1. Exam Review Nick Marshall & Andy Garcia-Civita

2. Order of Operations Does anybody in the audience know what order of operations is? How do you know the order to do the problem?

3. PEMDAS PEMDAS= 1) Parentheses 2) Exponents 3) Multiplication 4) Division 5) Addition 6)Subtraction

4. PEDMSA PEDMSA= 1) Parentheses 2) Exponents 3) Division 4) Multiplication 5) Subtraction 6) Addition PEDMSA also works because it is whatever comes first in the problem. Division could come before multiplication and subtraction could come before addition. It just depends on how the problem is written.

5. We'll Walk You Through This One! (8x3)-(6+6)x4+20 You solve the parentheses first. (24-12)x4+20 You solve the parentheses first again. 12x4+20 Then you do multiplication. 48+20= Finally you do addition to get the answer! 68

6. Now You Are On Your Own. Solve This. 152÷(1+5)13-17

7. Answer 48

8. Exponents Now we will switch to exponents. Exponents are little numbers that go on the top of the number. There is a base, and that is the big number. Then there is the exponent and that is the little number that goes on the top.

9. What They Mean Ex. 2 4 The base is the 2 and the exponent is 4. It means two to the fourth power. You do 2x2x2x2. You get 16. In other words, you multiply the base however many times the exponent says.

10. It's time for you to solve it! Solve: 1) 4 3 2) 5 4

11. The Answers 1. 2. 64 625

12. Algebraic Expressions Expressions contain numbers, variables and at least one operation. This problem is pretty self-explanatory. You just change the letters to the numbers that we give you, and then you are ready to solve the problem.

13. Example X = 4, Y = 3, Z = 4.8 XY+Z Just change those letters to the right numbers: 43+4.8 Now you can get the answer.

14. Solve Solve this problem if a=2.6, b=6, and c=3.4. a+b-c=?

15. Answer 5.2

16. Variables A variable is a letter that takes a place of a number. Variables could make the problem harder because you don't know one number. It is very important that you know variables. For example, in an algebraic expression you have to know what the letters stand for, or else you can't do the problem.

17. Example R = 56, O = 75, P = 22 R+P÷O What would the problem look like? 56+22÷75

18. Solve J = 745, E = 32, Q = 56.3 QJ÷E What will the problem look like?

19. Answer 56.3745÷32

20. Thank You! Thank you for doing our review with us and good luck to you all on the exams!