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Introduction to Patterson Function and its Applications

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1 Introduction to Patterson Function and its Applications
“Transmission Electron Microscopy and Diffractometry of Materials”, B. Fultz and J. Howe, Springer-Verlag Berlin Chapter 9) The Patterson function: explain diffraction phenomena involving displacement of atoms off periodic positions (due to temperature or atomic size)  diffuse scattering Phase factor: instead of Fourier transform prefactor ignored:

2 Supplement: Definitions in diffraction
Fourier transform and inverse Fourier transform System 1 System 4 System 2 System 5 System 3 System 6

3 Relationship among Fourier transform, reciprocal
lattice, and diffraction condition System 1 Reciprocal lattice Diffraction condition

4 System 2, 3 Reciprocal lattice Diffraction condition

5 Patterson function Atom centers at Points in Space:
Assuming: N scatterers (points), located at rj. The total diffracted waves is The discrete distribution of scatterers  f(r)

6 f(r): zero over most of the space, but at atom centers
such as , is a Dirac delta function times a constant Property of the Dirac delta function:

7 Definition of the Patterson function:
Slightly different from convolution called “autoconvolution” (the function is not inverted). Convolution: Autocorrelation:

8 Fourier transform of the Patterson function =
the diffracted intensity in kinematical theorem. Define  Inverse transform

9 The Fourier transform of the scattering factor
distribution, f(r)  (k) and i.e.

10 1D example of Patterson function

11 Properties of Patterson function comparing to f(r):
1. Broader Peaks 2. Same periodicity 3. higher symmetry

12 Case I: Perfect Crystals
much easier to handle f(r); the convolution of the atomic form factor of one atom with a sum of delta functions

13 Shape function RN(x): extended  to 

14 N = 9 shift 8a a triangle of twice the total width  -3a -a 2a 4a -4a
2a 4a -4a -2a a 3a shift 8a -3a -a 2a 4a -4a -2a a 3a a triangle of twice the total width -9a -7a -5a -3a -a 2a 4a 6a 8a -8a -6a -4a -2a a 3a 5a 7a 9a

15 F(P0(x))  I(k) Convolution theorem: a*b  F(a)F(b); ab  F(a)*F(b)

16 If ka  2, the sum will be zero. The sum will have a
nonzero value when ka = 2 and each term is 1. N: number of terms in the sum 1 D reciprocal lattice

17 F.T.

18 A familiar result in a new form.
  -function  center of Bragg peaks  Peaks broadened by convolution with the shape factor intensity  Bragg peak of Large k are attenuated by the atomic form factor intensity

19 Patterson Functions for homogeneous disorder
and atomic displacement diffuse scattering Deviation from periodicity: Deviation function Perfect periodic function: provide sharp Bragg peaks Look at the second term Mean value for deviation is zero

20 The same argument for the third term  0
1st term: Patterson function from the average crystal, 2nd term: Patterson function from the deviation crystal. Sharp diffraction peaks from the average crystal often a broad diffuse intensity

21  Uncorrelated Displacements:
Types of displacement: (1) atomic size differences in an alloy  static displacement, (2) thermal vibrations  dynamic displacement Consider a simple type of displacement disorder: each atom has a small, random shift, , off its site of a periodic lattice Consider the overlap of the atom center distribution with itself after a shift of

22 12

23 No correlation in   probability of overlap of two atom
centers is the same for all shift except n = 0 When n = 0, perfect overlap at  = 0, at   0: no overlap + = = + The same number of atom- atom overlap

24 The diffuse scattering increases with k !
constant deviation F[Pdevs1(x)] increasingly dominates over F[Pdevs2(x)] at larger k. The diffuse scattering increases with k !

25 Correlated Displacements: Atomic size effects
a big atoms locate Overall effect: causes an asymmetry in the shape of the Bragg peaks.

26 Diffuse Scattering from chemical disorder:
Concentration of A-atoms: cA; Concentration of B-atoms: cB. Assume cA > cB  When the product is summed over x. # positive > # negative H positive < H ones negative Pdevs(x  0) = 0; Pdevs(0)  0

27 Let’s calculate Pdevs(0): cAN peaks of cBN peaks of

28 Total diffracted intensity
Just like the case of perfect crystal Total diffracted intensity

29 The diffuse scattering part is: the difference
between the total intensity from all atoms and the intensity in the Bragg peaks


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