 4 1 2 y = - x What if we wanted perpendicular instead of parallel? Let's find the equation of a line perpendicular to y = - x that passes through the point (2, 4)y = - x(2, 4)The gradient of the first line is still –1.The gradient of a line perpendicular is the negative reciprocal so take –1 and "flip" it over and make it negative.412Distribute and then solve for y to leave in gradient-intercept form.So the gradient of a perpendicular line is 1 and it passes through (2, 4).
6 .Stephen CorcoranHead of MathematicsSt Stephen’s School – Carramar