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Multiplication Smorgasbord I am learning to solve multiplication problems using a variety of mental strategies. Work it out in your head At a smorgasbord there are lots of different foods to choose from. You now know a lot of different multiplication strategies. Now we are going to try and choose the best strategy for each question.

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All the containers below hold 29 counters. How many counters are there in total? 10 3 X 29 = ? Option 1: We could work out how many tens there are and how many ones there are then add that amount together. 3 X 20 = 603 X 9 = 2760 + 27 = 87 There are a number of different ways we could answer this problems. So 3 X 29 = 87

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All the containers below hold 16 counters. How many counters are there in total? 10 4 X 16 = ? Option 1: 10 I don’t know what 4 X 16 equals but I do know that 4 X 8 = 32. Since 8 is only half of 16 I must need to add that same amount again. 4 X 16 = (4 X 8 ) + (4 X 8) 4 X 16 = 32 + 32So 4 X 16 = 64

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All the containers below hold 16 counters. How many counters are there in total? 10 4 X 16 = ? Option 2: 10 I’m going to try doubling and halving. Now let’s try a different method. This will mean there will be twice as many groups (8) with half as many in each group (8) 4 X 16 = ? 8 X 8 = 64 X2 ÷2 So 4 X 16 = 64

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Choose the best method for working out the questions below and answer. 1) 4 X 25 = ? 2) 3 X 27 = ? 3) 6 X 39 = ? 4) 7 X 22 = ? 5) 4 X 24 = ? Need some more practise? Try Pg34 & 35 of Teacher Tools Multiplication and Division Book Numeracy resourcesNumeracy resources Click again when you have worked out all your answers. A strategy for answering each of these questions will be displayed. Please note that this is only one possible solution. Your answer however should be the same. 100, 2 X 50 = 100 81, 9 X 9 = 81 234, (6 X 40) – (6 X 1 ) = 234 154, (7 X 20) + (7 X 2) = 154 96, (4 X 12 = 48) double this amount.

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