1. SA & Volume Applications 1.How many feet of form board are needed to enclose a 4 by 6 foot concrete pad? 6 ft 4 ft perimeter = 20 ft

2. SA & Volume Applications 2.The bore of a cylinder is its diameter, the stroke is its height, and the displacement is its volume. What is the displacement of a cylinder with a bore of 56.5 mm and a stroke of 48.5 mm? Give the answer in cubic centimeters. volume = Bh V = (base area) (dist b/w bases) V = (  r 2 )(h) V = (3.14)(2.825)(2.825)(4.85) V = 121.5cm 3 48.5 mm 4.85 cm 56.5 mm 5.65 cm

3. SA & Volume Applications 3.If asphalt pavement costs $0.78 per square foot, determine the cost of the circular road in the figure. A outer circle =  r 2 = 3.14(50)(50) = 7850 ft 2 36’ 50’ A inner circle =  r 2 = 3.14(36)(36) = 4069 ft 2 A outer circle – A inner circle = 7850 – 4069 = 3780.56 ft 2 Cost = (3780.56)(0.78) = $2948.84

4. SA & Volume Applications 4.A 6 inch diameter pipe 50 feet high is filled to the top with water. What is the weight at its base? (Note that one cubic foot of water weighs 62.4 pounds.) Round to the nearest pound. 6” 50’ d = 0.5 ft volume = Bh V = (base area) (dist b/w bases) V = (  r 2 )(h) V = (3.14)(0.25)(0.25)(50) = (0.196)(50) = 9.81 ft 3 Weight = (9.81)(62.4) = 612 lbs

5. SA & Volume Applications 3.A customer wants to surround a two-wall shower with synthetic marble to a height of 72”. If the two walls measure 36” and 78” and marble costs $35 per square foot, what is the total cost of the marble? 50’ A back = lw = (6)(6.5) = 39 ft 2 72” 78” 36” 6 ft 6.5 ft 3 ft A side = lw = (6)(3) = 18 ft 2 A total = 39 + 18 = 57 ft 2 cost = (57)(35) = $1995