1. Electrochemistry : Oxidation and Reduction Electrochemical Reaction - Chemical reaction that involves the flow of electrons. Redox Reaction (oxidation-reduction reaction) - A reaction in which at least one atom changes in oxidation state. Don't confuse this with the following definitions: Oxidizing Agent - Causes oxidation; undergoes reduction (gains electrons). Reducing Agent - Causes reduction; undergoes oxidation (loses electrons). **In spontaneous redox reactions, stronger oxidizing and reducing agents are converted into weaker oxidizing and reducing agents. Good Oxidizing Agents Atoms, ions, and molecules with large electron affinities. e.g. F 2, Cl 2 Compounds with large oxidation states. WHY? - The electronegativity increases as oxidation state increases Electronegativity - The tendency of an atom to draw electrons toward itself. e.g. MnO 4 -, CrO 4 2- Good Reducing Agents Active metals e.g. Na, Mg, Al, Zn Metal hydrides e.g. NaH, CaH 2 H 2 can act as either: Oxidizing agent when it combines with metals. Reducing agent when it combines with nonmetals. Reduction - Any process in which the oxidation number of an atom decreases (becomes more negative). Oxidation - Any process in which the oxidation number of an atom increases (becomes more positive). Oxidation Number - The charge that an atom would have if the compound in which it were found were ionic. (Next page is a refresher on “How to”.) To help remember oxidation and reduction, remember the following: OILRIG: Oxidation Is Loss Reduction Is Gain Types of Redox Reactions Corrosion - A type of redox reaction in which a metal is destroyed. 4 Fe (s) + 3 O 2(g) 2 Fe 2 O 3 3 H 2 O Metathesis Reaction - A reaction in which atoms are interchanged and there is no change in oxidation number. Disproportionation Reaction - A reaction in which a single reactant undergoes both oxidation and reduction. Disproportionation

2. Before we balance a Redox equation lets first refresh our memory on how to calculate oxidation numbers. Assigning Oxidation Numbers Category Oxidation # Example 1) Neutral substances containing only a single element 0 N 2, He 2) Monatomic ions same as the charge Na + = +1 3) Hydrogen combined with a nonmetal +1 HBr, CH 4, OH - 4) Hydrogen combined with a metal -1NaH, CaH 2 5) Metals in Group IA+1Li 3 N, Na 2 S 6) Metals in Group IIA +2Mg 3 N 2 7) Oxygen -2H 2 O, NO (Exceptions: H 2 O 2, O 2 2- ) -1 8) Halogens -1AlF 3, HCl Oxidation Number - The charge that an atom would have if the compound in which it were found were ionic. The rules: 1) The sum of the oxidation numbers of the atoms in a molecule must be equal to the overall charge on the molecule. 2) To assign a number to a transition metal ion (not listed in the table below) start with the overall charge, add the total number of negative charges for oxygen (if there were four as in the case of MnO4 - then you would add 8 for a total of +7 for Mn), continue until all other species listed in the table below are considered (subtract if it is a positive value.) The result is the oxidation number of the transition metal ion. 3)The most electronegative element will have a negative oxidation number.

3. 1. What are the reduction and oxidation pairs? 0 -3e - -3 Al (s) + OH - (aq) Al(OH) - 4(aq) + H2OH2O 2H 2 O + H 2(g) 2 x +1 2 x -1e - 2 x 0 3 2 Al (s) + OH - (aq) Al(OH) - 4(aq) + H 2(g) H2OH2O 62 H 2 O + Al (s) + OH - (aq) Al(OH) - 4(aq) + H 2(g) H2OH2O 2 3 a) Al (s) and Al(OH) - 4(aq) (oxidized) b) ? and H 2(g) (reduced) Hint: 1. The reaction is taking place in a basic, aqueous media. 2. Look for a reduction potential for H 2(g) in a table. 2. Calculate the Oxidation numbers 3. Mass Balance 4. Charge Balance Balancing Redox equations using the Oxidation number method (Basic solution is demonstrated) and transfer to the redox partner

4. Pb(OH) - 3(aq) + OCl - (aq) PbO 2(s) + Cl - (aq) OH - 1. What are the reduction and oxidation pairs? OCl - (aq) Cl - (aq) OH - Pb(OH) - 3(aq) PbO 2(s) OH - 2. Mass Balance both equations + H2O+ H2O OCl - (aq) OH - + H + + H 2 O 2 H + + 3. Charge balance both equations (add extra e - ) + 2e - 2e - + 4. Cancel any common terms. OH - + + OH - 6. Add the two half reactions and cancel any extra water. 5. Is the reaction taking place in a basic solution? H 2 O + 2e - + H 2 O +Pb(OH) - 3(aq) +PbO 2(s) + Cl - (aq) + 2H 2 O+ OH - Balancing Redox equations using the Half Reaction method (Basic solution is demonstrated) (add H 2 O to balance extra oxygens then add extra H + to balance extra hydrogens from the added H 2 O) Are there are any H + left? add OH - to both sides. H + and OH - will make H 2 O on one side.