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ECCS5209 Project Planning & Control Faculty of Applied Engineering and Urban Planning Civil Engineering Department Example 2 nd Semester 2010/2011 Eng:

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Presentation on theme: "ECCS5209 Project Planning & Control Faculty of Applied Engineering and Urban Planning Civil Engineering Department Example 2 nd Semester 2010/2011 Eng:"— Presentation transcript:

1 ECCS5209 Project Planning & Control Faculty of Applied Engineering and Urban Planning Civil Engineering Department Example 2 nd Semester 2010/2011 Eng: Ismail Zakaria Al Daoor 1

2 2 Project Crashing

3 3 Example The durations and direct costs for each activity in the network of a small construction contract under both normal and crash conditions are given in the following table. Establish the least cost for expediting the contract. Determine the optimum duration of the contract assuming the indirect cost is LE 125/day. Time-Cost Trade-Off ( Project Crashing )

4 4 012 0 A(0) 2@100 1220 1422 B(8) 2@150 2025 2227 E(5) 1@50 27 47 2747 G(20) 5@60 4759 4759 I(12) 2@75 1227 1227 C(15) 3@200 2732 2934 F(5) 1@300 3245 3447 H(13) 2@40 2012 2412 D(23) Act.N.DC.D∆.DC.C.N.C∆.CSlop A1210272007000200100 B86253005000300150 C1512346004000600200 D23 05000 00 E5411050100050 F54133003000300 G201556300600030060 H1311228502500350175 I121023150300015075 CPM = A-C-G-I

5 5 1. The activity on the critical path with the lowest cost slope is G, this activity can be crashed by 5 days, but if it is crashed by more than 2 days another critical path will be generated. Therefore, activity G will be crashed by 2 days only. Then adjust timing of the activities. A new critical path will be formed, A-C-F-H-I. New contract duration is 57 days. The cost increase is 2 x 60 = LE 120. Time-Cost Trade-Off ( Project Crashing )

6 6 2. At this step the activities that can be crashed are listed below: Either A at cost LE 100/day Or C at cost LE 200/day Or I at cost LE 75/day Or F & G at cost LE 360/day Or H & G at cost LE 100/ day Activity I is chosen because it has the least cost slope, and it can be crashed by 2 days. Because this is last activity in the network, it has no effect on other activities. New contract duration is 55 days. The cost increase is 2 x 75 = LE 150. Cumulative cost increase = 120 + 150 = LE 270 Time-Cost Trade-Off ( Project Crashing )

7 7 3. Now, we could select A or both H & G, because they have the same cost slope. Activity A is chosen to be crashed. This will change the timings for all activities, but no new critical path will be formed. New contract duration is 53 days. The cost increase is 2 x 100 = LE 200. Cumulative cost increase = 270 + 200 = LE 470 Time-Cost Trade-Off ( Project Crashing )

8 8 4. Now, activities H & G can be crashed by 2 days each. A new critical path A-B-D-I will be formed. New contract duration is 51 days. The cost increase is 2 x 100 = LE 200. Cumulative cost increase = 470 + 200 = LE 670 Time-Cost Trade-Off ( Project Crashing )

9 9 5. At this stage, the network have three critical paths. The activities that can be crashed are listed below: Either C & B at cost LE 350/day Or F, G & B at cost LE 510/day Activities C & B are chosen because they have the least cost slope. New contract duration is 49 days. The cost increase is 2 x 350 = LE 700. Cumulative cost increase = 670 + 700 = LE 1370 Now, there is no further shortening is possible. Time-Cost Trade-Off ( Project Crashing )

10 10 The contract duration and the corresponding cost are given in the table below. Time-Cost Trade-Off ( Project Crashing )

11

12 Question 12


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