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Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley Momentum Physics 102 Goderya Chapter(s): 6 Learning Outcomes: 1,2,10,11,12.

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Presentation on theme: "Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley Momentum Physics 102 Goderya Chapter(s): 6 Learning Outcomes: 1,2,10,11,12."— Presentation transcript:

1 Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley Momentum Physics 102 Goderya Chapter(s): 6 Learning Outcomes: 1,2,10,11,12

2 Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley This Chapter will help you understand: Momentum Impulse Impulse Changes Momentum Collisions Conservation of Momentum 2D collisions

3 Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley Momentum and Impulse

4 Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley Momentum and Impulse

5 Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley Injury in Car Collision Data: Survival data for head on collision: Force for bone fracture 90KN, Pressure 1.9x10 5 N/m 2 at 60 mi/h resulting in acceleration of 50g’s for 70 ms for an area of 0.7-0.9 m 2 Case Data M p = 75-kg, V i =60 mi/h (27m/s), t r =0.010 s, A chest+head =0.5 m 2 Find F, a, P

6 Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley Impulse Changes Momentum example: In a crash test, a car of mass 1500 kg collides with a wall and rebounds. The initial and final velocities are v i = -15.0 m/s and v f =2.60 m/s, respectively. If the collision lasts for 0.150 s, find the impulse delivered to the car due to collision and the size and direction of the average force exerted on the car. Ans. I= p f –p i = 2.64 x 10 4 kg.m/s Ans. F avg =Δp/Δt= +1.76 x 10 5 N

7 Air Bags and Seat Belts


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