2. If sugar reacts with potassium chlorate how would you mix them? Suppose we mix them in equal masses? 11g sugar and 11g potassium chlorate? Is this the RIGHT proportion? If it is then both reactants will be gone at the end of the reaction and only products will remain. Since sugar has many carbon atoms if carbon is left over at the end then there was not enough potassium chlorate to consume all the sugar. What color is carbon?

4. Click on slide to start; click on border to stop

5. How can we mix these two and not have anything left over?

6. lst: Write out a balanced chemical equation: 1C 12 H 22 O 11 + 8KClO 3 == 12CO 2 + 8KCl +11H 2 O 1(342 g) + 8 (122.5) === 12(44g) + 8(74.5g) + 11(18g) 342 g to 980 g or 980/342 or 2.9/1 11 g to 31.5 g For 11 g of sugar it will take 2.9 x 11 g of KClO 3 or 31.5 g Now there should be no messy carbon left behind….showing unused sugar.

8. Click on slide to start movie; on border to stop

10. What causes the small black spots to appear? Neither H 2 O or KCl or CO 2 is black.

11. Mixture of sugar and potassium chlorate This is a clue!

12. ..\Copy of Chemistry Minilab NaClO3 and C12H22O11 Name.doc