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Targets Write an equation of a line given information about the graph. Solve problems by writing equations. Lesson 3-4: Equations of Lines TARGETS.

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Presentation on theme: "Targets Write an equation of a line given information about the graph. Solve problems by writing equations. Lesson 3-4: Equations of Lines TARGETS."— Presentation transcript:

1 Targets Write an equation of a line given information about the graph. Solve problems by writing equations. Lesson 3-4: Equations of Lines TARGETS

2 Concept Nonvertical Line Equations y = mx + b LESSON 3-3: Equations of Lines Slope-intercept form Point-slope form

3 Example 1 Slope and y-intercept Answer: Plot a point at the y-intercept, –3. Use the slope of 6 or to find another point 6 units up and 1 unit right of the y-intercept. Draw a line through these two points. LESSON 3-3: Equations of Lines EXAMPLE 1 Write an equation in slope-intercept form of the line with slope of 6 and y-intercept of –3. Then graph the line. y = mx + b Slope-intercept form y = 6x + (–3) m = 6, b = –3 y = 6x – 3 Simplify.

4 Example 2 Slope and a Point on the Line Answer: Graph the given point (–10, 8). Use the slope to find another point 3 units down and 5 units to the right. LESSON 3-3: Equations of Lines EXAMPLE 2 Write an equation in point-slope form of the line whose slope is that contains (–10, 8). Then graph the line. Point-slope form

5 Example 3 Two Points A. Write an equation in slope-intercept form for a line containing (4, 9) and (–2, 0). Step 1 First find the slope of the line. Slope formula LESSON 3-3: Equations of Lines EXAMPLE 3 Step 2 Now use the point-slope form and either point to write an equation. Point-slope form Using (4, 9): Answer:

6 Example 3 Two Points B. Write an equation in slope-intercept form for a line containing (–3, –7) and (–1, 3). Step 1 First find the slope of the line. Slope formula LESSON 3-3: Equations of Lines EXAMPLE 3 Step 2 Now use the point-slope form and either point to write an equation. Point-slope form Using (4, 9): Answer:

7 Example 4 Horizontal Line Write an equation of the line through (5, –2) and (0, –2) in slope-intercept form. Slope formula This is a horizontal line. Step 1 LESSON 3-3: Equations of Lines EXAMPLE 4 Step 2 Answer:

8 Concept LESSON 3-3: Equations of Lines Horizontal & Vertical Line Equations

9 Example 5 Write Parallel or Perpendicular Equations of Lines y =mx + bSlope-Intercept form 0 =–5(2) + bm = 5, (x, y) = (2, 0) 0 =–10 + bSimplify. 10 =bAdd 10 to each side. Answer: So, the equation is y = 5x + 10. LESSON 3-3: Equations of Lines EXAMPLE 5

10 Example 6 Write Linear Equations RENTAL COSTS An apartment complex charges $525 per month plus a $750 annual maintenance fee. A. Write an equation to represent the total first year’s cost A for r months of rent. For each month of rent, the cost increases by $525. So the rate of change, or slope, is 525. The y-intercept is located where 0 months are rented, or $750. A= mr + bSlope-intercept form A= 525r + 750m = 525, b = 750 Answer: The total annual cost can be represented by the equation A = 525r + 750. LESSON 3-3: Equations of Lines EXAMPLE 6

11 Example 6 Write Linear Equations RENTAL COSTS An apartment complex charges $525 per month plus a $750 annual maintenance fee. Evaluate each equation for r = 12. First complex:Second complex: A= 525r + 750A= 600r + 200 = 525(12) + 750r = 12= 600(12) + 200 = 7050Simplify.= 7400 B. Compare this rental cost to a complex which charges a $200 annual maintenance fee but $600 per month for rent. If a person expects to stay in an apartment for one year, which complex offers the better rate? LESSON 3-3: Equations of Lines EXAMPLE 6

12 Example 6 Write Linear Equations Answer: The first complex offers the better rate: one year costs $7050 instead of $7400. LESSON 3-3: Equations of Lines


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