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EASTERN MEDITERRANEAN UNIVERSITY EE 529 Circuit and Systems Analysis Lecture 4.

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Presentation on theme: "EASTERN MEDITERRANEAN UNIVERSITY EE 529 Circuit and Systems Analysis Lecture 4."— Presentation transcript:

1 EASTERN MEDITERRANEAN UNIVERSITY EE 529 Circuit and Systems Analysis Lecture 4

2 Matrices of Oriented Graphs THEOREM: In a graph G let the fundamental circuit and cut-set matrices with respect to a tree to be written as

3 Matrices of Oriented Graphs Consider the following graph e3e3 v1v1 v2v2 v3v3 v0v0 e1e1 e2e2 e4e4 e5e5 e3e3 v1v1 v2v2 v3v3 v0v0 e1e1 e2e2 e4e4 e5e5 e6e6

4 FUNDAMENTAL POSTULATES Now, Let G be a connected graph having e edges and let be two vectors where x i and y i, i=1,...,e, correspond to the across and through variables associated with the edge i respectively.

5 FUNDAMENTAL POSTULATES 2. POSTULATE Let B be the circuit matrix of the graph G having e edges then we can write the following algebraic equation for the across variables of G 3. POSTULATE Let A be the cut-set matrix of the graph G having e edges then we can write the following algebraic equation for the through variables of G

6 FUNDAMENTAL POSTULATES 2. POSTULATE is called the circuit equations of electrical system. (is also referred to as Kirchoff’s Voltage Law) 3. POSTULATE is called the cut-set equations of electrical system. (is also referred to as Kirchoff’s Current Law)

7 Fundamental Circuit & Cut-set Equations Consider a graph G and a tree T in G. Let the vectors x and y partitioned as where x b (y b ) and x c (y c ) correspond to the across (through) variables associated with the branches and chords of the tree T, respectively. Then and fundamental circuit equation fundamental cut-set equation

8 Series & Parallel Edges Definition: Two edges e i and e k are said to be connected in series if they have exactly one common vertex of degree two. eiei ekek v0v0

9 Series & Parallel Edges Definition: Two edges e i and e k are said to be connected in parallel if they are incident at the same pair of vertices v i and v k. eiei ekek vivi vkvk

10 (n+1) edges connected in series (x 1,y 1 ) (x 2,y 2 ) (x n,y n ) (x 0,y 0 )

11 (n+1) edges connected in parallel (x 0,y 0 ) (x 1,y 1 ) (x 2,y 2 ) (x n,y n )

12 Mathematical Model of a Resistor A B a b v(t) i(t)

13 Mathematical Model of an Independent Voltage Source a b v(t) i(t) v(t) i(t) VsVs

14 Mathematical Model of an Independent Voltage Source a b v(t) i(t) v(t) i(t) IsIs

15 Circuit Analysis A-Branch Voltages Method: Consider the following circuit.

16 Circuit Analysis A-Branch Voltages Method: 1. Draw the circuit graph 1 2 3 4 5 6 7 8 a b c d e There are: 5 nodes (n) 8 edges (e) 3 voltage sources (n v ) 1 current source (n i )

17 Circuit Analysis A-Branch Voltages Method: 1.Select a proper tree: (n-1=4 branches)  Place voltage sources in tree  Place current sources in co-tree  Complete the tree from the resistors 1 2 3 4 5 6 7 8 a b c d e

18 Circuit Analysis A-Branch Voltages Method: 2. Write the fundamental cut-set equations for the tree branches which do not correspond to voltage sources. 1 2 3 4 5 6 7 8 a b c d e

19 Circuit Analysis A-Branch Voltages Method: 2. Write the currents in terms of voltages using terminal equations. 1 2 3 4 5 6 7 8 a b c d e

20 Circuit Analysis A-Branch Voltages Method: 2. Substitute the currents into fundamental cut-set equation. 1 2 3 4 5 6 7 8 a b c d e 3. v 3, v 5, and v 6 must be expressed in terms of branch voltages using fundamental circuit equations.

21 Circuit Analysis A-Branch Voltages Method: 1 2 3 4 5 6 7 8 a b c d e Find how much power the 10 mA current source delivers to the circuit

22 Circuit Analysis A-Branch Voltages Method: 1 2 3 4 5 6 7 8 a b c d e Find how much power the 10 mA current source delivers to the circuit

23 Circuit Analysis Example: Consider the following circuit. Find ix in the circuit.

24 Circuit Analysis Circuit graph and a proper tree 1 2 3 4 5 6 78

25 Circuit Analysis Fundamental cut-set equations 1 2 3 4 5 6 78

26 Circuit Analysis Fundamental cut-set equations 1 2 3 4 5 6 78

27 Circuit Analysis Fundamental circuit equations 1 2 3 4 5 6 78

28 Circuit Analysis v 3 = 9.5639V v 2 = -8.1203 V

29 Circuit Analysis


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